Problem 27
Question
Evaluate the function for the given value of x. $$ y=\sqrt{3 x-5} ; 7 $$
Step-by-Step Solution
Verified Answer
The value for \(y\) when \(x = 7\) is 4.
1Step 1: Substitute the Value
Begin by substituting \(x = 7\) into the equation. This gives: \(y=\sqrt{3*7-5}\).
2Step 2: Simplify the Expression
Next, simplify the expression inside the square root. This gives: \(y=\sqrt{21-5}\).
3Step 3: Calculate the Result
Further simplify the expression. This results into: \(y=\sqrt{16}\).
4Step 4: Find the Square Root
Finally, find the square root to get the value for \(y\), which gives: \(y=4\).
Key Concepts
SubstitutionSimplifying ExpressionsSquare RootsAlgebraic Expressions
Substitution
Substitution is a key step in math problems involving functions or equations. It's the process of replacing a variable with a given number or expression. In our exercise, we have the function \( y=\sqrt{3x-5} \) and we need to evaluate it for \( x = 7 \).
To do this, you take the value of \( x \) that is provided (which is 7) and substitute it directly into the equation wherever \( x \) appears.
Here's how the substitution step looked in our problem:
To do this, you take the value of \( x \) that is provided (which is 7) and substitute it directly into the equation wherever \( x \) appears.
Here's how the substitution step looked in our problem:
- Start with the original equation: \( y=\sqrt{3x-5} \)
- Replace \( x \) with 7: \( y=\sqrt{3(7)-5} \)
Simplifying Expressions
Simplifying expressions is about reducing them into their simplest form. This often involves performing arithmetic operations or combining like terms in an equation.
In the given exercise, after substituting \( x = 7 \) into the equation, we have the expression \( \sqrt{3 \times 7 - 5} \).
Now let's simplify this:
In the given exercise, after substituting \( x = 7 \) into the equation, we have the expression \( \sqrt{3 \times 7 - 5} \).
Now let's simplify this:
- First, calculate \( 3 \times 7 = 21 \)
- Then solve the subtraction: \( 21 - 5 = 16 \)
- Now the expression is reduced to \( \sqrt{16} \)
Square Roots
When you encounter square roots in math, you're dealing with a value that, when multiplied by itself, gives the original number under the square root sign.
In our example, we reached \( \sqrt{16} \) through substitution and simplification.
The task now is to find the square root of 16.
In our example, we reached \( \sqrt{16} \) through substitution and simplification.
The task now is to find the square root of 16.
- The square root of 16 is 4 because \( 4 \times 4 = 16 \)
Algebraic Expressions
Algebraic expressions involve variables, coefficients, and operations (like addition and multiplication). They're central to algebra and help represent quantities symbolically.
The function \( y=\sqrt{3x-5} \) in this exercise is an algebraic expression that includes a square root sign and a linear expression inside it.
Algebraic expressions can often be manipulated by using methods like substitution and simplification to find desired values.
The function \( y=\sqrt{3x-5} \) in this exercise is an algebraic expression that includes a square root sign and a linear expression inside it.
Algebraic expressions can often be manipulated by using methods like substitution and simplification to find desired values.
- Identify and understand each component: variables, coefficients, and constants.
- Apply operations correctly to simplify the expression.
- Use substitution to evaluate the expression at specific values.
Other exercises in this chapter
Problem 26
Simplify the expression. $$ \sqrt{16} \cdot \sqrt{4} $$
View solution Problem 26
Solve the equation. $$ \sqrt{9-x}-10=14 $$
View solution Problem 27
Solve the percent problem. (Lesson 3.9) 100 is \(1 \%\) of what number?
View solution Problem 27
Find the midpoint of the line segment connecting the given points. Then show that the midpoint is the same distance from each point. \((5,1),(1,-5)\)
View solution