Problem 261
Question
An aqueous solution of \(1 \mathrm{M} \mathrm{NaCl}\) and \(\mathrm{IM} \mathrm{HCl}\) is [2002] (a) not a buffer but \(\mathrm{pH}<7\) (b) not a buffer but \(\mathrm{pH}>7\) (c) a buffer with \(\mathrm{pH}<7\) (d) a buffer with \(\mathrm{pH}>7\)
Step-by-Step Solution
Verified Answer
(a) not a buffer but \( \mathrm{pH}<7 \).
1Step 1: Understanding the Components
Identify the components in the solution: NaCl and HCl. NaCl is a neutral salt and does not affect the pH of the solution. HCl is a strong acid, which dissociates completely, contributing H⁺ ions.
2Step 2: Identifying Buffer Conditions
A buffer solution contains a weak acid and its conjugate base, or a weak base and its conjugate acid. Here, HCl is a strong acid and there is no conjugate base present in significant amounts from a weak acid to form a buffer.
3Step 3: Predicting the pH of the Solution
Because HCl is a strong acid, the solution will have an excess of H⁺ ions. Therefore, the solution is acidic, and the pH will be less than 7.
4Step 4: Final Analysis
Since the solution is neither a mixture of a weak acid and its conjugate base nor a weak base and its conjugate acid, it is not a buffer. Given that it contains a strong acid, the pH is less than 7.
Key Concepts
Buffer SolutionsStrong AcidsConjugate Base
Buffer Solutions
A buffer solution is a special type of solution that resists changes in its pH. It's a mixture of a weak acid and its conjugate base, or a weak base and its conjugate acid.
These solutions are crucial, especially in maintaining the pH necessary for various biological and chemical processes.
This is because they work together to neutralize additional acids or bases.
These solutions are crucial, especially in maintaining the pH necessary for various biological and chemical processes.
- A buffer solution can maintain its pH even when a small amount of strong acid or strong base is added.
- In contrast, solutions without these buffering components can undergo significant pH changes.
- Buffer solutions are typically made by partially neutralizing a weak acid with a strong base, or vice versa.
This is because they work together to neutralize additional acids or bases.
Strong Acids
Strong acids are chemicals that dissociate completely in water, releasing protons (H⁺ ions) and increasing the hydrogen ion concentration of the solution.
This complete dissociation makes them very effective at lowering the pH of a solution.
This is because there is an abundance of H⁺ ions, which are responsible for the acidic property.
This complete dissociation makes them very effective at lowering the pH of a solution.
- Common examples include hydrochloric acid (HCl), sulfuric acid (H₂SO₄), and nitric acid (HNO₃).
- Unlike weak acids, which only partially dissociate, strong acids fully release their protons when dissolved.
This is because there is an abundance of H⁺ ions, which are responsible for the acidic property.
Conjugate Base
The conjugate base of an acid is what remains after the acid has donated a proton. In other words, it's the substance formed when an acid loses an H⁺ ion.
An essential aspect of buffer solutions is the presence of sufficient quantities of both the weak acid and its conjugate base.
This is because there is no equilibrium established between a weak acid and its conjugate base to adjust pH changes.
An essential aspect of buffer solutions is the presence of sufficient quantities of both the weak acid and its conjugate base.
- For example, the conjugate base of acetic acid (CH₃COOH) is acetate (CH₃COO⁻).
- A conjugate base is typically a weaker base than the strong bases found in solution.
This is because there is no equilibrium established between a weak acid and its conjugate base to adjust pH changes.
Other exercises in this chapter
Problem 259
Solubility of \(\mathrm{Ca}(\mathrm{OH})_{2}\) is \(\mathrm{S}\) mol litre \(^{-1} .\) The solubility product (Ksp) under the same condition is [2002] (a) \(4 \
View solution Problem 260
One of the following species acts as both Bronsted acid and base (a) \(\mathrm{H}_{2} \mathrm{PO}_{2}\) (b) \(\mathrm{HPO}_{3}^{2}\) (c) \(\mathrm{HPO}_{4}^{2}\
View solution Problem 262
\(\mathrm{pH}\) of \(0.005 \mathrm{M}\) calcium acetate \(\left(\mathrm{pKa}\right.\) of \(\mathrm{CH}_{3} \mathrm{COOH}\) \(=4.74)\) is [2002] (a) \(7.37\) (b)
View solution Problem 263
The solubility in water of a sparingly soluble salt \(\mathrm{AB}_{2}\) is \(1.0 \times 10^{-5} \mathrm{molL}^{-1}\). Its solubility product number will be (a)
View solution