Problem 27
Question
In Exercises \(27-36,\) find (if possible): \(\begin{array}{llll}\text { a. } A B & \text { and } & \text { b. } B A\end{array}\) $$ A=\left[\begin{array}{ll} 1 & 3 \\ 5 & 3 \end{array}\right], \quad B=\left[\begin{array}{rr} 3 & -2 \\ -1 & 6 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The resulting matrices are AB = \[\left[\begin{array}{ll} 0 & 16 \ 12 & 8 \end{array}\right], and BA = \[\left[\begin{array}{ll} -7 & 3 \ 29 & 15 \end{array}\right]\]
1Step 1: Check the dimensions for validity of multiplication
Matrix A is a \(2×2\) matrix and matrix B is also a \(2×2\) matrix. Hence, AB and BA are both valid as the number of columns in A equals the number of rows in B and vice versa.
2Step 2: Calculate AB
Compute AB by multiplying corresponding elements and adding the values. Thus, AB equals \[\left[\begin{array}{ll} (1*3) + (3*-1) & (1*-2) + (3*6) \ (5*3) + (3*-1) & (5*-2) + (3*6) \end{array}\right] = \[\left[\begin{array}{ll} 0 & 16 \ 12 & 8 \end{array}\right]\]
3Step 3: Calculate BA
Compute BA similarly. Thus, BA equals \[\left[\begin{array}{ll} (3*1) + (-2*5) & (3*3) + (-2*3) \ (-1*1) + (6*5) & (-1*3) + (6*3) \end{array}\right] = \[\left[\begin{array}{ll} -7 & 3 \ 29 & 15 \end{array}\right]\]
Key Concepts
MatricesMatrix OperationsAlgebraic Expressions2x2 Matrices
Matrices
Matrices are rectangular arrays of numbers arranged in rows and columns. They serve as a foundational tool in linear algebra. Each element in a matrix is usually denoted by a coordinate that consists of its row and column position. In the given exercise, we work with two matrices:
- Matrix A, with elements aligned in two rows and two columns.
- Matrix B, which similarly has two rows and two columns.
Matrix Operations
Matrix operations encompass several fundamental procedures such as addition, subtraction, and multiplication. Here, we focus on multiplication, which requires the matrices to have dimensions that align properly.
For matrices to be multiplied, the number of columns in the first matrix must equal the number of rows in the second matrix. For this exercise, both matrices are 2x2, making them compatible for bending either as \(AB\) or \(BA\).When matrices are multiplied:
For matrices to be multiplied, the number of columns in the first matrix must equal the number of rows in the second matrix. For this exercise, both matrices are 2x2, making them compatible for bending either as \(AB\) or \(BA\).When matrices are multiplied:
- Each element in the resulting product is obtained by summing the products of elements from the corresponding row and column.
- This can be computationally intensive but follows systematic rules, allowing precise computation.
Algebraic Expressions
In working with matrices, algebraic expressions organize the calculations into manageable parts. An algebraic expression involves arithmetic calculations combining variables and numbers, set out in formulaic form.
For matrix multiplication, each element of the resulting matrix involves an algebraic expression defined by:
For matrix multiplication, each element of the resulting matrix involves an algebraic expression defined by:
- The product of elements from a row of the first matrix with a column of the second matrix.
- All products from corresponding row and column elements are summed up.
2x2 Matrices
A 2x2 matrix is particularly simple yet forms the basis of understanding larger, more complex matrices. Each 2x2 matrix consists of four elements arranged in two rows and two columns.
In this exercise:
In this exercise:
- Matrix A has elements \(\begin{bmatrix} 1 & 3 \ 5 & 3 \end{bmatrix}\).
- Matrix B has elements \(\begin{bmatrix} 3 & -2 \ -1 & 6 \end{bmatrix}\).
- Helps students appreciate how small systems are structured.
- Forms a stepping stone to comprehending larger dimension operations.
Other exercises in this chapter
Problem 26
Use Cramer's rule to solve each system or to determine that the system is inconsistent or contains dependent equations. $$ \begin{aligned}&2 x=7+3 y\\\&4 x-6 y=
View solution Problem 26
find \(A^{-1}\) by forming \([A | I]\) and then using row operations to obtain [ \(I | B],\) where \(A^{-1}=[B]\) Check that \(A A^{-1}=I\) and \(A^{-1} A=I\) $
View solution Problem 27
Evaluate each determinant. $$ \left|\begin{array}{rrr}3 & 0 & 0 \\\2 & 1 & -5 \\\2 & 5 & -1\end{array}\right| $$
View solution Problem 27
find \(A^{-1}\) by forming \([A | I]\) and then using row operations to obtain [ \(I | B],\) where \(A^{-1}=[B]\) Check that \(A A^{-1}=I\) and \(A^{-1} A=I\) $
View solution