Problem 27
Question
Evaluate each factorial expression. $$\frac{(n+2) !}{n !}$$
Step-by-Step Solution
Verified Answer
The simplified form of \(\frac{(n+2) !}{n !}\) is \((n+2) \cdot (n+1)\)
1Step 1: Expand the Factorial in the Numerator
The factorial operation expands a number into the product of all integers from one to that number. Expanding (n+2)! We can write it as \((n+2) \cdot (n+1) \cdot n!\)
2Step 2: Simplify the Expression
The expression now becomes \(\frac{(n+2) \cdot (n+1) \cdot n!}{n !}\). Noticing that there is a \(n!\) both in the numerator and the denominator, these will cancel out.
3Step 3: Final Simplification
After simplification, the final expression is \((n+2) \cdot (n+1)\). This is a simplified form of the given factorial expression.
Other exercises in this chapter
Problem 27
In Exercises 25-34, use mathematical induction to prove that each statement is true for every positive integer \(n.\) 6 is a factor of \(n(n+1)(n+2)\).
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A state lottery is designed so that a player chooses six numbers from 1 to 30 on one lottery ticket. What is the probability that a player with one lottery tick
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Evaluate each expression. $$ \frac{_{5} C_{1} \cdot_{7} C_{2}}{_{12} C_{3}} $$
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