Problem 26
Question
Without plotting the point, tell whether it is in Quadrant I, Quadrant II, Quadrant III, or Quadrant IV. $$(-5,6)$$
Step-by-Step Solution
Verified Answer
The point (-5,6) is located in Quadrant II.
1Step 1: Identify the x-coordinate
The x-coordinate of the given point is -5. Negative values for x indicate that the point is located to the left of the origin. This narrows down our possibilities to Quadrant II and Quadrant III, where x-values are negative.
2Step 2: Identify the y-coordinate
The y-coordinate of the given point is 6. Positive values for y indicate that the point is located above the origin. This means the point is located in Quadrant II, where y-values are also positive.
3Step 3: Determine the Quadrant
Given that the x-coordinate is negative and the y-coordinate is positive, we can conclude that the point (-5,6) is located in Quadrant II.
Key Concepts
quadrantsx-coordinatey-coordinate
quadrants
In a coordinate plane, quadrants help us locate points based on their positions relative to the origin, which is where the x-axis and y-axis intersect. Each quadrant is like a section of the plane, separated by these axes.
There are four quadrants:
There are four quadrants:
- Quadrant I: Both x and y coordinates are positive. This means any point here is up and to the right of the origin.
- Quadrant II: The x-coordinate is negative, while the y-coordinate is positive. Points in this quadrant are up and to the left of the origin.
- Quadrant III: Both coordinates are negative, placing points down and to the left of the origin.
- Quadrant IV: The x-coordinate is positive, and the y-coordinate is negative. This quadrant contains points down and to the right of the origin.
x-coordinate
The x-coordinate, or abscissa, is the first in the ordered pair \(x, y\), and it tells us how far left or right a point is from the origin. A positive x-value places the point to the right of the origin, while a negative x-value places it to the left.
When analyzing the point \((-5, 6)\), the x-coordinate is -5. This indicates a position to the left of the y-axis.
The importance of the x-coordinate lies in its ability to help identify which side of the coordinate plane the point resides in. It immediately helps us differentiate between Quadrants I and IV, which have positive x-coordinates, and Quadrants II and III, both with negative values.
When analyzing the point \((-5, 6)\), the x-coordinate is -5. This indicates a position to the left of the y-axis.
The importance of the x-coordinate lies in its ability to help identify which side of the coordinate plane the point resides in. It immediately helps us differentiate between Quadrants I and IV, which have positive x-coordinates, and Quadrants II and III, both with negative values.
y-coordinate
The y-coordinate, also known as the ordinate, is the second value in the ordered pair \(x, y\). It represents how high or low a point is from the origin. Positive y-values position the point above the x-axis, while negative y-values place it below.
For the point \((-5, 6)\), the y-coordinate is 6, meaning the point is above the x-axis.
Understanding the y-coordinate is crucial. It assists in pinpointing whether the point is located in Quadrants I or II, where y-coordinates are positive, or in Quadrants III or IV, where they are negative. Combining both x and y coordinates helps precisely determine the location of any point on the coordinate plane.
For the point \((-5, 6)\), the y-coordinate is 6, meaning the point is above the x-axis.
Understanding the y-coordinate is crucial. It assists in pinpointing whether the point is located in Quadrants I or II, where y-coordinates are positive, or in Quadrants III or IV, where they are negative. Combining both x and y coordinates helps precisely determine the location of any point on the coordinate plane.
Other exercises in this chapter
Problem 25
Find three different ordered pairs that are solutions of the equation. \(x=\frac{1}{2}\)
View solution Problem 26
Solve the equation algebraically. Check your solution graphically. $$-\frac{2}{3} x-6=-4$$
View solution Problem 26
Evaluate the function when \(x=2, x=0,\) and \(x=-3\). $$ h(x)=\frac{3}{4} x-4 $$
View solution Problem 26
The variables x and y vary directly. Use the given values to write an equation that relates x and y. $$x=22, y=11$$
View solution