Problem 27
Question
Find the indicated term of each geometric sequence. $$ a_{7} \text { for } \frac{1}{32}, \frac{1}{16}, \frac{1}{8}, \dots $$
Step-by-Step Solution
Verified Answer
The seventh term of the sequence is 2.
1Step 1: Identify the First Term and Common Ratio
In a geometric sequence, each term after the first is found by multiplying the previous term by a constant called the common ratio. The first term of this sequence is \( a_1 = \frac{1}{32} \). To find the common ratio \( r \), divide the second term by the first term: \( r = \frac{1/16}{1/32} = 2 \).
2Step 2: Use the Formula for the nth Term
The formula for the nth term of a geometric sequence is \( a_n = a_1 \times r^{(n-1)} \). Here, \( a_1 = \frac{1}{32} \), \( r = 2 \), and \( n = 7 \). Substitute these values into the formula to find \( a_7 \).
3Step 3: Calculate the Seventh Term
Substitute the known values into the formula: \( a_7 = \frac{1}{32} \times 2^{(7-1)} \). This simplifies to \( a_7 = \frac{1}{32} \times 2^6 \).
4Step 4: Simplify the Expression
Calculate \( 2^6 \), which is \( 64 \). Then, multiply: \( a_7 = \frac{1}{32} \times 64 \). This simplifies to \( a_7 = 2 \).
Key Concepts
Common RatioNth Term FormulaFirst Term in Geometric Sequence
Common Ratio
In a geometric sequence, the difference between consecutive terms isn't based on addition or subtraction but rather multiplication by a fixed number known as the common ratio. This unique feature sets geometric sequences apart from arithmetic sequences, where the difference is constant by addition. For example, in the sequence \( \frac{1}{32}, \frac{1}{16}, \frac{1}{8}, \dots \), you calculate the common ratio \( r \) by dividing any term by its preceding term.
To find \( r\), simply divide the second term by the first term:
To find \( r\), simply divide the second term by the first term:
- First term \( a_1 = \frac{1}{32} \)
- Second term \( a_2 = \frac{1}{16} \)
Nth Term Formula
To find any term in a geometric sequence, we use the nth term formula. This formula provides a straightforward method to calculate any term based on the positions of the terms and the sequence’s characteristics. The general formula for the nth term is: \[ a_n = a_1 \times r^{(n-1)} \]
Here’s what each symbol stands for:
Substituting into the formula, we calculate \( a_7 = \frac{1}{32} \times 2^{(7-1)} \), which simplifies further. This formula is indispensable for efficiently working with geometric sequences.
Here’s what each symbol stands for:
- \( a_n \): the term we want to find
- \( a_1 \): the first term in the sequence
- \( r \): the common ratio
- \( n \): the term's position in the sequence
Substituting into the formula, we calculate \( a_7 = \frac{1}{32} \times 2^{(7-1)} \), which simplifies further. This formula is indispensable for efficiently working with geometric sequences.
First Term in Geometric Sequence
The starting point in any geometric sequence is crucial as it acts as the foundation for all subsequent terms. Denoted as \( a_1 \), the first term determines the baseline value from which the sequence commences. In the example sequence \( \frac{1}{32}, \frac{1}{16}, \frac{1}{8}, \dots \), the first term is \( a_1 = \frac{1}{32} \).
The first term plays an essential role in the process of determining other terms as it is multiplied by the common ratio raised to a power, according to its position. For example, in the nth term formula \( a_n = a_1 \times r^{(n-1)} \), the term \( a_1 \) determines the constant value related to all terms of the sequence.
Always identifying the first term in a geometric sequence is the stepping stone for successfully leveraging the common ratio and nth term formula in problem-solving.
The first term plays an essential role in the process of determining other terms as it is multiplied by the common ratio raised to a power, according to its position. For example, in the nth term formula \( a_n = a_1 \times r^{(n-1)} \), the term \( a_1 \) determines the constant value related to all terms of the sequence.
Always identifying the first term in a geometric sequence is the stepping stone for successfully leveraging the common ratio and nth term formula in problem-solving.
Other exercises in this chapter
Problem 27
GEOMETRY For Exercises \(25-27,\) study the triangular numbers shown below. What is the 200 th triangular number?
View solution Problem 27
Find the sum of each infinite geometric series, if it exists. $$\sum_{n=1}^{\infty} \frac{1}{100}\left(\frac{101}{99}\right)^{n-1}$$
View solution Problem 27
Find the indicated term of each arithmetic sequence. \(a_{1}=3, d=7, n=14\)
View solution Problem 27
Find \(a_{1}\) for each arithmetic series described. $$ d=-4, n=42, S_{42}=-3360 $$
View solution