Problem 27
Question
Find the \(n\)th term of a sequence whose first several terms are given. \(2,4,6,8, \dots\)
Step-by-Step Solution
Verified Answer
The nth term is \(a_n = 2n\).
1Step 1: Identify the Pattern
Examine the sequence: 2, 4, 6, 8, ... and determine how each term relates to its position in the sequence. Notice that each term is 2 more than the previous term, suggesting a constant difference.
2Step 2: Confirm the Pattern as an Arithmetic Sequence
Check if the pattern holds by finding the differences between consecutive terms: 4 - 2 = 2, 6 - 4 = 2, 8 - 6 = 2. Since the difference is constant, this is an arithmetic sequence.
3Step 3: Derive the Formula for the General Term
Use the formula for the general term of an arithmetic sequence: \(a_n = a + (n-1) imes d\), where \(a\) is the first term and \(d\) is the common difference. Here, \(a = 2\) and \(d = 2\).
4Step 4: Substitute Values into the Formula
Substitute \(a = 2\) and \(d = 2\) into the formula: \(a_n = 2 + (n-1) imes 2\). This simplifies to \(a_n = 2 + 2n - 2\), which further simplifies to \(a_n = 2n\).
Key Concepts
Common DifferenceGeneral Term FormulaSequence Pattern Recognition
Common Difference
In mathematics, specifically in sequences, the *common difference* is a key component in determining whether a sequence is arithmetic. An arithmetic sequence occurs when the difference between consecutive terms is constant. For example, consider the sequence: 2, 4, 6, 8, ... This sequence is arithmetic because each subsequent term is obtained by adding 2 to the previous term. Here, 2 is the common difference. It's consistent across terms, allowing us to predict subsequent values in the sequence.
- The *common difference* is denoted as \(d\).
- If given the first term \(a\) and the common difference \(d\), you can generate the entire sequence.
- Recognizing this common difference helps distinguish the type of sequence you are dealing with, here it is arithmetic.
General Term Formula
To find any term in an arithmetic sequence, the *general term formula* is indispensable. The formula for the general term, or the \(n\)th term, of an arithmetic sequence is: \(a_n = a + (n-1) \times d\). Here, \(a\) is the first term, \(n\) is the term number, and \(d\) is the common difference.
In our sequence example of 2, 4, 6, 8, ..., and using \(a = 2\) and \(d = 2\), the general term formula becomes \(a_n = 2 + (n-1) \times 2\). Simplifying this expression yields \(a_n = 2n\). This formula allows us to calculate any term in the sequence by simply plugging in the desired term number \(n\).
In our sequence example of 2, 4, 6, 8, ..., and using \(a = 2\) and \(d = 2\), the general term formula becomes \(a_n = 2 + (n-1) \times 2\). Simplifying this expression yields \(a_n = 2n\). This formula allows us to calculate any term in the sequence by simply plugging in the desired term number \(n\).
- Use \(a_n = a + (n-1) \times d\) to find any term.
- In the formula, replacing \(n\) with your desired term number gives its value.
- This approach saves time and effort since there's no need for listing all preceding terms.
Sequence Pattern Recognition
Recognizing *patterns* in sequences is an important skill for identifying types of sequences and their properties. Pattern recognition encompasses observing how sequences progress and identifying if a predictable rule applies. For the arithmetic sequence 2, 4, 6, 8, ..., observe how each term increases by a constant value of 2. This consistent pattern tells us the sequence is arithmetic.
Understanding patterns allows us to
Understanding patterns allows us to
- Deducate the type of sequence (arithmetic, geometric, etc.).
- Predict subsequent terms without explicitly listing them.
- Formulate rules, like the general term formula, to find further terms efficiently.
Other exercises in this chapter
Problem 27
Show that \(x-y\) is a factor of \(x^{n}-y^{n}\) for all natural numbers \(n\) \(\left[\text {Hint: } x^{k+1}-y^{k+1}=x^{k}(x-y)+\left(x^{k}-y^{k}\right) y .\ri
View solution Problem 27
Use the Binomial Theorem to expand the expression. $$\left(1+\frac{1}{x}\right)^{6}$$
View solution Problem 28
Find the first five terms of the sequence, and determine whether it is arithmetic. If it is arithmetic, find the common difference, and express the \(n\) th ter
View solution Problem 28
Show that \(x+y\) is a factor of \(x^{2 n-1}+y^{2 n-1}\) for all natural numbers \(n\)
View solution