Problem 26
Question
Which of the series converge, and which diverge? Use any method, and give reasons for your answers. \begin{equation}\sum_{n=1}^{\infty} \frac{1}{\sqrt{n^{3}+2}}\end{equation}
Step-by-Step Solution
Verified Answer
The series converges by the Comparison Test with the convergent p-series \( \sum \frac{1}{n^{3/2}} \).
1Step 1: Determine Test Choice
To determine if the series \( \sum_{n=1}^{\infty} \frac{1}{\sqrt{n^{3}+2}} \) converges or diverges, we need to choose an appropriate convergence test. Since the series involves a radical function of \( n \) (namely \( \sqrt{n^3 + 2} \)), we shall use the Comparison Test by comparing it to a simpler series.
2Step 2: Compare with a Simpler Series
We note that for large \( n \), the expression \( \sqrt{n^3 + 2} \) can be approximated by \( \sqrt{n^3} = n^{3/2} \). Thus, we compare with the series \( \sum_{n=1}^{\infty} \frac{1}{n^{3/2}} \), which is a known p-series.
3Step 3: Test Known Series for Convergence
The series \( \sum_{n=1}^{\infty} \frac{1}{n^{3/2}} \) is a p-series where \( p = 3/2 > 1 \). It is a known fact that p-series converge if \( p > 1 \). Thus, \( \sum_{n=1}^{\infty} \frac{1}{n^{3/2}} \) converges.
4Step 4: Apply the Comparison Test
Since \( \sqrt{n^3 + 2} > n^{3/2} \) for all \( n \geq 1 \), it follows that \( \frac{1}{\sqrt{n^3 + 2}} < \frac{1}{n^{3/2}} \). By the Comparison Test, because the larger series \( \sum_{n=1}^{\infty} \frac{1}{n^{3/2}} \) converges, our original series \( \sum_{n=1}^{\infty} \frac{1}{\sqrt{n^{3}+2}} \) also converges.
Key Concepts
Understanding the Comparison TestExploring p-seriesUnderstanding Infinite SeriesSequence and Series Convergence
Understanding the Comparison Test
The comparison test is an analytical method used to determine the convergence or divergence of infinite series. It involves comparing the series in question with another series whose convergence properties are already known.
The idea is simple: if you can show that your series behaves similarly to a well-understood series, you can draw conclusions about its convergence or divergence.
In our example, the given series involves terms of the form \(\frac{1}{\sqrt{n^3 + 2}}\). By approximating \(\sqrt{n^3 + 2}\) as \(n^{3/2}\), we compare to the known convergent p-series \(\sum \frac{1}{n^{3/2}}\). Since \(\frac{1}{\sqrt{n^3+2}} < \frac{1}{n^{3/2}}\), the original series converges by the comparison test.
The idea is simple: if you can show that your series behaves similarly to a well-understood series, you can draw conclusions about its convergence or divergence.
- If series A is always less than or equal to series B, and series B converges, then series A also converges.
- Conversely, if series A is greater than series B, and B diverges, then A diverges as well.
In our example, the given series involves terms of the form \(\frac{1}{\sqrt{n^3 + 2}}\). By approximating \(\sqrt{n^3 + 2}\) as \(n^{3/2}\), we compare to the known convergent p-series \(\sum \frac{1}{n^{3/2}}\). Since \(\frac{1}{\sqrt{n^3+2}} < \frac{1}{n^{3/2}}\), the original series converges by the comparison test.
Exploring p-series
P-series are a specific type of series given by the formula \(\sum_{n=1}^{\infty} \frac{1}{n^p}\), where \(p\) is a real number. Understanding p-series is crucial when studying the convergence of sequences and series.
The convergence of p-series can be simply determined:
This rule is essential for analyzing other series by comparison. In the solution above, the comparison was made with a p-series where \(p = 3/2\). Since \(3/2 > 1\), we concluded that the comparison series converges, helping us determine the behavior of our original series.
The convergence of p-series can be simply determined:
- If \(p > 1\), the series converges.
- If \(p \leq 1\), the series diverges.
This rule is essential for analyzing other series by comparison. In the solution above, the comparison was made with a p-series where \(p = 3/2\). Since \(3/2 > 1\), we concluded that the comparison series converges, helping us determine the behavior of our original series.
Understanding Infinite Series
An infinite series is the sum of an infinite sequence of numbers. The study of these series is vital in mathematics as they appear in calculus, number theory, and many areas of science.
Not all infinite series sum to a finite number, which is why determining convergence or divergence is important. When a series converges, its terms approach a limiting value, allowing the series to sum to a finite number.
Analyzing infinite series often involves various tests, such as the comparison test, to assess these behaviors.
Not all infinite series sum to a finite number, which is why determining convergence or divergence is important. When a series converges, its terms approach a limiting value, allowing the series to sum to a finite number.
- Convergent series are stable and useful in many practical applications.
- Divergent series grow without bound and typically indicate instability or lack of a solution in the context applied.
Analyzing infinite series often involves various tests, such as the comparison test, to assess these behaviors.
Sequence and Series Convergence
The convergence of a sequence or series indicates that it approaches a specific value as \(n\) (the number of terms) approaches infinity.
Sequences are collections of numbers, while series are sums of sequences. The convergence test for a series checks if adding more terms leads us to a stable sum.
Understanding the criteria for convergence, like the comparison test or observing behavior akin to convergent p-series, is essential for navigating more complex mathematical problems.
Sequences are collections of numbers, while series are sums of sequences. The convergence test for a series checks if adding more terms leads us to a stable sum.
- A converging sequence will have its terms getting closer and closer to a particular number.
- For series, convergence implies that the sum of its terms reaches a limit, even with infinitely many terms.
Understanding the criteria for convergence, like the comparison test or observing behavior akin to convergent p-series, is essential for navigating more complex mathematical problems.
Other exercises in this chapter
Problem 26
Use power series operations to find the Taylor series at \(x=0\) for the functions in Exercises \(11-28 .\) $$\cos x-\sin x$$
View solution Problem 26
Find the Taylor series generated by \(f\) at \(x=a.\) \(f(x)=3 x^{5}-x^{4}+2 x^{3}+x^{2}-2, \quad a=-1\)
View solution Problem 26
Which of the series Converge absolutely, which converge, and which diverge? Give reasons for your answers. $$ \sum_{n=1}^{\infty}(-1)^{n+1}(\sqrt[n]{10}) $$
View solution Problem 26
Determining Convergence or Divergence In Exercises \(17-44,\) use any method to determine if the series converges or diverges. Give reasons for your answer. $$\
View solution