Problem 27
Question
In Problems 23-36, name the curve with the given polar equation. If it is a conic, give its eccentricity. Sketch the graph. \(r=4 \sin \theta\)
Step-by-Step Solution
Verified Answer
The curve is a circle with radius 2 centered above the origin; its eccentricity is 0.
1Step 1: Identify the type of curve
The given polar equation is of the form \( r = a \, \sin \theta \). These equations represent conic sections. Specifically, equations of this form describe a circle when \( a \) equals any constant.
2Step 2: Determine the parameters
In the given equation \( r = 4 \sin \theta \), we can see that \( a = 4 \). This means we have a circle. This circle is centered at the pole (origin) since it is a type of rose curve when the value of \( n = 1 \), which is not explicitly used here.
3Step 3: Confirm eccentricity
For the polar equation \( r = a \sin \theta \), eccentricity \( e \) is used to determine the type of conic. Since this equation represents a circle, the eccentricity is \( e = 0 \).
4Step 4: Sketch the graph
To sketch the graph of \( r = 4 \sin \theta \), you start by noting that the maximum value of \( r \) occurs when \( \sin \theta = 1 \), which gives \( r = 4 \). As \( \theta \) changes from 0 to \( \pi \), the value of \( \sin \theta \) increases from 0 to 1 and then back to 0, so the circle is above the polar axis (the horizontal axis) with a radius of 2 centered above the pole.
Key Concepts
Conic SectionsEccentricityGraph Sketching
Conic Sections
Conic sections are curves obtained by intersecting a plane with a double-napped cone. These intersections can result in different types of curves, namely:
- Circles
- Ellipses
- Parabolas
- Hyperbolas
Eccentricity
Eccentricity is a crucial concept in understanding conic sections as it defines the shape of the conic. It is represented by \( e \), and different values of eccentricity correspond to different conics:
- \( e = 0 \): Circle
- \( 0 < e < 1 \): Ellipse
- \( e = 1 \): Parabola
- \( e > 1 \): Hyperbola
Graph Sketching
Sketching graphs of polar equations involves plotting points based on the polar coordinate's angle \( \theta \) and radius \( r \). For the equation \( r = 4 \sin \theta \), this process is both interesting and intuitive. Here's how we can break it down:
- When \( \theta = 0 \), \( \sin \theta = 0 \), so \( r = 0 \). The point starts at the pole.
- At \( \theta = \frac{\pi}{2} \), \( \sin \theta = 1 \), giving the maximum radius of 4.
- As \( \theta \) increases from 0 to \( \pi \), \( r \) grows to 4 and falls back to 0.
Other exercises in this chapter
Problem 26
In Problems \(1-32\), sketch the graph of the given polar equation and verify its symmetry (see Examples 1-3). \(r=3 \sin 5 \theta\) (five-leaved rose)
View solution Problem 26
Find the equations of the tangent and the normal lines to the given parabola at the given point. Sketch the parabola, the tangent line, and the normal line. $$y
View solution Problem 27
In Problems \(21-30\), find \(d y / d x\) and \(d^{2} y / d x^{2}\) without eliminating the parameter. $$ x=3 \tan t-1, y=5 \sec t+2 ; t \neq \frac{(2 n+1) \pi}
View solution Problem 27
Sketch the graph of the given equation. $$ 4 x^{2}+16 x-16 y+32=0 $$
View solution