Problem 26
Question
Use a table of values to estimate the value of the limit. If you have a graphing device, use it to confirm your result graphically. \( \displaystyle \lim_{t \to 0}\frac{5^t - 1}{t} \)
Step-by-Step Solution
Verified Answer
The estimated limit is approximately 1.48.
1Step 1: Understanding the Limit Expression
We need to estimate the limit of the expression \( \frac{5^t - 1}{t} \) as \( t \) approaches 0. This means that we should evaluate how the expression behaves as \( t \) gets closer and closer to zero from both the positive and negative sides.
2Step 2: Create a Table of Values
To create a table of values, we'll select values of \( t \) that are close to 0, such as \( t = -0.1, -0.01, -0.001, 0, 0.001, 0.01, 0.1 \). For each of these values, we will compute \( \frac{5^t - 1}{t} \).
3Step 3: Calculate Values for Positive \( t \) Near 0
Let's calculate \( \frac{5^t - 1}{t} \) for positive values: - For \( t = 0.1 \), \( \frac{5^{0.1} - 1}{0.1} \approx 1.61 \)- For \( t = 0.01 \), \( \frac{5^{0.01} - 1}{0.01} \approx 1.48 \)- For \( t = 0.001 \), \( \frac{5^{0.001} - 1}{0.001} \approx 1.45 \)
4Step 4: Calculate Values for Negative \( t \) Near 0
Now, calculate for negative values of \( t \): - For \( t = -0.001 \), \( \frac{5^{-0.001} - 1}{-0.001} \approx 1.45 \)- For \( t = -0.01 \), \( \frac{5^{-0.01} - 1}{-0.01} \approx 1.48 \)- For \( t = -0.1 \), \( \frac{5^{-0.1} - 1}{-0.1} \approx 1.61 \)
5Step 5: Analyze and Estimate the Limit
Observe that as \( t \) approaches 0 from both the positive and negative directions, the value of \( \frac{5^t - 1}{t} \) seems to converge towards 1.48. Therefore, we estimate that the limit is approximately 1.48.
6Step 6: Verify using a Graphing Calculator
Plot the function \( f(t) = \frac{5^t - 1}{t} \) on a graphing calculator. The graph should show that as \( t \) approaches 0, the y-values of the graph approach 1.48. This graphical verification confirms our estimated limit.
Key Concepts
Limit EstimationGraphical VerificationTable of ValuesExponential Functions
Limit Estimation
Limit estimation is the process of finding the value that a function approaches as its input approaches a certain value. In our example, we need to estimate the limit of the expression \( \frac{5^t - 1}{t} \) as \( t \) approaches 0. This is particularly interesting because if we try to substitute \( t = 0 \) directly into the expression, we get an undefined form \( \frac{0}{0} \). Therefore, we need other methods such as numerical and graphical approaches.
One popular way to estimate limits is by choosing values of \( t \) that are very close to 0 and examining how the expression behaves. This involves checking the expression's value from both sides of the point we are interested in, paying close attention to whether these values converge towards a single number as we approach the point. This single number is what we refer to as the estimated limit of the function.
One popular way to estimate limits is by choosing values of \( t \) that are very close to 0 and examining how the expression behaves. This involves checking the expression's value from both sides of the point we are interested in, paying close attention to whether these values converge towards a single number as we approach the point. This single number is what we refer to as the estimated limit of the function.
Graphical Verification
Graphical verification involves using visual tools such as graphs to confirm the results obtained through mathematical estimations. For our problem, we plot the function \( f(t) = \frac{5^t - 1}{t} \) on a graphing calculator. As we focus on how the graph behaves when \( t \) approaches 0, the visual representation provides insights into how the function behaves near this point.
The graph is expected to show a clear trend of the y-values approaching a certain number as \( t \) gets closer to 0. In our specific example, we predict from our calculations that the function approaches the limit of approximately 1.48. If the graph confirms this by showing the curve approaching y = 1.48 as \( t \) moves towards zero from both sides, then the graphical verification supports our estimated limit.
The graph is expected to show a clear trend of the y-values approaching a certain number as \( t \) gets closer to 0. In our specific example, we predict from our calculations that the function approaches the limit of approximately 1.48. If the graph confirms this by showing the curve approaching y = 1.48 as \( t \) moves towards zero from both sides, then the graphical verification supports our estimated limit.
Table of Values
Creating a table of values is a practical method to explore how a function behaves near the point of interest. For our example, we select values of \( t \) that are very close to 0, such as \( -0.1, -0.01, -0.001, 0, 0.001, 0.01, 0.1 \), and compute \( \frac{5^t - 1}{t} \) for each.
Listing these results helps us to see patterns. Specifically:
Listing these results helps us to see patterns. Specifically:
- For positive values of \( t \), it appears the values decrease towards a point.
- Similarly, for negative \( t \), the values increase towards that same point.
Exponential Functions
Exponential functions, like \( 5^t \) in our limit problem, exhibit rapid growth or decay depending on the exponent \( t \). When working with limits involving such functions, the key trait is how they behave with small values of \( t \).
For very small \( t \), \( 5^t \) is close to 1, which indicates a small change or deviation about the base value. In our case, since we compute \( \frac{5^t - 1}{t} \), the expression accounts for how \( 5^t \) differs from 1, adjusted by \( t \), leading us to explore the instantaneous rate of change at \( t = 0 \). This links directly to the concept of derivatives in calculus, where analyzing how the output of an exponential function changes as \( t \) gets extremely close to zero is crucial.
Such nuances highlight the powerful nature of exponential functions in limit problems, demanding attention to subtle variances around the pivoting point, which in this case, is 0.
For very small \( t \), \( 5^t \) is close to 1, which indicates a small change or deviation about the base value. In our case, since we compute \( \frac{5^t - 1}{t} \), the expression accounts for how \( 5^t \) differs from 1, adjusted by \( t \), leading us to explore the instantaneous rate of change at \( t = 0 \). This links directly to the concept of derivatives in calculus, where analyzing how the output of an exponential function changes as \( t \) gets extremely close to zero is crucial.
Such nuances highlight the powerful nature of exponential functions in limit problems, demanding attention to subtle variances around the pivoting point, which in this case, is 0.
Other exercises in this chapter
Problem 26
Prove the statement using the \( \varepsilon \), \( \delta \) definition of a limit. \( \displaystyle \lim_{x \to 0} x^3 = 0 \)
View solution Problem 26
Evaluate the limit, if it exists. \( \displaystyle \lim_{t \to 0}\left( \frac{1}{t} - \frac{1}{t^2 + t} \right) \)
View solution Problem 27
Find the derivative of the function using the definition of derivative. State the domain of the function and the domain of its derivative. \( g(x) = \sqrt{9 - x
View solution Problem 27
If \( f(x) = 3x^2 - x^3 \), find \( f'(1) \) and use it to find an equation of the tangent line to the curve \( y = 3x^2 - x^3 \) at the point \( (1, 2) \).
View solution