Problem 27
Question
Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Focus \(F(-8,0)\)
Step-by-Step Solution
Verified Answer
The equation of the parabola is \(x = -\frac{1}{32}y^2\).
1Step 1: Understand the Parabola Definition
A parabola with a vertex at the origin and focus at \((-8, 0)\) is a horizontal parabola because the focus has an x-coordinate other than zero, while the y-coordinate is zero.
2Step 2: Use the Standard Form of the Parabola Equation
For a parabola with a vertex at the origin \((0, 0)\) and a horizontal orientation, the standard form is \(x = ay^2\).
3Step 3: Determine the Distance to the Focus
For a horizontal parabola, the distance \(p\) between the vertex and the focus is the absolute value of the focus's x-coordinate, \(p = 8\) since the focus is \((-8,0)\). However, considering the direction to the focus, we use \(p = -8\).
4Step 4: Relate Focus Distance to Coefficient
The equation in vertex form is \(x = \frac{1}{4p}y^2\). Substitute \(p = -8\) to find \(a = \frac{1}{4(-8)} = -\frac{1}{32}\).
5Step 5: Write the Final Equation
Substitute \(a = -\frac{1}{32}\) into the vertex form equation: \(x = -\frac{1}{32}y^2\). This is the equation of the parabola with a focus at \((-8, 0)\) and vertex at the origin.
Key Concepts
Vertex Form of a ParabolaFocus and Directrix of a ParabolaUnderstanding Horizontal Parabolas
Vertex Form of a Parabola
The vertex form of a parabola is a handy way to express the quadratic equation of a parabola. For a parabola with a vertex at the origin \(0, 0\), this form simplifies things greatly.The vertex form for a parabola that opens horizontally is given by the equation:\[x = a(y - k)^2 + h\]Here, \((h, k)\) is the vertex of the parabola. With the vertex at the origin, \(h = 0\) and \(k = 0\), so the equation becomes:\[x = ay^2\]The parameter \(a\) determines the shape and direction of the parabola.- If \(a\) is positive, the parabola opens to the right.- If \(a\) is negative, it opens to the left.Understanding the vertex form helps in easily identifying key features of the parabola, such as its vertex and the direction it opens.
Focus and Directrix of a Parabola
The focus and directrix are essential geometric entities that help in defining a parabola.### Role of the FocusThe focus of a parabola is a fixed point on its interior. For a horizontal parabola with a vertex at the origin \(0,0\) and a focus at \((-8, 0)\), the parabola opens horizontally and curves around this focus.- The focus is used to determine the parabola's orientation and shape.### Role of the DirectrixOpposite to the focus, the directrix of a parabola is a line.- For a horizontal parabola, it is vertical. The vertex is exactly halfway between the focus and the directrix.- In our case, since the focus is \((-8, 0)\), the directrix is the vertical line \((x = 8)\).The parabola is defined in such a way that for any point on the parabola, the distance to the focus is equal to the distance to the directrix.
Understanding Horizontal Parabolas
Horizontal parabolas are a specific orientation of parabolas. Unlike the more common vertical parabolas that open up or down, these parabolas open left or right.### Characteristics- ** Vertex **: The starting point is typically at the origin \(0, 0\) which simplifies equations.- ** Direction **: The orientation (left or right) depends on the sign of \(a\) in the equation \(x = ay^2\).### Equation of Horizontal ParabolasFor a horizontal parabola with a vertex at the origin, the equation takes the form:- \(x = ay^2\)Where:- \(a = \text{positive}\) means the parabola opens to the right.- \(a = \text{negative}\) means it opens to the left, like in our exercise where \(a = -\frac{1}{32}\).Focusing on these key elements helps simplify the understanding of how horizontal parabolas behave, making it easier to graph and comprehend their properties.
Other exercises in this chapter
Problem 27
Complete the square to determine whether the equation represents an ellipse, a parabola, a hyperbola, or a degenerate conic. If the graph is an ellipse, find th
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Use a graphing device to graph the ellipse. $$ x^{2}+2 y^{2}=8 $$
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