Problem 27
Question
A solid of density \(D\) is floating in a liquid of density \(d\). If \(v\) is the volume of solid submerged in the liquid and \(V\) is the total volume of the solid, then \(v / V\) is equal to (a) \(\frac{d}{P}\) (b) \(\frac{D}{d}\) (c) \(\frac{D}{(D+d)}\) (d) \(\frac{D+d}{D}\)
Step-by-Step Solution
Verified Answer
The fraction \( \frac{v}{V} \) is equal to option (b) \( \frac{D}{d} \).
1Step 1: Understanding Buoyancy
For a floating object, the weight of the object is balanced by the buoyancy force. This can be represented by the equation: \[ \text{Weight of solid} = \text{Buoyant force} \] The weight of the solid is given by \( D \times V \times g \) and the buoyant force is \( d \times v \times g \) where \( g \) is the acceleration due to gravity.
2Step 2: Setting the Equation for Equilibrium
At equilibrium, the weight of the solid (\( D \times V \times g \)) is equal to the buoyant force (\( d \times v \times g \)). Therefore, we can write:\[ D \times V \times g = d \times v \times g \] Since \( g \) is common, it cancels out, and we simplify the equation to:\[ D \times V = d \times v \]
3Step 3: Solving for Submerged Volume Fraction
To find the fraction of the volume of the solid that is submerged, we need to solve for \( \frac{v}{V} \). From the equation \( D \times V = d \times v \), dividing both sides by \( V \) and rearranging gives:\[ \frac{v}{V} = \frac{D}{d} \]
4Step 4: Conclusion and Answer
Comparing this result to the options provided, we see that the correct answer is option (b) \( \frac{D}{d} \). Therefore, the fraction of the solid submerged is equal to the ratio of the solid's density to the liquid's density.
Key Concepts
DensityFloating objectsVolume submergedEquilibrium in fluids
Density
Density is a crucial concept in understanding how objects interact with fluids. It is essentially how much mass an object has in a given volume. Mathematically, it can be expressed as:\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]Density determines whether an object will sink or float in a fluid:
- If an object's density is greater than the fluid's density, it will sink.
- If it's less, the object will float.
- If densities are equal, it will remain suspended in the fluid.
Floating objects
When an object is placed in a fluid and it floats, there are several forces in action. This scenario is a classic example of equilibrium in fluids. For any object to float:
- The buoyant force must equal the object's weight.
- This balance is what allows an object to float or remain partially submerged in a fluid.
Volume submerged
The volume of an object submerged in a fluid is directly linked to the object’s ability to float. This concept focuses on how much of the object's volume is below the surface of the fluid. For floating objects:
- The ratio \( \frac{v}{V} \) represents the fraction of the object submerged.
- This ratio is determined by comparing the density of the object to the fluid density.
- A higher fluid density leads to less volume being submerged.
Equilibrium in fluids
Equilibrium in fluids is achieved when the forces acting on an object within the fluid are balanced. This concept is essential when examining how objects float or sink. For an object floating in a fluid:
- The gravitational force acting downward must be balanced by the buoyant force pushing upwards.
- The key equation at play here is \( D \times V = d \times v \), where both terms represent the equilibrium of forces.
- This results in the object floating at a stable position, dictated by its density relative to the fluid.
Other exercises in this chapter
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