Problem 27
Question
A uniformly charged, thin ring has radius 15.0 cm and total charge \(+\)24.0 nC. An electron is placed on the ring's axis a distance 30.0 cm from the center of the ring and is constrained to stay on the axis of the ring. The electron is then released from rest. (a) Describe the subsequent motion of the electron. (b) Find the speed of the electron when it reaches the center of the ring.
Step-by-Step Solution
Verified Answer
The electron accelerates towards the center and gains speed; its speed is determined by converting initial potential energy into kinetic energy.
1Step 1: Understanding the Problem
We have a ring with radius 15.0 cm and charge +24.0 nC. An electron is placed on the axis, 30.0 cm away, and is released. We'll first describe how the electron moves and then find its speed when it reaches the center.
2Step 2: Electron's Motion Description
The electron is negatively charged, and the ring is positively charged. Thus, the electron is attracted towards the center of the ring. It will accelerate towards the ring because of the electrostatic force and travel down the axis to the center.
3Step 3: Equipotential Surface Analysis
Understand that on the axis of a charged ring, there is an electric potential resulting from the charges uniformly distributed along the ring. The electron, being on the axis, will be subjected to this potential, hence will convert its potential energy into kinetic energy as it moves toward the center.
4Step 4: Calculation of Electric Potential and Energy Conversion
The potential energy of the electron at the start can be calculated using the electric potential due to the ring at a point on its axis. Given the ring's charge \( Q = 24.0 \, \text{nC} = 24.0 \times 10^{-9} \, \text{C} \), radius \( a = 0.15 \, \text{m} \) and distance \( x = 0.30 \, \text{m} \), the electric potential \( V \) is: \[ V = \frac{kQ}{\sqrt{a^2 + x^2}} \]Where \( k = 8.99 \times 10^9 \, \text{Nm}^2\/\text{C}^2 \). Calculate \( V \) and then the initial potential energy \( U_i = -eV \) for an electron with charge \( e = -1.6 \times 10^{-19} \, \text{C} \).
5Step 5: Kinetic Energy at the Center
When the electron reaches the center of the ring, its potential energy becomes zero. Therefore, the initial potential energy converts into kinetic energy, given as:\[ K_e = U_i = \frac{1}{2} mv^2 \]Where \( m = 9.11 \times 10^{-31} \text{kg} \) is the mass of the electron, and \( v \) is the speed we need to find. Rearrange to find \( v \).
6Step 6: Calculation of Speed
Set the initial potential energy equal to the kinetic energy: \[ -eV = \frac{1}{2} mv^2 \]Solve for \( v \) using the calculated value of \( V \) from Step 4 and plug into the equation for kinetic energy to find \( v \):\[ v = \sqrt{\frac{2(-eV)}{m}} \]Compute this to determine the electron's speed when it reaches the center.
Key Concepts
ElectrostaticsKinetic EnergyElectrostatic ForceEquipotential Surface
Electrostatics
Electrostatics is the study of electric charges at rest, and it plays a crucial role in understanding how electric forces act over distances. In the scenario involving the charged ring and the electron, the principles of electrostatics help us predict the motion of the electron.
The charged ring creates an electric field in the space surrounding it due to its charge distribution. This field behaves like a map showing the direction and magnitude of the force experienced by a test charge, like our electron, placed in its vicinity.
The charged ring creates an electric field in the space surrounding it due to its charge distribution. This field behaves like a map showing the direction and magnitude of the force experienced by a test charge, like our electron, placed in its vicinity.
- Static charges create fields that influence other charges.
- These fields in turn exert electrostatic forces, attracting or repelling charges around them.
Kinetic Energy
Kinetic energy refers to the energy that a body or particle possesses due to its motion. In this exercise, as the electron moves towards the center of the ring, it converts potential energy into kinetic energy.
The conservation of energy principle suggests that the total energy remains constant. Initially, the electron has maximum potential energy owing to its position relative to the electric potential of the ring. As the electron accelerates towards the center:
The conservation of energy principle suggests that the total energy remains constant. Initially, the electron has maximum potential energy owing to its position relative to the electric potential of the ring. As the electron accelerates towards the center:
- The potential energy decreases because the electron is moving to a lower electric potential.
- This decrease in potential energy results in a corresponding increase in kinetic energy.
Electrostatic Force
The electrostatic force is the force exerted by a charged body on another due to their electric charges. It's one of the fundamental forces in physics, described by Coulomb's law. In this problem, this force is responsible for the acceleration of the electron towards the center of the ring.
Coulomb's Law tells us that the magnitude of the electrostatic force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between their centers. For our exercise:
Coulomb's Law tells us that the magnitude of the electrostatic force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between their centers. For our exercise:
- The electron is negatively charged and the ring is positively charged.
- The electrostatic force is attractive, working to pull the electron towards the ring.
Equipotential Surface
An equipotential surface is a surface where every point has the same electric potential. In this problem, because of the symmetry of the charged ring, an equipotential surface can be visualized along the axis of the ring where the electron lies.
When the electron moves along the axis, it travels through different equipotential levels, causing changes in its potential energy. However, while in complete contact with an equipotential surface, the electron's potential energy remains constant:
When the electron moves along the axis, it travels through different equipotential levels, causing changes in its potential energy. However, while in complete contact with an equipotential surface, the electron's potential energy remains constant:
- Movement perpendicular to an equipotential surface does not change the potential energy.
- Potential energy changes only when moving through different equipotential surfaces.
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