Problem 27
Question
Exercises \(19-28\) tell how many units and in what directions the graphs of the given equations are to be shifted. Give an equation for the shifted graph. Then sketch the original and shifted graphs together, labeling each graph with its equation. $$ y=1 / x \quad \text { Up } 1, \text { right } 1 $$
Step-by-Step Solution
Verified Answer
Shifted equation: \( y = \frac{1}{x-1} + 1 \).
1Step 1: Break Down the Instructions
We need to shift the graph of the equation \( y = \frac{1}{x} \) up by 1 unit and to the right by 1 unit. Each of these transformations will affect the equation differently. Our task is to find the new equation after these shifts.
2Step 2: Horizontal Shift (Right)
To shift a graph to the right by 1 unit, we replace every "\( x \)" in the equation with "\( x - 1 \)". Thus, the equation \( y = \frac{1}{x} \) becomes \( y = \frac{1}{x-1} \) after this transformation.
3Step 3: Vertical Shift (Up)
To shift a graph up by 1 unit, we add 1 to the entire function. After shifting right, we have \( y = \frac{1}{x-1} \). Therefore, the equation becomes \( y = \frac{1}{x-1} + 1 \) after shifting vertically.
4Step 4: Write the Final Shifted Equation
The final equation after shifting \( y = \frac{1}{x} \) right by 1 and up by 1 is \( y = \frac{1}{x-1} + 1 \).
5Step 5: Sketch the Original and Shifted Graphs
Draw the graph of the original equation \( y = \frac{1}{x} \), a hyperbola with vertical and horizontal asymptotes along the axes. Label this graph. Next, draw the shifted graph using the equation \( y = \frac{1}{x-1} + 1 \), shifted one unit right and up, so the asymptotes are at \( x = 1 \) and \( y = 1 \), respectively. Label this graph as well.
Key Concepts
Horizontal ShiftVertical ShiftAsymptotesRational Functions
Horizontal Shift
Graph transformations involve adjusting a graph's position along the coordinate plane without altering its shape. One key transformation is the horizontal shift, which moves the graph left or right. To perform a horizontal shift, you adjust the variable within the function. For example, if you have the function \( y = \frac{1}{x} \), moving it right by 1 unit changes the input as follows:
- Replace \( x \) with \( x - 1 \) to move right.
- Resulting equation becomes \( y = \frac{1}{x-1} \).
Vertical Shift
Vertical shifts adjust a graph's position up or down on the coordinate plane. For a vertical shift, you change the function’s output. This transformation adds or subtracts a constant from the entire function. Using \( y = \frac{1}{x-1} \) from our previous horizontal shift:
- Add 1 to shift the graph up by 1 unit.
- The equation becomes \( y = \frac{1}{x-1} + 1 \).
Asymptotes
Asymptotes are lines that a graph approaches but never actually touches. They are crucial in analyzing rational functions, such as \( y = \frac{1}{x} \). In the original function,
- Vertical asymptote: \( x = 0 \)
- Horizontal asymptote: \( y = 0 \)
- New vertical asymptote: \( x = 1 \)
- New horizontal asymptote: \( y = 1 \)
Rational Functions
Rational functions are functions that involve a ratio of polynomials. Often seen as \( y = \frac{p(x)}{q(x)} \), they can have unique features like asymptotes and undefined points. The function \( y = \frac{1}{x} \) is a classic example, where the denominator defines the vertical asymptote. Transformations, like shifts, modify these without changing the function's rational nature. Recognizing rational functions’ structure helps in predicting and visualizing how graph transformations, such as horizontal and vertical shifts, impact their visuals and behavior.
Other exercises in this chapter
Problem 26
In Exercises 17–30, write an equation for each line described. Has \(y\) -intercept \(-6\) and \(x\) -intercept 2
View solution Problem 26
Solve the inequalities in Exercises \(19-34,\) expressing the solution sets as intervals or unions of intervals. Also, show each solution set on the real line.
View solution Problem 27
In Exercises 5–30, determine an appropriate viewing window for the given function and use it to display its graph. $$ y=\cos \left(\frac{x}{50}\right) $$
View solution Problem 27
a. Graph \(y=\cos x\) and \(y=\sec x\) together for \(-3 \pi / 2 \leq x\) \(\leq 3 \pi / 2\) . Comment on the behavior of sec \(x\) in relation to the signs and
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