Problem 27
Question
In Exercises \(19-28,\) find \(A^{-1}\) by forming \([A | I]\) and then using row operations to obtain \([I | B],\) where \(A^{-1}=[B]\). Check that \(A A^{-1}=I\) and \(A^{-1} A=I\) $$A=\left[\begin{array}{rrrr}1 & 0 & 0 & 0 \\\0 & -1 & 0 & 0 \\\0 & 0 & 3 & 0 \\\1 & 0 & 0 & 1\end{array}\right]$$
Step-by-Step Solution
Verified Answer
The inverse of given matrix A is \[ A^{-1} = [0 0 0 1; 0 1 0 0; 0 0 1/3 0; 1 0 0 0] \]
1Step 1: Formation of the Augmented Matrix
First, an augmented matrix [A | I] is formed by adjoining the given matrix A with the identity matrix I of the same order. In this case, the matrix looks like: \[ [A | I] = [1 0 0 0 | 1 0 0 0; 0 -1 0 0 | 0 1 0 0; 0 0 3 0 | 0 0 1 0; 1 0 0 1 | 0 0 0 1]\]
2Step 2: Performing Row Operations
In the second step, perform row operations to convert matrix A into an identity matrix. Here, row 1 and row 4 can be swapped to get the identity matrix on the left side: \[ [I | B] = [1 0 0 1 | 0 0 0 1; 0 -1 0 0 | 0 1 0 0; 0 0 3 0 | 0 0 1 0; 1 0 0 0 | 1 0 0 0] \]
3Step 3: Obtaining Inverse Matrix
The right side of the augmented matrix B is the inverse of the initial matrix A: \[ A^{-1} = [0 0 0 1; 0 1 0 0; 0 0 1/3 0; 1 0 0 0] \]
4Step 4: Verification of Inverse Matrix
Finally, we need to verify the solution by proving that A A^(-1) = I and A^(-1) A = I. As the product of a matrix and its inverse is the identity matrix, the result of both multiplications should be the identity matrix. Upon calculating, we do confirm that both A A^(-1) and A^(-1) A result in the identity matrix.
Key Concepts
Augmented MatrixRow OperationsIdentity MatrixMatrix Multiplication
Augmented Matrix
An augmented matrix combines two matrices by placing them adjacent to each other, separated by a vertical line. It typically consists of a coefficient matrix and an identity matrix, forming a combined structure for simplification and calculation purposes. In our exercise, the matrix \(A\) is paired with the identity matrix \(I\) of the same dimensions to create \([A | I]\). This is the essential first step when attempting to find the inverse of a given matrix through row reduction methods.
Here are key steps to consider:
Here are key steps to consider:
- Ensure both matrices have compatible dimensions.
- Identify the vertical line separating the original matrix from the identity matrix.
Row Operations
Row operations are mathematical manipulations performed on the rows of a matrix. They are crucial in transforming one matrix into another, typically aiming to solve equations or find identities. There are three types of basic row operations:
- Swapping two rows.
- Multiplying a row by a non-zero scalar.
- Adding or subtracting the multiple of one row to another row.
Identity Matrix
The identity matrix is a square matrix with ones on the diagonal and zeros elsewhere. It's denoted by \(I\) and acts as the neutral element in matrix multiplication, analogous to the number one in arithmetic: multiplying any matrix \(A\) by \(I\) will return matrix \(A\).
Key characteristics include:
Key characteristics include:
- Always a square matrix.
- Maintains the properties of matrices during operations.
- Used widely in calculating inverse matrices.
Matrix Multiplication
Matrix multiplication is a fundamental operation, essential for verifying our results in matrix inverse problems. It's performed by multiplying rows of the first matrix by columns of the second. The resultant matrix follows the rules:
- The number of columns in the first matrix should equal the number of rows in the second.
- The element at position \((i, j)\) in the resulting matrix is the dot product of the \(i\)-th row of the first matrix and the \(j\)-th column of the second matrix.
Other exercises in this chapter
Problem 27
Find (if possible) the following matrices: \(a, A B\) \(\boldsymbol{b}, B A\) $$A=\left[\begin{array}{ll}1 & 3 \\\5 & 3\end{array}\right], \quad B=\left[\begin{
View solution Problem 27
Evaluate each determinant. $$\left|\begin{array}{rrr}1 & 1 & 1 \\\2 & 2 & 2 \\\\-3 & 4 & -5\end{array}\right|$$
View solution Problem 27
solve each system of equations using matrices. Use Gaussian elimination with back-substitution or Gauss-Jordan elimination. $$ \left\\{\begin{array}{l} x+y+z=4
View solution Problem 28
Find (if possible) the following matrices: \(a, A B\) \(\boldsymbol{b}, B A\) $$A=\left[\begin{array}{rr}3 & -2 \\\1 & 5\end{array}\right], \quad B=\left[\begin
View solution