Problem 27
Question
\(25-28\) . Evaluate the expression using \(x=3, y=4,\) and \(z=-1\) $$ (9 x)^{2 / 3}+(2 y)^{2 / 3}+z^{2 / 3} $$
Step-by-Step Solution
Verified Answer
The evaluated expression is 14.
1Step 1: Substitute the Values of Variables
Replace each variable in the expression with its given value. The expression becomes:\[(9 \times 3)^{2/3} + (2 \times 4)^{2/3} + (-1)^{2/3}\]
2Step 2: Simplify Inside the Parentheses
Calculate the values inside the parentheses:1. For \(9 \times 3\), calculate \(9 \times 3 = 27\).2. For \(2 \times 4\), calculate \(2 \times 4 = 8\).3. The last term is already \(-1\). Now the expression is:\[27^{2/3} + 8^{2/3} + (-1)^{2/3}\]
3Step 3: Evaluate the Exponents
Now calculate each term with the fractional exponent:1. \(27^{2/3}\): The cube root of 27 is 3, so \((27^{1/3} = 3)\), and \(3^2 = 9\).2. \(8^{2/3}\): The cube root of 8 is 2, so \((8^{1/3} = 2)\), and \(2^2 = 4\).3. \((-1)^{2/3}\): The cube root of -1 is -1, and \((-1)^2 = 1\).
4Step 4: Add the Simplified Terms
Sum the evaluated terms from the previous step:\(9 + 4 + 1 = 14\).
Key Concepts
Substitution in ExpressionsSimplifying ExponentsFractional Exponents
Substitution in Expressions
When you encounter an algebraic expression, substitution is a key step in evaluating it. Substitution involves replacing each variable in the expression with a given numeric value.
For example, if you're given an expression like \((9x)^{2/3} + (2y)^{2/3} + z^{2/3}\), and you know that \(x=3\), \(y=4\), and \(z=-1\), you'll substitute these values wherever the variables appear.
By doing this, you turn the expression into numerical form, like so: \((9 \times 3)^{2/3} + (2 \times 4)^{2/3} + (-1)^{2/3}\).
For example, if you're given an expression like \((9x)^{2/3} + (2y)^{2/3} + z^{2/3}\), and you know that \(x=3\), \(y=4\), and \(z=-1\), you'll substitute these values wherever the variables appear.
By doing this, you turn the expression into numerical form, like so: \((9 \times 3)^{2/3} + (2 \times 4)^{2/3} + (-1)^{2/3}\).
- Step-by-step substitution:
- Replace \(x\) with 3, \(y\) with 4, and \(z\) with -1.
- This results in the values in parentheses changing to actual numbers.
Simplifying Exponents
After substituting the values, you will often need to simplify expressions that contain exponents. Simplifying exponents means performing any arithmetic inside the base of the exponents and then addressing the exponent.
For example, consider the expression \( (9 \times 3)^{2/3} + (2 \times 4)^{2/3} + (-1)^{2/3} \). First, calculate what is inside the parentheses:
For example, consider the expression \( (9 \times 3)^{2/3} + (2 \times 4)^{2/3} + (-1)^{2/3} \). First, calculate what is inside the parentheses:
- Calculate \(9 \times 3\), which equals 27.
- Calculate \(2 \times 4\), which equals 8.
- \(-1\) is already simplified.
Fractional Exponents
Fractional exponents represent both a root and a power simultaneously. To evaluate them, you typically take the root first and then apply the power.
- Understanding Fractional Exponents: In \(a^{m/n}\), \(n\) signifies the root, and \(m\) signifies the power.
- In this problem, look at expressions like \(27^{2/3}\):
- First, take the cube root of 27, which is 3.
- Then, raise that result to the power of 2, giving you 9.
- The cube root of 8 is 2.
- Square that result to get 4.
- The cube root of -1 is -1.
- But when squared, it becomes positive, resulting in 1.
Other exercises in this chapter
Problem 27
\(21-28\) Use a Factoring Formula to factor the expression. $$ x^{2}+12 x+36 $$
View solution Problem 27
\(7-28\) Evaluate each expression. $$ 2^{-2}+2^{-3} $$
View solution Problem 27
Find the indicated set if $$ A=\\{1,2,3,4,5,6,7\\} \quad B=\\{2,4,6,8\\} \quad C=\\{7,8,9,10\\} $$ $$ \begin{array}{ll}{\text { (a) } A \cup B} & {\text { (b) }
View solution Problem 27
Use properties of real numbers to write the expression without parentheses. \(-\frac{5}{2}(2 x-4 y)\)
View solution