Problem 27
Question
Fill in each blank with the appropriate response. (Remember that the vertical stretch or shrink factor is positive.) The graph of \(y=-4 x^{2}\) can be obtained from the graph of \(y=x^{2}\) by vertically stretching by applying a factor of_______________ and reflecting across the _________-axis.
Step-by-Step Solution
Verified Answer
Stretch by a factor of 4 and reflect across the x-axis.
1Step 1: Identify the Original Function
The original function given is \( y = x^2 \), which is a standard parabola opening upwards.
2Step 2: Transform the Vertical Stretch or Shrink
The function to transform into is \( y = -4x^2 \). Here, the coefficient of \( x^2 \) is \(-4\). The absolute value \(|-4| = 4\) indicates a vertical stretch by a factor of 4 from the original function \( y = x^2 \).
3Step 3: Identify the Reflection Axis
The negative sign in \( y = -4x^2 \) indicates that the graph is reflected across the x-axis, as compared to the original \( y = x^2 \), which opens upwards.
Key Concepts
Vertical StretchReflection Across AxisQuadratic Function
Vertical Stretch
A vertical stretch modifies the graph of a function by expanding it away from the x-axis, making it taller and narrower. In this scenario, we have the function transformation from \(y = x^2\) to \(y = -4x^2\). The coefficient in front of \(x^2\) in \(y = -4x^2\) is \(-4\), where we consider only the absolute value to determine the stretching factor. This means that the graph stretches vertically by a factor of 4.
To better understand, think of vertical stretch as multiplying the original y-values by a positive number greater than 1. In our case:
To better understand, think of vertical stretch as multiplying the original y-values by a positive number greater than 1. In our case:
- The original y-value from \(y = x^2\) is multiplied by 4.
- Every point of the parabola is pulled 4 times further away from the x-axis than it was in the original function.
Reflection Across Axis
A reflection across an axis involves flipping the graph over a specific axis. In our example, the transformation from \(y = x^2\) to \(y = -4x^2\) includes a reflection across the x-axis. The reflection is indicated by the negative sign in front of the \(x^2\) term.To picture this, imagine holding the graph at the x-axis and flipping it over like a book page from top to bottom. The once upward opening parabola now flips to open downwards.Here’s how it works:
- The original parabola \(y = x^2\) which opens upwards, has all its positive y-values turned negative.
- For every point on the original curve, the y-coordinate becomes its opposite (e.g., +3 becomes -3).
Quadratic Function
Quadratic functions are polynomial functions of degree 2, commonly expressed in the form \( y = ax^2 + bx + c \). They produce parabolic graphs, which resemble a U-shape.The most basic quadratic function is \( y = x^2 \). It creates a parabola that opens upwards centered at the origin, which provides a starting point for many transformations.Key features of a quadratic function include:
- The vertex, which is the highest or lowest point on the graph. In \( y = x^2 \), the vertex is at (0,0).
- The axis of symmetry, which is a vertical line that passes through the vertex, keeping the parabola symmetric. For \( y = x^2 \), this line is x = 0.
- The direction of opening, which can be upwards if the coefficient of \(x^2\) is positive, or downwards if negative.
Other exercises in this chapter
Problem 27
For each pair of functions, (a) find \((f+g)(x),(f-g)(x),\) and \((f g)(x)\) (b) give the domains of the functions in part (a); (c) find \(\frac{f}{8}\) and giv
View solution Problem 27
Graph each function in the standard viewing window of your calculator, and trace from left to right along a representative portion of the specified interval. Th
View solution Problem 28
For each pair of functions, (a) find \((f+g)(x),(f-g)(x),\) and \((f g)(x)\) (b) give the domains of the functions in part (a); (c) find \(\frac{f}{8}\) and giv
View solution Problem 28
Graph each function in the standard viewing window of your calculator, and trace from left to right along a representative portion of the specified interval. Th
View solution