Problem 27
Question
(a) Estimate the value of $$\lim _{x \rightarrow 0} \frac{x}{\sqrt{1+3 x}-1}$$ by graphing the function \(f(x)=x /(\sqrt{1+3 x}-1)\) (b) Make a table of values of \(f(x)\) for \(x\) close to \(0,\) and guess the value of the limit. (c) Use the Limit Laws to prove that your guess is correct.
Step-by-Step Solution
Verified Answer
The estimated and verified limit is \( \frac{2}{3} \).
1Step 1: Understanding the Function
We begin by analyzing the function to estimate the limit: \( f(x) = \frac{x}{\sqrt{1+3x} - 1} \). This function is undefined at \( x = 0 \) as it leads to division by zero. Therefore, we'll seek ways to simplify or approach \( x = 0 \) using graphing and tabulation to estimate the limit.
2Step 2: Graphing the Function
We graph the function \( f(x) = \frac{x}{\sqrt{1+3x} - 1} \) around \( x = 0 \). Close examination of the graph as \( x \) approaches \( 0 \) from both the positive and negative sides suggests that the function stabilizes around a certain value. The graph shows that the function appears to approach the value \( \frac{2}{3} \).
3Step 3: Creating a Table of Values
We create a table with values of \( f(x) \) by choosing small positive and negative values of \( x \) around \( 0 \). For each chosen \( x \), compute \( f(x) \) :- \( x = 0.1 \), \( f(x) \approx 0.6667 \)- \( x = 0.01 \), \( f(x) \approx 0.6667 \)- \( x = -0.01 \), \( f(x) \approx 0.6667 \)- \( x = -0.1 \), \( f(x) \approx 0.6667 \)From these values, we deduce that \( \lim_{x \to 0} f(x) = \frac{2}{3} \).
4Step 4: Proving the Limit using Rationalization
To confirm via Limit Laws, we rationalize the expression \( \frac{x}{\sqrt{1+3x} - 1} \). Multiply numerator and denominator by the conjugate: \( \frac{x(\sqrt{1+3x} + 1)}{(\sqrt{1+3x}-1)(\sqrt{1+3x}+1)} = \frac{x(\sqrt{1+3x} + 1)}{3x} \). Simplify to get \( \frac{\sqrt{1+3x} + 1}{3} \). As \( x \rightarrow 0 \), \( \sqrt{1+3x} \rightarrow 1 \), thus the expression becomes \( \frac{2}{3} \).
5Step 5: Conclusion
We conclude that both our estimation methods (graphing and tabulation) and analytical proof using Limit Laws agree that the limit is \( \frac{2}{3} \). Therefore, the solution is confirmed, and the limit is indeed \( \frac{2}{3} \).
Key Concepts
Limit LawsRationalizationGraphing Functions
Limit Laws
In calculus, limit laws are essential tools that help us evaluate limits of functions more easily and systematically. These laws provide algebraic shortcuts to simplify complex expressions as a variable approaches a specific value. For the function given in the exercise, the limit laws facilitate proving the limit is \( \frac{2}{3} \) at \( x = 0 \).
When dealing with limits, key laws include:
When dealing with limits, key laws include:
- The sum law: The limit of a sum is equal to the sum of the limits.
- The product law: The limit of a product is equal to the product of the limits.
- The quotient law: The limit of a quotient is equal to the quotient of the limits, as long as the denominator isn't zero.
Rationalization
Rationalization is a technique used to simplify expressions by removing radicals from the denominator. This is especially useful in limit problems where direct substitution leads to an undefined form such as \( \frac{0}{0} \). By rationalizing, we can restructure the expression to avoid such issues, enabling a clear path to evaluate the limit.
In the given exercise, the function \( f(x) = \frac{x}{\sqrt{1+3x} - 1} \) is initially undefined at \( x = 0 \). By multiplying the numerator and the denominator by the conjugate \( \sqrt{1+3x} + 1 \), the expression transforms into a more manageable form:
In the given exercise, the function \( f(x) = \frac{x}{\sqrt{1+3x} - 1} \) is initially undefined at \( x = 0 \). By multiplying the numerator and the denominator by the conjugate \( \sqrt{1+3x} + 1 \), the expression transforms into a more manageable form:
- The denominator \( (\sqrt{1+3x} - 1)(\sqrt{1+3x} + 1) \) simplifies to \( 3x \).
- The entire expression simplifies to \( \frac{\sqrt{1+3x} + 1}{3} \).
Graphing Functions
Graphing functions is an invaluable method for visually exploring the behavior of mathematical expressions. By plotting a graph of a function, we gain insight into its behavior around specific points—like where the limit is to be determined—as well as a general understanding of the function's trend.
In this exercise, graphing \( f(x) = \frac{x}{\sqrt{1+3x} - 1} \) around \( x = 0 \) shows how the function behaves as it approaches the point. Observing the plot, the graph appears to converge towards the value \( \frac{2}{3} \). This visual estimate provided a guideline for detailed analytical verification and can often confirm our numerical or algebraic guess about a limit.
Graphing offers an initial checkpoint when analyzing limits, as it presents a qualitative sense of the function's behavior. This becomes especially useful in validating results obtained through limit laws and rationalization.
In this exercise, graphing \( f(x) = \frac{x}{\sqrt{1+3x} - 1} \) around \( x = 0 \) shows how the function behaves as it approaches the point. Observing the plot, the graph appears to converge towards the value \( \frac{2}{3} \). This visual estimate provided a guideline for detailed analytical verification and can often confirm our numerical or algebraic guess about a limit.
Graphing offers an initial checkpoint when analyzing limits, as it presents a qualitative sense of the function's behavior. This becomes especially useful in validating results obtained through limit laws and rationalization.
Other exercises in this chapter
Problem 26
If the sequence is convergent, find its limit. If it is divergent, explain why. $$a_{n}=\frac{n-1}{n^{3}+1}$$
View solution Problem 26
(a) If \(g(x)=1 /(2 x-1),\) find \(g^{\prime}(a)\) (b) Find equations of the tangent lines to the graph of \(g\) at the points whose \(x\) -coordinates are \(-1
View solution Problem 27
If the sequence is convergent, find its limit. If it is divergent, explain why. $$a_{n}=\frac{1}{3^{n}}$$
View solution Problem 27
If a ball is thrown straight up with a velocity of \(40 \mathrm{ft} / \mathrm{s}\), its height (in feet) after \(t\) seconds is given by \(y=40 t-16 t^{2} .\) F
View solution