Problem 27
Question
(II) Determine the lowest four energy levels and wave functions for an electron trapped in an infinitely deep potential well of width 2.0 \(\mathrm{nm} .\)
Step-by-Step Solution
Verified Answer
The lowest four energy levels are calculated and their wave functions are expressed in sine terms, considering the well width of 2 nm.
1Step 1: Understand the Potential Well
An infinitely deep potential well imposes boundary conditions where the potential energy inside the well is zero, and it is infinite outside. This means the wave function must be zero at the boundaries of the well, at \( x = 0 \) and \( x = L \) where \( L = 2 \text{ nm} \).
2Step 2: Apply the Schrödinger Equation
Use the time-independent Schrödinger equation for a particle in an infinite potential well: \( -\frac{\hbar^2}{2m} \frac{d^2 \psi}{dx^2} = E \psi \). Since the potential inside the well is zero, this simplifies to \( \frac{d^2 \psi}{dx^2} + k^2 \psi = 0 \) where \( k^2 = \frac{2mE}{\hbar^2} \).
3Step 3: Determine the Form of the Wave Function
The general solution to the differential equation is \( \psi(x) = A \sin(kx) + B \cos(kx) \). The boundary conditions \( \psi(0) = 0 \) and \( \psi(L) = 0 \) imply \( B = 0 \) and \( \sin(kL) = 0 \).
4Step 4: Solve for Allowed Wave Numbers
The condition \( \sin(kL) = 0 \) implies \( kL = n\pi \), where \( n \) is a positive integer. Therefore, \( k = \frac{n\pi}{L} \). For \( L = 2 \text{ nm} \), \( k = \frac{n\pi}{2 \times 10^{-9}} \).
5Step 5: Calculate Energy Levels
The energy levels are given by \( E_n = \frac{\hbar^2 k^2}{2m} = \frac{n^2 \pi^2 \hbar^2}{2mL^2} \). Using \( \hbar = 1.055 \times 10^{-34} \text{ J}\cdot\text{s} \) and \( m = 9.11 \times 10^{-31} \text{ kg} \), we find \( E_1, E_2, E_3, E_4 \) by substituting \( n = 1, 2, 3, 4 \).
6Step 6: Calculate Specific Energies
Substitute values to find specific energies. For example, \( E_1 = \frac{\pi^2 (1.055 \times 10^{-34})^2}{2 \times 9.11 \times 10^{-31} \times (2 \times 10^{-9})^2} \approx 6.024 \times 10^{-20} \text{ J} \). This process is repeated for \( E_2, E_3, \) and \( E_4 \) with \( n = 2, 3, 4 \).
7Step 7: Write the Wave Functions
For each energy level \( n \), the wave function \( \psi_n(x) = A \sin\left(\frac{n\pi x}{L}\right) \). Use normalization conditions to find \( A \), typically resulting in \( A = \sqrt{\frac{2}{L}} \). Therefore, \( \psi_n(x) = \sqrt{\frac{2}{L}} \sin\left(\frac{n\pi x}{L}\right) \).
Key Concepts
Infinitely Deep Potential WellWave FunctionEnergy LevelsSchrödinger Equation
Infinitely Deep Potential Well
The concept of an infinitely deep potential well is pivotal in quantum mechanics for understanding how particles behave when constrained within a particular region. Imagine this well as a box with walls so high that a particle can never escape. The potential energy inside this well is zero, meaning a particle can move freely within, but becomes infinite at the boundaries. As a result, the wave function, which describes the probability of finding a particle, must be zero at these boundaries. In the case of a well with width 2 nm, this condition holds at both ends, specifically when the position is at 0 nm and 2 nm.
Wave Function
In quantum mechanics, the wave function is a fundamental concept that captures all the information about a quantum system. When dealing with particles, like electrons in an infinitely deep potential well, the wave function determines the probability of finding the particle at various positions.
The wave function for a particle in such a well is typically given by:
The wave function for a particle in such a well is typically given by:
- For boundary conditions \( \psi(0) = 0 \) and \( \psi(L) = 0 \, \text{where } L = 2 \text{ nm}\)
- This leads to solutions of the form \( \psi(x) = A \sin(kx) + B \cos(kx) \) where \( B = 0 \).
Energy Levels
The energy levels in an infinitely deep potential well are quantized, meaning they can only take on discrete values. Quantum mechanics dictates that these levels are proportional to the square of the integers known as quantum numbers, represented as \( n \, = 1, 2, 3, ... \).
The energies are given by:
The energies are given by:
- \( E_n = \frac{\hbar^2 k^2}{2m} \)
- Substituting for \( k \, \text{the expression simplifies to } E_n = \frac{n^2 \pi^2 \hbar^2}{2mL^2} \)
- Calculating for the first few quantum numbers (\( n = 1, 2, 3, \,\text{and } 4\)) yields specific energy values with increasing magnitude.
Schrödinger Equation
The Schrödinger Equation is the cornerstone of quantum mechanics, governing how the quantum state of a physical system changes over time. For an infinitely deep potential well, we work with the time-independent Schrödinger Equation:
- \( -\frac{\hbar^2}{2m} \frac{d^2 \psi}{dx^2} = E\psi \)
- Inside the well, this simplifies to \( \frac{d^2 \psi}{dx^2} + k^2 \psi = 0 \), where \( k^2 = \frac{2mE}{\hbar^2} \)
Other exercises in this chapter
Problem 24
(II) An \(n=4\) to \(n=1\) transition for an electron trapped in a rigid box produces a 340 -nm photon. What is the width of the box?
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(II) For a particle in a box with rigid walls, determine whether our results for the ground state are consistent with the uncertainty principle by calculating t
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(II) Consider an atomic nucleus to be a rigid box of width \(2.0 \times 10^{-14} \mathrm{~m} .\) What would be the ground-state energy for (a) an electron, (b)
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(II) A proton in a nucleus can be roughly modeled as a particle in a box of nuclear dimensions. Calculate the energy released when a proton confined in a nucleu
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