Problem 27
Question
Estimate the value of the radical accurate to four decimal places by using three iterations of Newton's method to solve the equation \(f(x)=0\) with initial estimate \(x_{0}\). \(\sqrt[4]{20} ; \quad f(x)=x^{4}-20 ; x_{0}=2.1\)
Step-by-Step Solution
Verified Answer
After three iterations of Newton's method with the initial estimate \(x_0 = 2.1\), we have approximated the fourth root of 20 accurate to four decimal places as follows: \(\sqrt[4]{20} \approx x_3 = 2.0241\).
1Step 1: Derive Newton's Method Formula
To use Newton's method, we need to find the iterative formula. The general formula for the method is given by:
\[x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}\]
For the given function \(f(x) = x^4 - 20\), we first need to find its derivative, \(f'(x)\).
The derivative of \(f(x)\) is:
\[f'(x) = \frac{d}{dx}(x^4 - 20) = 4x^3\]
Now we have:
\[x_{n+1} = x_n - \frac{x_n^4 - 20}{4x_n^3}\]
This is the formula we will use for our Newton's method iterations.
2Step 2: Perform the First Iteration (n = 0)
Plug in the given initial estimate, \(x_0 = 2.1\), into the formula:
\[x_{1} = 2.1 - \frac{2.1^4 - 20}{4(2.1)^3}\]
Compute the value of \(x_1\):
\[x_{1} \approx 2.0349\]
3Step 3: Perform the Second Iteration (n = 1)
Plug in the updated value of \(x_1 \approx 2.0349\) into the formula:
\[x_{2} = 2.0349 - \frac{2.0349^4 - 20}{4(2.0349)^3}\]
Compute the value of \(x_2\):
\[x_{2} \approx 2.0246\]
4Step 4: Perform the Third Iteration (n = 2)
Plug in the updated value of \(x_2 \approx 2.0246\) into the formula:
\[x_{3} = 2.0246 - \frac{2.0246^4 - 20}{4(2.0246)^3}\]
Compute the value of \(x_3\):
\[x_{3} \approx 2.0241\]
After three iterations of Newton's method, we have approximated the radical accurate to four decimal places as follows:
\[\sqrt[4]{20} \approx x_3 = 2.0241\]
Key Concepts
Numerical ApproximationDerivativesRoot Finding Algorithms
Numerical Approximation
Numerical approximation is a crucial technique in mathematics and engineering when finding exact solutions analytically is challenging or impossible. It enables us to estimate solutions with a high degree of accuracy through iterative processes.
Newton's method is one of the most popular numerical approximation methods. It allows for the estimation of roots of a function by successively refining guesses until the results are sufficiently precise.
With initial estimates like the one given in the exercise (\(x_0 = 2.1\)), you perform several iterations to improve the approximation of \(\sqrt[4]{20}\). Each iteration brings us closer to the actual root, aiming for the desired level of precision, such as four decimal places in this example. The power of numerical approximation lies in its ability to handle complex calculations that might not be practically solvable through direct algebraic means. It transforms unsolvable analytical circumstances into highly manageable computational tasks.
Newton's method is one of the most popular numerical approximation methods. It allows for the estimation of roots of a function by successively refining guesses until the results are sufficiently precise.
With initial estimates like the one given in the exercise (\(x_0 = 2.1\)), you perform several iterations to improve the approximation of \(\sqrt[4]{20}\). Each iteration brings us closer to the actual root, aiming for the desired level of precision, such as four decimal places in this example. The power of numerical approximation lies in its ability to handle complex calculations that might not be practically solvable through direct algebraic means. It transforms unsolvable analytical circumstances into highly manageable computational tasks.
Derivatives
Derivatives represent a key concept in calculus often connecting to rates of change and slopes of curves. In Newton's method, derivatives are fundamental as they define the slope of the tangent line at any given point on a function.
The formula for Newton's method relies heavily on the derivative of the function to make effective approximations. The derivative used in the exercise is given by \(f'(x) = 4x^3\), which is the slope of the tangent to the curve \(f(x) = x^4 - 20\).
The formula for Newton's method relies heavily on the derivative of the function to make effective approximations. The derivative used in the exercise is given by \(f'(x) = 4x^3\), which is the slope of the tangent to the curve \(f(x) = x^4 - 20\).
- The knowledge of derivatives allows us to adjust our estimation more accurately with each iteration.
- Derivatives help the method "home in" on the actual root by guiding the approximations towards the point where the tangent crosses the x-axis.
Root Finding Algorithms
Root finding algorithms are essential in solving equations where the goal is to find the value of \(x\) such that \(f(x) = 0\). These algorithms vary in complexity and efficiency, each suitable for different types of functions or desired levels of precision.
Newton's method falls under this category and is especially powerful for polynomial equations, like the one we encounter in our exercise. It takes advantage of both the function and its derivative to iteratively close in on a root. Some key characteristics of Newton's method as a root-finding algorithm include:
Newton's method falls under this category and is especially powerful for polynomial equations, like the one we encounter in our exercise. It takes advantage of both the function and its derivative to iteratively close in on a root. Some key characteristics of Newton's method as a root-finding algorithm include:
- Fast convergence near the root, especially when starting close to actual roots.
- Requires calculation of derivatives, making it potent but dependent on differentiable functions.
- Depending on the initial guess, convergence is not guaranteed and may require a sensible choice of starting points.
Other exercises in this chapter
Problem 26
Determine where the graph of the function is concave upward and where it is concave downward. Also, find all inflection points of the function. $$ g(x)=\cos ^{2
View solution Problem 26
In Exercises \(25-40\), find the critical number \((s)\), if any, of the function. $$ g(x)=4-3 x $$
View solution Problem 27
In Exercises \(5-38\), sketch the graph of the function using the curve- sketching guidelines on page \(348 .\) $$ f(x)=\frac{1}{1-\cos x}, \quad-2 \pi
View solution Problem 27
evaluate the limit using l'Hôpital's Rule if appropriate. $$ \lim _{x \rightarrow 0} \frac{\sin ^{-1}(2 x)}{x} $$
View solution