Problem 26
Question
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Passing through \((3,5)\) and \((8,15)\)
Step-by-Step Solution
Verified Answer
The line passing through the points (3, 5) and (8, 15) can be represented by the equation \(y - 5 = 2(x - 3)\) in point-slope form and \(y = 2x - 1\) in slope-intercept form.
1Step 1: Calculate the slope
We can calculate the slope of the line using the formula \(m = \frac{y_2-y_1}{x_2-x_1}\). Plugging the given points into this formula gives \(m = \frac{15-5}{8-3} = \frac{10}{5} = 2\).
2Step 2: Write the equation in point-slope form
Substituting \(m = 2\), \(x_1 = 3\), and \(y_1 = 5\) into the equation for point-slope form, \(y - y_1 = m(x - x_1)\), we get \(y - 5 = 2(x - 3)\).
3Step 3: Convert the equation into slope-intercept form
Solving the equation from Step 2 for \(y\) gives the equation in slope-intercept form. \(y - 5 = 2x - 6 \Rightarrow y = 2x - 1\).
Other exercises in this chapter
Problem 26
Determine whether each equation defines \(y\) as a function of \(x .\) $$ |x|-y=5 $$
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Determine whether each function is even, odd, or neither. $$f(x)=2 x^{3}-6 x^{5}$$
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find the midpoint of each line segment with the given endpoints. $$ (8,3 \sqrt{5}) \text { and }(-6,7 \sqrt{5}) $$
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