Problem 27
Question
Analyzing an \(L \cdot R-C\) Circuit. You have a \(200-\Omega\) resistor, a \(0.400-\mathrm{H}\) inductor, a \(5.00-\mu \mathrm{F}\) capacitor, and a variable-frequency ac source with an amplitude of 3.00 \(\mathrm{V} .\) You connect all four elements together to form a series circuit. (a) At what frequency will the current in the circuit be greatest? What will be the current amplitude at this frequency? (b) What will be the current amplitude at an angular frequency of 400 \(\mathrm{rad} / \mathrm{s} ?\) At this frequency, will the source voltage lead or lag the current?
Step-by-Step Solution
Verified Answer
(a) Maximum current at 356 Hz with amplitude 0.015 A. (b) At 400 rad/s, current amplitude is 0.011 A; voltage leads current.
1Step 1: Understanding Resonance
In a series LCR circuit, the current is greatest when the impedance is minimum. This occurs at the resonant frequency. The resonant frequency \( f_0 \) is calculated by the formula \( f_0 = \frac{1}{2\pi\sqrt{LC}} \), where \( L \) is the inductance and \( C \) is the capacitance.
2Step 2: Calculating Resonant Frequency
Given \( L = 0.400 \) H and \( C = 5.00 \times 10^{-6} \) F, substitute these values into the formula: \[ f_0 = \frac{1}{2\pi\sqrt{0.400 \times 5.00 \times 10^{-6}}} \]Calculate \( f_0 \) to find the resonant frequency for maximum current.
3Step 3: Calculating Current Amplitude at Resonance
At resonance, the impedance is just the resistance \( R \), which is \( 200 \) \( \Omega \). The current amplitude \( I_0 \) at resonance is calculated by \( I_0 = \frac{V}{R} \), where \( V = 3.00 \) V is the amplitude of the source voltage. Calculate \( I_0 \).
4Step 4: Analyzing the Circuit at 400 rad/s
The angular frequency \( \omega = 400 \) rad/s. Calculate the impedance \( Z \) using the formula: \[ Z = \sqrt{R^2 + (\omega L - \frac{1}{\omega C})^2} \]Substitute \( R = 200 \) \( \Omega \), \( \omega = 400 \) rad/s, \( L = 0.400 \) H, and \( C = 5.00 \times 10^{-6} \) F into the formula to find \( Z \).
5Step 5: Calculating Current Amplitude at 400 rad/s
The current amplitude \( I \) is given by \( I = \frac{V}{Z} \). Using \( V = 3.00 \) V and the \( Z \) from Step 4, calculate the new current amplitude at \( \omega = 400 \) rad/s.
6Step 6: Determine Phase Difference at 400 rad/s
The phase angle \( \phi \) is determined by \( \tan \phi = \frac{\omega L - \frac{1}{\omega C}}{R} \). If \( \phi > 0 \), the voltage leads the current; if \( \phi < 0 \), the voltage lags the current. Calculate \( \phi \) using the given and calculated values.
Key Concepts
Resonant FrequencyImpedance CalculationPhase DifferenceCurrent AmplitudeAngular Frequency
Resonant Frequency
In an RLC circuit, the resonant frequency is crucial because it represents the frequency at which the circuit's impedance is minimized and current is maximized. Essentially, it's the frequency at which the reactive effects of the inductor and capacitor cancel each other out. This balance allows the circuit to operate more efficiently, with minimal energy loss.
To determine the resonant frequency, we use the formula:
\[ f_0 = \frac{1}{2\pi\sqrt{LC}} \]Where:
To determine the resonant frequency, we use the formula:
\[ f_0 = \frac{1}{2\pi\sqrt{LC}} \]Where:
- \( L \) is the inductance (in henries, H)
- \( C \) is the capacitance (in farads, F)
Impedance Calculation
Impedance in an RLC circuit is the total opposition to the flow of alternating current, combining both resistance and reactance into a single value. It dictates how much current flows for a given voltage.
The formula to calculate impedance \( Z \) is:
\[ Z = \sqrt{R^2 + (\omega L - \frac{1}{\omega C})^2} \]Where:
The formula to calculate impedance \( Z \) is:
\[ Z = \sqrt{R^2 + (\omega L - \frac{1}{\omega C})^2} \]Where:
- \( R \) is the resistance in ohms (\( \Omega \))
- \( \omega \) is the angular frequency in rad/s
- \( L \) is the inductance in henries
- \( C \) is the capacitance in farads
Phase Difference
Phase difference in an RLC circuit is the angular difference between the source voltage and the circuit current. This concept is crucial for understanding power delivery and efficiency in AC circuits.
The phase angle \( \phi \) can be determined using:
\[ \tan \phi = \frac{\omega L - \frac{1}{\omega C}}{R} \]
The phase angle \( \phi \) can be determined using:
\[ \tan \phi = \frac{\omega L - \frac{1}{\omega C}}{R} \]
- A positive \( \phi \) indicates that the source voltage leads the current.
- A negative \( \phi \) shows that the voltage lags behind the current.
Current Amplitude
Current amplitude refers to the maximum current that flows through an RLC circuit for a given voltage source. It varies with the frequency of the AC source due to the circuit's impedance changes.
To find the current amplitude \( I \) at resonance or any specific frequency, use:
\[ I = \frac{V}{Z} \]Where:
To find the current amplitude \( I \) at resonance or any specific frequency, use:
\[ I = \frac{V}{Z} \]Where:
- \( V \) is the amplitude of the supply voltage
- \( Z \) is the impedance of the whole circuit
Angular Frequency
Angular frequency \( \omega \) is an essential parameter in the analysis of RLC circuits, representing how quickly the sinusoidal source voltage oscillates. It is related to the frequency by the equation:
\[ \omega = 2\pi f \]Where \( f \) is the frequency in hertz (Hz).
\[ \omega = 2\pi f \]Where \( f \) is the frequency in hertz (Hz).
- It measures in radians per second (rad/s).
- This metric helps in determining the reactance of inductors and capacitors within the circuit.
Other exercises in this chapter
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