Problem 27
Question
For each pair of bonds, indicate the more polar bond, and use an arrow to show the direction of polarity in each bond. (a) \(\mathrm{C}-\mathrm{O}\) and \(\mathrm{C}-\mathrm{N}\) (b) \(\mathrm{P}-\mathrm{Br}\) and \(\mathrm{P}-\mathrm{Cl}\) (c) \(\mathrm{B}-\mathrm{O}\) and \(\mathrm{B}-\mathrm{S}\) (d) \(\mathrm{B}-\mathrm{F}\) and \(\mathrm{B}-\mathrm{I}\)
Step-by-Step Solution
Verified Answer
More polar: (a) C-O (C→O), (b) P-Cl (P→Cl), (c) B-O (B→O), (d) B-F (B→F).
1Step 1: Understanding Polarity
Bond polarity occurs when there is a difference in electronegativity between two atoms. The atom with a higher electronegativity will attract the shared electron pair more strongly, making the bond polar. The direction of polarity is indicated by an arrow pointing towards the more electronegative atom.
2Step 1: Compare Electronegativity for C-O and C-N
Oxygen (
O) has a higher electronegativity than nitrogen (
N). Therefore, the bond
C-O is more polar than
C-N. The direction of polarity (arrow) points from carbon (
C) to oxygen (
O), as oxygen is more electronegative.
Thus,
C → O.
3Step 2: Compare Electronegativity for P-Br and P-Cl
Chlorine (
Cl) is more electronegative than bromine (
Br). Thus, the
P-Cl bond is more polar than the
P-Br bond. The arrow for the bond polarity points from phosphorus (
P) to chlorine (
Cl). Thus,
P → Cl.
4Step 3: Compare Electronegativity for B-O and B-S
Oxygen (
O) has a higher electronegativity compared to sulfur (
S). So, the bond
B-O is more polar than
B-S. The direction of the arrow is from boron (
B) to oxygen (
O), as oxygen is more electronegative. Thus,
B → O.
5Step 4: Compare Electronegativity for B-F and B-I
Fluorine (
F) has a higher electronegativity than iodine (
I). Therefore, the bond
B-F is more polar than
B-I. The direction of the arrow goes from boron (
B) to fluorine (
F), as fluorine is more electronegative. Thus,
B → F.
Key Concepts
ElectronegativityPolar BondsChemical BondsDirection of Polarity
Electronegativity
Electronegativity is a measure of how strongly an atom can attract and hold onto electrons in a chemical bond. Each element has its own electronegativity value, and these values are crucial for determining the nature of bonds. Typically, electronegativity increases across a period on the periodic table and decreases as you move down a group.
This means that elements on the top right of the periodic table, like fluorine, have the highest electronegativities. When two atoms with different electronegativities form a bond, the more electronegative atom will have a stronger pull on the shared electrons, creating a polar bond. Understanding where elements fall on the electronegativity scale helps predict which atom will more strongly attract the bond's electron pair, thus influencing the bond's characteristics.
This means that elements on the top right of the periodic table, like fluorine, have the highest electronegativities. When two atoms with different electronegativities form a bond, the more electronegative atom will have a stronger pull on the shared electrons, creating a polar bond. Understanding where elements fall on the electronegativity scale helps predict which atom will more strongly attract the bond's electron pair, thus influencing the bond's characteristics.
Polar Bonds
Polar bonds are a result of the difference in electronegativity between two bonded atoms. When this difference is significant, the shared electrons will spend more time closer to the more electronegative atom. This unequal sharing of electrons leads to a separation of charge within the bond, making it polar.
The greater the difference in electronegativity, the more polar the bond is. For example:
The greater the difference in electronegativity, the more polar the bond is. For example:
- The C-O bond is polar because oxygen is much more electronegative than carbon.
- In the bond between P-Cl, chlorine's higher electronegativity makes the bond polar.
Chemical Bonds
Chemical bonds are the lasting attractions between atoms that enable the formation of chemical compounds. These bonds can be covalent, ionic, or metallic, depending on the nature of the elements involved.
In covalent bonds, atoms share electrons to achieve greater stability, typically fulfilling the octet rule. However, when the atoms involved have different electronegativities, the shared electrons are not equally distributed, creating polar covalent bonds. Ionic bonds, on the other hand, result from the transfer of electrons from one atom to another, forming ions.
In covalent bonds, atoms share electrons to achieve greater stability, typically fulfilling the octet rule. However, when the atoms involved have different electronegativities, the shared electrons are not equally distributed, creating polar covalent bonds. Ionic bonds, on the other hand, result from the transfer of electrons from one atom to another, forming ions.
- C-O, B-F, and similar bonds are examples of covalent bonds with polar characteristics.
- P-Cl bonds show how different electronegativities can influence bond nature, although still covalent.
Direction of Polarity
The direction of polarity in a bond is the trend or orientation of partial charges within a molecule due to uneven electron sharing. This direction is typically indicated by an arrow, pointing from the less electronegative atom towards the more electronegative one.
An arrow shows where the electron density is moving. For instance:
An arrow shows where the electron density is moving. For instance:
- In the C-O bond, the arrow points from carbon to oxygen, indicating oxygen is more electronegative.
- Similarly, in B-F, the arrow points from boron to fluorine.
Other exercises in this chapter
Problem 22
Draw a Lewis structure for each of the following molecules or ions. Describe the electron-pair geometry and the molecular geometry around the central atom. (a)
View solution Problem 23
Give approximate values for the indicated bond angles. (a) \(\mathrm{O}-\mathrm{S}-\mathrm{O}\) in \(\mathrm{SO}_{2}\) (b) \(\mathrm{F}-\mathrm{B}-\mathrm{F}\)
View solution Problem 28
For each of the bonds listed below, tell which atom is the more negatively charged. (a) \(\mathbf{C}-\mathbf{N}\) (b) \(\mathbf{C}-\mathbf{H}\) (c) \(\mathrm{C}
View solution Problem 31
Considering both formal charges and bond polarities, predict on which atom or atoms the negative charge resides in the following anions: (a) \(\mathrm{OH}^{-}\)
View solution