Problem 26
Question
Write the equation of a circle in standard form with the following properties. Center at \((5,3) ;\) radius 2
Step-by-Step Solution
Verified Answer
The equation of the circle is \\( (x - 5)^2 + (y - 3)^2 = 4 \\).
1Step 1: Identify the Standard Form Formula for a Circle
The standard form of the equation of a circle with center \(h, k\) and radius \ r \ is given by \( (x - h)^2 + (y - k)^2 = r^2 \). Here, \( (h, k) = (5, 3) \), and \( r = 2 \).
2Step 2: Substitute the Center Coordinates
Plug the center coordinates \( h = 5 \) and \( k = 3 \) into the circle equation to get \( (x - 5)^2 + (y - 3)^2 = r^2 \).
3Step 3: Substitute the Radius
Replace \( r \) with the radius value, which is 2. This modifies the equation to \( (x - 5)^2 + (y - 3)^2 = 2^2 \).
4Step 4: Simplify the Equation
Calculate \( 2^2 \) which equals 4. Finalizing the equation gives \( (x - 5)^2 + (y - 3)^2 = 4 \). This is the standard form of the circle's equation.
Key Concepts
Standard FormCenter and RadiusGeometry
Standard Form
In the world of mathematics, particularly in geometry, the standard form of a circle's equation is a very useful tool. This form allows us to clearly see both the center and radius of a circle from its equation. The standard form is given by:
- \((x - h)^2 + (y - k)^2 = r^2\)
Center and Radius
Every circle has specific characteristics, namely its center and radius, which determine its size and position on a plane.
- The **center** of the circle, denoted as \( (h, k) \), indicates the exact middle point of the circle. This point is equidistant from any point on the circle's boundary.
- The **radius** \( r \) is the distance from the center to any point on the circumference of the circle. It essentially determines the size of the circle.
- Center: \( h = 5 \, k = 3 \)
- Radius: \( r = 2 \)
Geometry
Geometry helps us understand the spatial arrangement and properties of shapes, and circles are a fundamental shape studied in this field. Circles have unique symmetry and uniformity, and their equations are deeply rooted in geometric principles. By studying the equation of a circle in standard form, we can easily determine key attributes like position, size, and relationships within a coordinate plane.
Using the standard form, one can explore:
Using the standard form, one can explore:
- The concept of **symmetry** around the center point, where every point on the circle is at an equal distance from its center.
- How varying the radius \( r \) affects the circle's size and space it occupies on the graph.
- The impact of shifting the center \( (h,k) \), which moves the entire circle across the plane without altering its shape.
Other exercises in this chapter
Problem 25
Graph each equation. \(\frac{(x-2)^{2}}{9}+\frac{(y-1)^{2}}{4}=1\)
View solution Problem 26
Graph each hyperbola. See Example 3. $$ \frac{(x+2)^{2}}{16}-\frac{(y-3)^{2}}{25}=1 $$
View solution Problem 26
Graph each equation. \(\frac{(x-1)^{2}}{9}+\frac{(y-3)^{2}}{4}=1\)
View solution Problem 27
Solve each system of equations by substitution for real values of \(x\) and \(y.\) See Examples 2 and 3. $$ \left\\{\begin{array}{l} x^{2}+y^{2}=13 \\ y=x^{2}-1
View solution