Problem 27
Question
Convert each of the given pairs of rectangular coordinates to a pair of polar coordinates ( \(r, \theta\) ) with \(r>0\) and \(0 \leq \theta<2 \pi\). $$(1, \sqrt{3})$$
Step-by-Step Solution
Verified Answer
The pair of polar coordinates equivalent to the rectangular coordinates (1, \(\sqrt{3}\)) is (2, 2\(\pi\)/3).
1Step 1: Apply the formula for 'r'
First, calculate the radius using the formula \(r = \sqrt{x^2 + y^2}\). In this case, x=1 and y=\(\sqrt{3}\). So, \(r = \sqrt{1^2 + (\sqrt{3})^2} = 2\).
2Step 2: Apply the formula for '\(\theta\)'
Next, find the angle using the formula \(\theta = \arctan(y/x)\). However, since \(y > x\) in the given pair of coordinates, in the second quadrant \(\theta = \pi - \arctan(y/x)\). So, \(\theta = \pi - \arctan(\sqrt{3}/1) = \pi - \pi/3 = 2\pi/3\).
3Step 3: Write the converted coordinates
The pair of polar coordinates corresponding to the given rectangular coordinates is therefore (r, \(\theta\)) = (2, 2\(\pi\)/3).
Key Concepts
Rectangular CoordinatesTrigonometryCoordinate Conversion
Rectangular Coordinates
Understanding rectangular coordinates is essential when dealing with points represented on a plane using two numbers. These numbers - represented as
Together, these coordinates define a unique point in the two-dimensional plane. Rectangular coordinates fit perfectly in a Cartesian system, allowing us to use straight grid lines to locate points based on these x and y values.
- x: The horizontal distance from the origin.
- y: The vertical distance from the origin.
Together, these coordinates define a unique point in the two-dimensional plane. Rectangular coordinates fit perfectly in a Cartesian system, allowing us to use straight grid lines to locate points based on these x and y values.
Trigonometry
Trigonometry is a branch of mathematics focusing on relationships between angles and sides of triangles. It's critical in coordinate conversion.
Particularly, trigonometric functions like sine, cosine, and tangent become significant tools. To convert rectangular coordinates to polar, we use:- The tangent function: \[\theta = \arctan\left(\frac{y}{x}\right)\]This formula helps determine the angle \(\theta\) between the positive x-axis and the line connecting the point to the origin.
To find \(r\), the hypotenuse or radius, we use
Particularly, trigonometric functions like sine, cosine, and tangent become significant tools. To convert rectangular coordinates to polar, we use:- The tangent function: \[\theta = \arctan\left(\frac{y}{x}\right)\]This formula helps determine the angle \(\theta\) between the positive x-axis and the line connecting the point to the origin.
To find \(r\), the hypotenuse or radius, we use
- Pythagoras' theorem in a different form: \( r = \sqrt{x^2 + y^2} \).
- This ensures the point's total distance from the origin is accurately calculated regardless of direction.
Coordinate Conversion
Converting coordinates involves changing from rectangular (x, y) to polar coordinates \((r, \theta)\).
The goal is to express the same point either relative to axes or in terms of distance and angle from the origin. This conversion is useful because it provides a different perspective that can simplify analysis or calculations in certain contexts, like physics or engineering.
Here’s how the conversion works:
The goal is to express the same point either relative to axes or in terms of distance and angle from the origin. This conversion is useful because it provides a different perspective that can simplify analysis or calculations in certain contexts, like physics or engineering.
Here’s how the conversion works:
- Step 1: Determine \(r\) using the formula: \[r = \sqrt{x^2 + y^2}\]
- Step 2: Calculate \(\theta\), the angle: \[\theta = \arctan\left(\frac{y}{x}\right)\] Consider the quadrant if necessary, like in this example where \(\theta = \pi - \arctan(\frac{\sqrt{3}}{1})\).
- Final Step: Express the result as polar coordinates \((r, \theta)\).
Other exercises in this chapter
Problem 27
Determine whether the given pairs of vectors are orthogonal. $$\mathbf{v}=\langle 2,-3\rangle, \mathbf{w}=\langle-6,4\rangle$$
View solution Problem 27
If at least one triangle with the given characteristics exists, solve the triangle; otherwise, state that there is no solution. If there are treo solutions, giv
View solution Problem 28
Find the magnitude and direction of each of the given vectors. Express the direction as an angle \(\theta\) in standard position, where \(0^{\circ} \leq \theta
View solution Problem 28
Multiply or divide as indicated, and leave the answer in trigonometric form. $$\frac{6\left(\cos \frac{\pi}{12}+i \sin \frac{\pi}{12}\right)}{3\left(\cos \frac{
View solution