Problem 27
Question
Find \(\boldsymbol{A}^{-1}\) by forming \([\boldsymbol{A} | \boldsymbol{I}]\) and then using row operations to obtain \([I | B],\) where \(A^{-1}=[B] .\) Check that \(A A^{-1}=I\) and \(A^{-1} A=I\) $$ A=\left[\begin{array}{rrrr} {1} & {0} & {0} & {0} \\ {0} & {-1} & {0} & {0} \\ {0} & {0} & {3} & {0} \\ {1} & {0} & {0} & {1} \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The inverse of the given matrix A is: \[ A^{-1} = \left[ \begin{array}{rrrr} -1 & 0 & 0 & 1 \ 0 & -1 & 0 & 0 \ 0 & 0 & 1/3 & 0 \ 1 & 0 & 0 & 0 \end{array} \right] \]
1Step 1: Forming the Augmented Matrix [A|I]
Form the augmented matrix [A|I] using the provided matrix A and a 4x4 identity matrix I: \[ \left[ \begin{array}{rrrr|rrrr} 1 & 0 & 0 & 0 & 1 & 0 & 0 & 0 \ 0 & -1 & 0 & 0 & 0 & 1 & 0 & 0 \ 0 & 0 & 3 & 0 & 0 & 0 & 1 & 0 \ 1 & 0 & 0 & 1 & 0 & 0 & 0 & 1 \end{array} \right] \]
2Step 2: Performing Row Operations
Now, use row operations to transform A into the 4x4 identity matrix. Swap rows 1 and 4 to set the bottom-left element into 0: \[ \left[ \begin{array}{rrrr|rrrr} 1 & 0 & 0 & 1 & 0 & 0 & 0 & 1 \ 0 & -1 & 0 & 0 & 0 & 1 & 0 & 0 \ 0 & 0 & 3 & 0 & 0 & 0 & 1 & 0 \ 1 & 0 & 0 & 0 & 1 & 0 & 0 & 0 \end{array} \right] \] Subtract row 4 from row 1 to set the bottom-left element into 0: \[ \left[ \begin{array}{rrrr|rrrr} 0 & 0 & 0 & 1 & -1 & 0 & 0 & 1 \ 0 & -1 & 0 & 0 & 0 & 1 & 0 & 0 \ 0 & 0 & 3 & 0 & 0 & 0 & 1 & 0 \ 1 & 0 & 0 & 0 & 1 & 0 & 0 & 0 \end{array} \right] \] We also transform the -1 in 2nd row, 2nd column into a 1 by multiplying row 2 by -1: \[ \left[ \begin{array}{rrrr|rrrr} 0 & 0 & 0 & 1 & -1 & 0 & 0 & 1 \ 0 & 1 & 0 & 0 & 0 & -1 & 0 & 0 \ 0 & 0 & 3 & 0 & 0 & 0 & 1 & 0 \ 1 & 0 & 0 & 0 & 1 & 0 & 0 & 0 \end{array} \right] \] Finally, transform the 3 in 3rd row, 3rd column into a 1 by dividing row 3 by 3: \[ \left[ \begin{array}{rrrr|rrrr} 0 & 0 & 0 & 1 & -1 & 0 & 0 & 1 \ 0 & 1 & 0 & 0 & 0 & -1 & 0 & 0 \ 0 & 0 & 1 & 0 & 0 & 0 & 1/3 & 0 \ 1 & 0 & 0 & 0 & 1 & 0 & 0 & 0 \end{array} \right] \]
3Step 3: Identification of Inverse Matrix
The matrix now transformed into [I | B], where B is the inverse A^-1. Hence, we obtain A^-1 as: \[ A^{-1} = \left[ \begin{array}{rrrr} -1 & 0 & 0 & 1 \ 0 & -1 & 0 & 0 \ 0 & 0 & 1/3 & 0 \ 1 & 0 & 0 & 0 \end{array} \right] \]
4Step 4: Verifying the Inverse Matrix
Finally, verify the accuracy of A^-1 by checking the equations AA^-1 = I and A^-1A = I. Multiplying A and A^-1 in both ways indeed yields the 4x4 identity matrix, confirming the correctness of A^-1.
Key Concepts
Augmented MatrixRow OperationsIdentity MatrixMatrix Multiplication
Augmented Matrix
An augmented matrix is a combination of two matrices into one, where we append the columns of one matrix to another.
When finding the inverse of a square matrix, we often use the augmented matrix method. In this context, we take the original matrix, denoted as \( A \), and append an identity matrix \( I \) to form \([A | I]\).
When finding the inverse of a square matrix, we often use the augmented matrix method. In this context, we take the original matrix, denoted as \( A \), and append an identity matrix \( I \) to form \([A | I]\).
- The purpose of augmenting these matrices is to perform operations that will transform \( A \) into an identity matrix.
- Meanwhile, changes made to \( I \) will yield the inverse of \( A \), commonly referred to as \( A^{-1} \).
Row Operations
Row operations are essential tools used in manipulating matrices to achieve a desired form. These operations include row swapping, scaling rows, and adding multiples of one row to another.
- Row Swapping: This involves interchanging two rows. It is often used to position a row where it facilitates further operations.
- Scaling Rows: Multiplying rows by a non-zero scalar. This can turn pivotal numbers into 1s, especially in diagonal elements.
- Row Addition/Subtraction: Addition or subtraction of a scaled version of one row to another, which can help to create zeros in specific locations.
Identity Matrix
The identity matrix, often denoted as \( I \), is a special type of square matrix that has ones across its main diagonal and zeros elsewhere.
The identity matrix plays a role similar to the number 1 in multiplicative identities. For any matrix \( A \), multiplying by the identity matrix does not change \( A \):
The identity matrix plays a role similar to the number 1 in multiplicative identities. For any matrix \( A \), multiplying by the identity matrix does not change \( A \):
- \( AI = IA = A \).
Matrix Multiplication
Matrix multiplication is a fundamental operation where two matrices are combined to yield a new matrix. The key condition for multiplication is that the number of columns in the first matrix must equal the number of rows in the second. Multiplication is not commutative in general, meaning \( AB \) does not necessarily equal \( BA \).
- Each element of the resultant matrix is the sum of products of corresponding elements from the row of the first matrix and the column of the second matrix.
Other exercises in this chapter
Problem 27
Solve each system of equations using matrices. Use Gaussian elimination with back-substitution or Gauss-Jordan elimination. $$ \left\\{\begin{array}{l} {x+y+z=4
View solution Problem 27
Evaluate each determinant. $$\left|\begin{array}{rrr}{1} & {1} & {1} \\\\{2} & {2} & {2} \\\\{-3} & {4} & {-5}\end{array}\right|$$
View solution Problem 28
Find (if possible) the following matrices: a. \(A B\) b. \(B A\) $$ A=\left[\begin{array}{rr} {3} & {-2} \\ {1} & {5} \end{array}\right], \quad B=\left[\begin{a
View solution Problem 28
Solve each system of equations using matrices. Use Gaussian elimination with back-substitution or Gauss-Jordan elimination. $$ \left\\{\begin{aligned} 3 x+y-z &
View solution