Problem 26
Question
Use the table to fill in the missing values. (There may be more than one answer.) (a) \(h(?)=2 h(0)\) (b) \(h(?)=2 h(-3)+h(2)\) (c) \(h(?)=h(-2)\) (d) \(h(?)=h(1)+h(2)\) $$ \begin{array}{c|c|c|c|c|c|c|c} t & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\ \hline h(t) & -1 & 0 & -4 & -2 & -1 & -2 & 0 \\ \hline \end{array} $$
Step-by-Step Solution
Verified Answer
)=2 h(0)
b) h(?)=2 h(-3)+h(2)
c) h(?)=h(-2)
d) h(?)=h(1)+h(2)
Answer:
a) h(-1)=2 h(0)
b) h(-1)=2 h(-3)+h(2)
c) h(-2)=h(-2)
d) No solution.
1Step 1: Identify h(0) in the table
Looking at the table, h(0) = -2.
2Step 2: Calculate 2 h(0)
Multiply h(0) by 2:
2 * (-2) = -4
Now we need to look for the value -4 in the table to identify what value of t corresponds to it. -4 corresponds to t = -1 in the table.
#a) Result#: \(h(-1) = 2 h(0)\)
#b) h(?)=2 h(-3)+h(2)#
3Step 3: Identify h(-3) and h(2) in the table
Looking at the table, h(-3) = -1 and h(2) = -2.
4Step 4: Calculate 2 h(-3) + h(2)
Substitute the known values in the equation:
2 * (-1) + (-2) = -4
Now, we look for the value -4 in the table. -4 corresponds to t = -1 in the table.
#b) Result#: \(h(-1) = 2 h(-3) + h(2)\)
#c) h(?)=h(-2)#
5Step 5: Identify h(-2) in the table
Looking at the table, h(-2) = 0.
Since h(-2) = 0, the missing value should correspond to t = -2.
#c) Result#: \(h(-2) = h(-2)\)
#d) h(?)=h(1)+h(2)#
6Step 6: Identify h(1) and h(2) in the table
Looking at the table, h(1) = -1 and h(2) = -2.
7Step 7: Calculate h(1) + h(2)
Add h(1) and h(2):
-1 + (-2) = -3
Now, we look for the value -3 in the table. However, there is no value of h(t) equal to -3 in the table, so there is no solution for this expression.
#d) Result#: No solution.
Key Concepts
function_evaluationfunction_tableproblem_solvingfunction_identification
function_evaluation
Function evaluation is the process of determining the output of a function for a particular input value. In mathematical terms, a function is a rule that assigns each input from a set of inputs (called the domain) to exactly one output in a set of possible outputs (called the range). To evaluate a function means to find the value of the function's output for a specific input. Let's consider the function given by the table in the exercise. For each value of \( t \), there is a corresponding \( h(t) \). For example:
- When \( t = -3 \), \( h(t) = -1 \).
- When \( t = 0 \), \( h(t) = -2 \).
function_table
A function table is a representation of outputs based on corresponding inputs. Each row or column in a function table, like the one provided in the exercise, usually represents a specific input-output pairing. This exercise gives a set of values for \( t \) and their corresponding outputs \( h(t) \):
- The table lists values for \(-3 \le t \le 3 \).
- The corresponding \( h(t) \) values vary based on \( t \).
problem_solving
Problem-solving in the context of functions often means understanding how to manipulate and use function formulas and values to find unknown quantities. In this exercise, you must use known values from a function table to deduce and solve for \( t \) values that satisfy different function equations. The process involves:
- Identifying known values from the table, such as \( h(0) = -2 \) and \( h(1) = -1 \).
- Applying these values in new expressions like \( h(?) = 2h(0) \) to re-calculate and solve for specific \( t \).
- Checking the computed results against the table to verify accuracy.
function_identification
Function identification involves recognizing specific functions and their properties by using given information or structures, like tables or equations. It's about matching given conditions to known function values and determining the settings in which these conditions hold true.Throughout this exercise:
- You're tasked with identifying which \( t \) values satisfy conditions such as \( h(?) = h(-2) \).
- It requires you to know not just the value \( h(-2) = 0 \) but also to find what other \( t \) value possesses an equivalent output, which might mean such direct comparison simplifies this to \( h(-2) = h(-2) \).
- Recognizing unmatched circumstances, like in part d, where \( h(1) + h(2) eq h(t) \) for any \( t \), is also part of function identification.
Other exercises in this chapter
Problem 26
Table 4.9 shows values of \(x\) and the expression \(3 x+2\). For which values of \(x\) in the table is (a) \(3 x+28 ?\) (c) \(3 x+2=8 ?\) Table 4.9 $$ \begin{a
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Put the functions in the form \(Q=k t\) and state the value of \(k\). $$ Q=t(n+1) $$
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Put the functions in the form \(Q=k t\) and state the value of \(k\). $$ Q=b t+r t $$
View solution Problem 28
Table 4.11 shows values of \(v\) and the expressions \(12-3 v\) and \(-3+2 v\). For which values of \(v\) in the table is (a) \(12-3 v-3+2 v ?\) (c) \(12-3 v=-3
View solution