Problem 27
Question
For the following exercises, solve the system by Gaussian elimination. $$ \begin{array}{l} -60 x+45 y=12 \\ 20 x-15 y=-4 \end{array} $$
Step-by-Step Solution
Verified Answer
The system has infinitely many solutions, expressed as \(x = \frac{3}{4}t - \frac{1}{5}, y = t\) for any real number \(t\).
1Step 1: Write the Augmented Matrix
Convert the given system of equations into an augmented matrix. The system is: \(-60x + 45y = 12\) and \(20x - 15y = -4\). Write it as:\[\begin{bmatrix}-60 & 45 & | & 12 \20 & -15 & | & -4\end{bmatrix}\]
2Step 2: Simplify Rows
Simplify the rows to make calculations easier. Divide the first row by 15 and the second row by 5 to get:\[\begin{bmatrix}-4 & 3 & | & rac{4}{5} \4 & -3 & | & -rac{4}{5}\end{bmatrix}\]
3Step 3: Eliminate x from Second Equation
Add the first row to the second row to eliminate \(x\) from the second equation:\[\begin{bmatrix}-4 & 3 & | & rac{4}{5} \0 & 0 & | & 0\end{bmatrix}\]
4Step 4: Interpret the Result
The resulting matrix corresponds to the equations \(-4x + 3y = \frac{4}{5}\) and \(0 = 0\). The second row, \(0 = 0\), suggests that there are infinitely many solutions as it does not provide any additional information about \(x\) or \(y\).
5Step 5: Express Solutions in Parametric Form
Since the second equation gives no new information, express \(x\) in terms of \(y\) using the first equation. Re-arrange \(-4x + 3y = \frac{4}{5}\) to get:\[x = \frac{3}{4}y - \frac{1}{5}\]Expressing in a parametric form, we choose \(y = t\) (a parameter), which means:\(x = \frac{3}{4}t - \frac{1}{5}\), \(y = t\), for all real numbers \(t\).
Key Concepts
Augmented MatrixParametric FormSystem of Equations
Augmented Matrix
The concept of an augmented matrix is a useful tool when solving systems of equations using methods like Gaussian Elimination. An augmented matrix is a compact representation of a system of linear equations, where the coefficients of the variables and the constants from the equations are placed into a matrix format. This format makes it easier to perform row operations and simpler transformations during the elimination process. In our particular exercise, the system of equations is
- \(-60x + 45y = 12\)
- \(20x - 15y = -4\)
Parametric Form
When a system of equations possesses infinitely many solutions, expressing the solution in parametric form provides a convenient way to list all possible solutions. In our exercise, the final form of the equations after using Gaussian Elimination resulted in \(-4x + 3y = \frac{4}{5}\)and an equation of \(0 = 0\), indicating infinite solutions.
To express this parametrically, we solve \(-4x + 3y = \frac{4}{5}\)\(x = \frac{3}{4}y - \frac{1}{5}\)By introducing a parameter, say \(t\), to represent one variable, typically the most convenient one, the solutions of the system then become:
To express this parametrically, we solve \(-4x + 3y = \frac{4}{5}\)\(x = \frac{3}{4}y - \frac{1}{5}\)By introducing a parameter, say \(t\), to represent one variable, typically the most convenient one, the solutions of the system then become:
- \(x = \frac{3}{4}t - \frac{1}{5}\)
- \(y = t\)
System of Equations
A system of equations is a collection of two or more equations, each containing one or more variables. Solving this system means finding a set of values for the variables that satisfies every equation simultaneously. In our exercise, we were given the system:
- \(-60x + 45y = 12\)
- \(20x - 15y = -4\)
Other exercises in this chapter
Problem 27
For the following exercises, solve the system of linear equations using Cramer's Rule. $$ \begin{array}{l} 6 x-3 y=2 \\ -8 x+9 y=-1 \end{array} $$
View solution Problem 27
For the following exercises, solve the system using the inverse of a \(2 \times 2\) matrix. $$ \begin{array}{l} 5 x-6 y=-61 \\ 4 x+3 y=-2 \end{array} $$
View solution Problem 27
For the following exercises, use the matrices below to perform the indicated operation if possible. If not possible, explain why the operation cannot be perform
View solution Problem 27
For the following exercises, find the decomposition of the partial fraction for the repeating linear factors. $$ \frac{5 x^{2}+20 x+8}{2 x(x+1)^{2}} $$
View solution