Problem 27
Question
(a) The following commands can be used in Mathematica: \(\mathbf{A}=\\{\\{4,2\\},\\{3,3\\}\\}\) \(\mathbf{c}=\\{\mathbf{c} 1, \mathbf{c} 2\\}\) \(\mathrm{m}=\) MatrixExp \([\mathrm{A} \mathrm{t}]\) sol = Expand [m.c] Collect[sol, \(\\{\mathrm{c} 1, \mathrm{c} 2\\}] /\) /MatrixForm The output gives $$\begin{array}{l} x(t)=c_{1}\left(\frac{2}{5} e^{t}+\frac{3}{5} e^{6 t}\right)+c_{2}\left(-\frac{2}{5} e^{t}+\frac{2}{5} e^{6 t}\right) \\ y(t)=c_{1}\left(-\frac{3}{5} e^{t}+\frac{3}{5} e^{6 t}\right)+c_{2}\left(\frac{3}{5} e^{t}+\frac{2}{5} e^{6 t}\right). \end{array}$$ The eigenvalues are 1 and 6 with corresponding eigenvectors $$\left(\begin{array}{r} -2 \\ 3 \end{array}\right) \quad \text { and } \quad\left(\begin{array}{l} 1 \\ 1 \end{array}\right),$$ so the solution of the system is $$\mathbf{X}(t)=b_{1}\left(\begin{array}{r} -2 \\ 3 \end{array}\right) e^{t}+b_{2}\left(\begin{array}{l} 1 \\ 1 \end{array}\right) e^{6 t}$$ or $$\begin{array}{l} x(t)=-2 b_{1} e^{t}+b_{2} e^{6 t} \\ y(t)=3 b_{1} e^{t}+b_{2} e^{6 t}. \end{array}$$ If we replace \(b_{1}\) with \(-\frac{1}{5} c_{1}+\frac{1}{5} c_{2}\) and \(b_{2}\) with \(\frac{3}{5} c_{1}+\frac{2}{5} c_{2},\) we obtain the solution found using the matrix exponential. (b) \(x(t)=c_{1} e^{-2 t} \cos t-\left(c_{1}+c_{2}\right) e^{-2 t} \sin t\) \(y(t)=c_{2} e^{-2 t} \cos t+\left(2 c_{1}+c_{2}\right) e^{-2 t} \sin t\)
Step-by-Step Solution
VerifiedKey Concepts
Eigenvectors
Let's use an example to clarify. Imagine a linear transformation represented by matrix \( \mathbf{A} \). When this transformation is applied to an eigenvector \( \mathbf{v} \), the result is a scaled version of \( \mathbf{v} \), but in the same direction.
For the matrix \( \mathbf{A} \) from the exercise, there are two eigenvectors given, \( \begin{pmatrix} -2 \ 3 \end{pmatrix} \) and \( \begin{pmatrix} 1 \ 1 \end{pmatrix} \), which stay on their span under matrix \( \mathbf{A} \). Such vectors are crucial when determining the makeup and transformations described by differential equations.
Eigenvalues
- In simpler terms, they tell you how a matrix modifies vectors on a particular line.
- In our problem, the matrix \( \mathbf{A} \) has eigenvalues 1 and 6.
Eigenvalues can be found by solving the characteristic equation, which is derived by setting the determinant of \( ( \mathbf{A} - \lambda \mathbf{I} ) \) to zero, where \( \lambda \) represents the eigenvalues and \( \mathbf{I} \) the identity matrix. These values are vital in many applications like solving differential equations, as they significantly simplify the process by showing long-term behaviors in systems.
Differential Equations
In the context of the exercise, these equations describe the rates of change of \( x(t) \) and \( y(t) \) over time.
- To solve them, we often use methods like eigenvectors and eigenvalues, as they can transform complex problems into manageable solutions.
- Here, the matrix exponential helps find a solution that describes how the state changes over time depending on initial conditions \( c_1 \) and \( c_2 \).
Mathematica Programming
In the exercise, several Mathematica commands were used:
- **MatrixExp** to calculate the matrix exponential necessary for evolving systems over time.
- **Expand** and **Collect** to manipulate and simplify expressions, making them easier to understand and apply.
Mastering Mathematica not only helps with solving problems quickly but also with visualizing complex mathematical concepts, offering a more tangible understanding of abstract mathematical ideas.