Problem 26
Question
Use positive rational exponents to rewrite each expression. Assume variables represent positive numbers. $$(\sqrt[3]{y^{2}})^{-5}$$
Step-by-Step Solution
Verified Answer
\(\frac{1}{y^{10/3}}\)
1Step 1: Understand the expression
We start with the expression \((\sqrt[3]{y^{2}})^{-5}\). The term \(\sqrt[3]{y^{2}}\) represents the cube root of \(y^2\).
2Step 2: Convert to rational exponent
The expression \(\sqrt[3]{y^{2}}\) can be rewritten using rational exponents as \(y^{2/3}\). This follows from the fact that a cube root is equivalent to raising to the power of \(1/3\).
3Step 3: Apply the negative exponent
Applying the negative exponent \(-5\) to \(y^{2/3}\), we have: \((y^{2/3})^{-5}\).
4Step 4: Simplify using the power of a power rule
Use the exponent rule \((a^m)^n = a^{m \cdot n}\) to combine the exponents. We get \(y^{(2/3) \cdot (-5)} = y^{-10/3}\).
5Step 5: Convert negative exponent to positive
Rewrite \(y^{-10/3}\) as a fraction: \(\frac{1}{y^{10/3}}\) to express the expression with a positive exponent.
Key Concepts
Rational ExponentsNegative ExponentsExponent Rules
Rational Exponents
In mathematics, rational exponents provide a way to express roots and powers within a single notation. Instead of writing the cube root of something, like \( \sqrt[3]{y^2} \), you can use a fraction as the exponent: \( y^{2/3} \). Here’s why and how it works:
Using rational exponents simplifies calculations and unifies the operations of taking roots and raising powers. It also prepares you for more advanced math topics where these concepts are used extensively.
- The numerator (top part) of the rational exponent tells you the power. In \( y^{2/3} \), the 2 tells us that we are squaring \( y \).
- The denominator (bottom part) tells you the root. The 3 indicates a cube root.
Using rational exponents simplifies calculations and unifies the operations of taking roots and raising powers. It also prepares you for more advanced math topics where these concepts are used extensively.
Negative Exponents
Negative exponents might seem tricky at first, but they have a simple rule: a negative exponent means "one over" the positive exponent. It's helpful because it offers a quick way to move terms with exponents to different parts of a fraction.
To make sense of \( y^{-10/3} \), remember:
This process of turning negative exponents into positive ones helps with simplification. It can also make expressions easier to evaluate, especially when combining different terms.
To make sense of \( y^{-10/3} \), remember:
- A negative exponent indicates the reciprocal. So, \( y^{-1} = \frac{1}{y} \).
- Therefore, \( y^{-10/3} = \frac{1}{y^{10/3}} \).
This process of turning negative exponents into positive ones helps with simplification. It can also make expressions easier to evaluate, especially when combining different terms.
Exponent Rules
Exponent rules are guidelines that make it easier to handle expressions with powers. Knowing key rules streamlines simplification and manipulation of powers.
Here are some important ones:
In the step where we simplified \( (y^{2/3})^{-5} \) to \( y^{-10/3} \), we used the power rule by multiplying the exponents. These rules are fundamental tools when working with exponents, allowing for quick and accurate transformations of expressions.
Here are some important ones:
- The Product Rule: \( a^m \times a^n = a^{m+n} \).
- The Quotient Rule: \( \frac{a^m}{a^n} = a^{m-n} \).
- The Power Rule: \((a^m)^n = a^{m \cdot n} \).
In the step where we simplified \( (y^{2/3})^{-5} \) to \( y^{-10/3} \), we used the power rule by multiplying the exponents. These rules are fundamental tools when working with exponents, allowing for quick and accurate transformations of expressions.
Other exercises in this chapter
Problem 26
Write a formula for a rational function with vertical asymptote \(x=1\) and oblique asymptote \(y=x+2\)
View solution Problem 26
Solve each equation by hand. Do not use a calculator. $$2 x^{-2}-x^{-1}=3$$
View solution Problem 26
Explain how the graph of \(f\) can be obtained from the graph of \(y=\frac{1}{x}\) or \(y=\frac{1}{x^{2}} .\) Draw a sketch of the graph of \(f\) by hand. Then
View solution Problem 27
Find all complex solutions for each equation by hand. $$\frac{x}{x-3}+\frac{4}{x+3}=\frac{18}{x^{2}-9}$$
View solution