Problem 27
Question
Graph the points and draw a line through them. Write an equation in slope- intercept form of the line that passes through the points. $$ (6,-4),(-1,2) $$
Step-by-Step Solution
Verified Answer
The equation of the line that passes through points (6,-4) and (-1,2) is \( y = -\frac{6}{7}x + \frac{2}{7} \)
1Step 1: Plot the Points
Plot the points (6,-4) and (-1,2) on a graph paper.
2Step 2: Calculate the Slope
Use the formula: \( m = \frac{y_2 - y_1}{x_2 - x_1} \), where \( (x_1, y_1) \) are the coordinates of the first point (6,-4) and \( (x_2, y_2) \) are the coordinates of the second point (-1,2). So the slope \( m \) equals to \( m = \frac{2 - (-4)}{-1 - 6} = \frac{6}{-7} = -\frac{6}{7} \).
3Step 3: Calculate the y-Intercept
Having the slope, now use one of the points and substitute to the form \( y = mx + b \) to find the y-intercept \( b \). Let's use point (6,-4). So we have: \( -4 = -\frac{6}{7}*6 + b \) which simplifies into \( -4 = -\frac{36}{7} + b \). Therefore, the y-intercept \( b \) is \( b = -4 + \frac{36}{7} = \frac{2}{7} \).
4Step 4: Write Down the Line Equation
Now we substitute the slope \( m \) and y-intercept \( b \) into the slope-intercept form. The line equation is \( y = -\frac{6}{7}x + \frac{2}{7} \)
Key Concepts
Graphing PointsCalculating SlopeFinding y-InterceptLine Equation
Graphing Points
Plotting points is the first step in understanding how to graph a line on a coordinate system. To graph the points provided in the exercise, you need to locate each point based on its coordinates. Coordinates are written as pairs of numbers:
- The first number is the x-coordinate (horizontal position).
- The second number is the y-coordinate (vertical position).
Calculating Slope
The slope of a line is a measure of its steepness and direction. It is calculated using the formula:\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]The variables \((x_1, y_1)\) and \((x_2, y_2)\) are the coordinates of any two points on the line. In this exercise, we use the points \((6, -4)\) and \((-1, 2)\). Plugging these into the formula gives:
- Difference in y-values: \(2 - (-4) = 6\)
- Difference in x-values: \(-1 - 6 = -7\)
Finding y-Intercept
The y-intercept is the point where the line crosses the y-axis, and it's represented by \(b\) in the slope-intercept equation \(y = mx + b\). To find the y-intercept, use the slope you calculated and one of the points on the line in the equation. Let's use the point (6, -4):\[-4 = -\frac{6}{7}(6) + b\] Simplify:\[-4 = -\frac{36}{7} + b\] Add \(\frac{36}{7}\) to both sides to solve for \(b\):\[b = -4 + \frac{36}{7}\] Convert \(-4\) to \(\frac{-28}{7}\) to easily add fractions:\[b = \frac{-28}{7} + \frac{36}{7} = \frac{2}{7}\]Therefore, the y-intercept is \(\frac{2}{7}\).
Line Equation
The slope-intercept form of a line equation is written as \(y = mx + b\). This form makes it clear what the slope (\(m\)) and the y-intercept (\(b\)) are. Once you have calculated both:
- Slope \(m = -\frac{6}{7}\)
- y-intercept \(b = \frac{2}{7}\)
Other exercises in this chapter
Problem 27
Write the equation in standard form with integer coefficients. $$3 x+9=\frac{7}{2} y$$
View solution Problem 27
Write an equation in point-slope form of the line that passes through the given points. $$ (-3,-9),(-6,-8) $$
View solution Problem 28
Use the table which shows the average tuition for attending a private and a public four-year college. $$ \begin{array}{|c|c|c|}\hline \text { Year } & \text { P
View solution Problem 28
Write the equation in standard form with integer coefficients. $$y=9 x+\frac{1}{2}$$
View solution