Problem 27
Question
Determine whether the sequence converges or diverges. If it converges, find the limit. \( a_n = 3^n 7^{-n} \)
Step-by-Step Solution
Verified Answer
The sequence converges, and its limit is 0.
1Step 1: Express the Sequence
We start with the given sequence: \( a_n = 3^n 7^{-n} \). This can be rewritten by combining the exponents: \( a_n = \left( \frac{3}{7} \right)^n \).
2Step 2: Identify the Base of the Exponential
The sequence \( a_n = \left( \frac{3}{7} \right)^n \) is an exponential sequence with a base of \( \frac{3}{7} \). This base is less than 1, which is key for evaluating convergence.
3Step 3: Determine Convergence
Since the base \( \frac{3}{7} \) is between 0 and 1, the sequence \( a_n = \left( \frac{3}{7} \right)^n \) converges to 0 as \( n \to \infty \). This is a known property of exponential sequences with bases in this range.
4Step 4: State the Limit
Therefore, the limit of the sequence as \( n \to \infty \) is 0, which confirms that the sequence converges to 0.
Key Concepts
Exponential SequencesConvergence CriteriaLimits of Sequences
Exponential Sequences
An exponential sequence is a type of sequence where each term is a constant raised to the power of its position in the sequence. In mathematical terms, this is described by the expression \( a_n = a^n \), where \( a \) is a constant. For our exercise example, the initiated sequence \( a_n = 3^n 7^{-n} \) can be simplified by recognizing it as \( a_n = \left( \frac{3}{7} \right)^n \) once the exponents are combined. This indicates that the sequence is exponential with a base \( \frac{3}{7} \).
Exponential sequences are widely recognized for their predictable behavior:
Exponential sequences are widely recognized for their predictable behavior:
- If the base \( |a| > 1 \), the sequence tends to diverge, meaning it will grow larger and larger without approaching any particular value.
- If the base \( |a| < 1 \), the sequence converges toward zero. This occurs because exponential growth becomes exponential decay when the base is a fraction less than one.
Convergence Criteria
To determine if a sequence converges, you need to evaluate the ultimate behavior of its terms as they approach infinity. For exponential sequences, convergence often hinges on the value of the base:
Another aspect of convergence criteria is the ability to ascertain a limit, which acts as a confirmation of the sequence's destination in terms of value as \( n \to \infty \). Keep in mind, criteria differ slightly depending on the type of sequence, making it essential to recognize the sequence type first.
- If the base is greater than one, the sequence will diverge.
- When the base is less than one, you can expect the sequence to shrink towards zero, which indicates convergence.
Another aspect of convergence criteria is the ability to ascertain a limit, which acts as a confirmation of the sequence's destination in terms of value as \( n \to \infty \). Keep in mind, criteria differ slightly depending on the type of sequence, making it essential to recognize the sequence type first.
Limits of Sequences
The limit of a sequence is a pivotal concept which tells us the value that the sequence tends toward as the number of terms becomes infinitely large. The key idea is to monitor whether a sequence reaches a particular value, no matter how large the term number becomes. Limits help validate convergence.
For our specific sequence \( a_n = \left( \frac{3}{7} \right)^n \):
For our specific sequence \( a_n = \left( \frac{3}{7} \right)^n \):
- It approaches the limit of \( 0 \) as \( n \to \infty \), because repeatedly multiplying fractions less than one results in progressively smaller and smaller values that zero in on zero.
- Practically speaking, if after numerous iterations the terms of your sequence remain extremely close to a single value or within a permissible margin (often acknowledged as an adequate proximity), you can assert a limit has been achieved.
Other exercises in this chapter
Problem 27
Determine whether the series converges or diverges. \( \displaystyle \sum_{n = 1}^{\infty} \left( 1 + \frac {1}{n} \right)^2 e^{-n} \)
View solution Problem 27
Explain why the Integral Test can't be used to determine whether the series is convergent. \( \displaystyle \sum_{n = 1}^{\infty} \frac {\cos \pi n}{\sqrt n} \)
View solution Problem 27
Use the Alternating Series Estimation Theorem or Taylor's Inequality to estimate the range of values of \( x \) for which the given approximation is accurate to
View solution Problem 27
Determine whether the series is convergent or divergent. If it is convergent, find its sum. \( \frac {1}{3} + \frac {1}{6} + \frac {1}{9} + \frac {1}{12} + \fra
View solution