Problem 27
Question
If \(\vec{d}_{1}+\vec{d}_{2}=5 \vec{d}_{3}, \vec{d}_{1}-\vec{d}_{2}=3 \vec{d}_{3}\), and \(\vec{d}_{3}=2 \hat{i}+4 \hat{j}\), then what are, in unit-vector notation, (a) \(\vec{d}_{1}\) and (b) \(\vec{d}_{2}\) ?
Step-by-Step Solution
Verified Answer
\( \vec{d}_1 = 8 \hat{i} + 16 \hat{j} \), \( \vec{d}_2 = 2 \hat{i} + 4 \hat{j} \).
1Step 1: Set Up Equations
We are given two vector equations: 1. \( \vec{d}_1 + \vec{d}_2 = 5 \vec{d}_3 \) 2. \( \vec{d}_1 - \vec{d}_2 = 3 \vec{d}_3 \) We also know that \( \vec{d}_3 = 2 \hat{i} + 4 \hat{j} \). We start by substituting \( \vec{d}_3 \) into the equations.
2Step 2: Substitute Values of \\vec{d}_3
Substitute \( \vec{d}_3 = 2 \hat{i} + 4 \hat{j} \) into the two equations:\[ \vec{d}_1 + \vec{d}_2 = 5(2 \hat{i} + 4 \hat{j}) = 10 \hat{i} + 20 \hat{j} \]\[ \vec{d}_1 - \vec{d}_2 = 3(2 \hat{i} + 4 \hat{j}) = 6 \hat{i} + 12 \hat{j} \]
3Step 3: Add Equations to Solve for \\vec{d}_1
Add the equations to eliminate \( \vec{d}_2 \):\[ (\vec{d}_1 + \vec{d}_2) + (\vec{d}_1 - \vec{d}_2) = (10 \hat{i} + 20 \hat{j}) + (6 \hat{i} + 12 \hat{j}) \]\[ 2\vec{d}_1 = 16 \hat{i} + 32 \hat{j} \] Divide by 2:\[ \vec{d}_1 = 8 \hat{i} + 16 \hat{j} \]
4Step 4: Plug Back to Find \\vec{d}_2
Substitute \( \vec{d}_1 = 8 \hat{i} + 16 \hat{j} \) back into the first equation to find \( \vec{d}_2 \):\[ 8 \hat{i} + 16 \hat{j} + \vec{d}_2 = 10 \hat{i} + 20 \hat{j} \]Solving for \( \vec{d}_2 \) gives:\[ \vec{d}_2 = (10 \hat{i} + 20 \hat{j}) - (8 \hat{i} + 16 \hat{j}) \]\[ \vec{d}_2 = 2 \hat{i} + 4 \hat{j} \]
5Step 5: Conclude the Solution
Now that we've solved for both vectors, summarize the solution:- \( \vec{d}_1 = 8 \hat{i} + 16 \hat{j} \)- \( \vec{d}_2 = 2 \hat{i} + 4 \hat{j} \)
Key Concepts
Unit-Vector NotationVector EquationsLinear Algebra
Unit-Vector Notation
Understanding unit-vector notation is crucial when working with vectors, especially in physics and engineering. In unit-vector notation, vectors are broken down into their component directions, using standard unit vectors.
- Unit Vectors: These are vectors with a magnitude of one, commonly denoted as \( \hat{i} \), \( \hat{j} \), and \( \hat{k} \). In the Cartesian coordinate system, \( \hat{i} \) represents the x-axis direction, \( \hat{j} \) represents the y-axis direction, and \( \hat{k} \) represents the z-axis direction.
- Component Representation: Any vector in the plane (2D) can be expressed as a combination of these unit vectors. For example, if you have \( \vec{v} = a \hat{i} + b \hat{j} \), it means the vector has a magnitude of \( a \) in the x-direction and \( b \) in the y-direction.
Vector Equations
Vector equations provide a powerful method for solving problems involving multiple vectors. They allow you to work with vectors algebraically in the same way you would with numbers.
- Setting Up Equations: To solve problems, it's important to first express all your known and unknown vectors using equations. In this case, the two equations are \( \vec{d}_1 + \vec{d}_2 = 5 \vec{d}_3 \) and \( \vec{d}_1 - \vec{d}_2 = 3 \vec{d}_3 \).
- Substitution: By substituting known vectors into these equations, you reduce the problem to algebraic manipulation. For our exercise, substituting \( \vec{d}_3 \) as \( 2\hat{i} + 4\hat{j} \) allows you to solve these equations step-by-step.
Linear Algebra
Linear algebra is a branch of mathematics focused on vectors, vector spaces, and operations like vector addition. It's essential for understanding how vectors interact in various fields such as physics and engineering.
- Vector Addition: This is a fundamental operation where corresponding components of vectors are added together. It forms the basis of the vector equations seen in our exercise.
- Linear Combinations: A core concept, where vectors are combined linearly using scalar coefficients, like in \( 5 \vec{d}_3 \) and \( 3 \vec{d}_3 \) seen in the equations. These coefficients scale the vectors, contributing to their sum or difference.
- Solving Systems: Linear algebra often involves solving systems of equations, typically involving sets of vector equations. Using algebraic methods, you can find solutions to these equations efficiently.
Other exercises in this chapter
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