Problem 26
Question
The function \(y=x^{2}\) has a U-shaped graph called a parabola. If the domain of this function is given as \(x \geq 0\) and \(x \leq 4,\) find the range.
Step-by-Step Solution
Verified Answer
The range of the function y = \(x^{2}\) for the domain \(0 \leq x \leq 4\) is \(0 \leq y \leq 16\).
1Step 1: Understand the Function
Consider the function \(y=x^{2}\), a quadratic function that describes a U-shaped curve or parabola. For this function, the lowest point (vertex) is at (0,0) when x=0.
2Step 2: Define the Domain
The domain of a function is the complete set of possible values of the independent variable. In this exercise, the given domain is \(x \geq 0\) and \(x \leq 4\). That means x takes any value from 0 to 4, inclusive.
3Step 3: Find the Range
Substitute the endpoints of the domain into the function to find the range. When substituting x=0 into the function, the result is \(0^{2}=0\). When x=4 are substituted, the resulting y-value is \(4^{2}=16\). So, the range of the function for this domain is \(0 \leq y \leq 16\).
Key Concepts
Understanding ParabolasExploring Domain and RangeVertex of a Parabola
Understanding Parabolas
A parabola is a symmetrical open plane curve formed by plotting a quadratic function like \( y = x^2 \). It resembles a "U" shape, and its understanding is crucial when studying quadratic functions. Each parabola is defined by its unique vertex and where it opens. Parabolas can open upwards, like \( y = x^2 \), or downwards if negated, like \( y = -x^2 \).
Key features of a parabola include:
Key features of a parabola include:
- The **vertex**, which is the point where the parabola changes direction.
- The **axis of symmetry** that vertically divides the parabola into two mirror images.
- The **focus** and **directrix** that help define its precise shape.
Exploring Domain and Range
The **domain** and **range** are foundational concepts in mathematics that describe the input and output of a function. For the quadratic function \( y = x^2 \), the domain is simply the set of all possible \( x \) values. The standard domain of \( y = x^2 \) is all real numbers because any real number squared remains a real number. However, in this exercise, we've been given a limited domain: \( 0 \leq x \leq 4 \).
The **range** corresponds to the possible \( y \) values that result when the \( x \) values from the domain are plugged into the function. By squaring the values at the endpoints of the domain, \( 0^2 = 0 \) and \( 4^2 = 16 \), we find the range is \( 0 \leq y \leq 16 \), as \( y \) takes all values from 0 to 16 inclusive.
Remember:
The **range** corresponds to the possible \( y \) values that result when the \( x \) values from the domain are plugged into the function. By squaring the values at the endpoints of the domain, \( 0^2 = 0 \) and \( 4^2 = 16 \), we find the range is \( 0 \leq y \leq 16 \), as \( y \) takes all values from 0 to 16 inclusive.
Remember:
- **Domain**: The set of all possible independent variable (usually \( x \)) values.
- **Range**: The resulting set of dependent variable (usually \( y \)) values after applying the function on the domain.
Vertex of a Parabola
The vertex of a parabola is a pivotal point and is often the starting reference point when discussing quadratic graphs. For the function \( y = x^2 \), the vertex is at the point \( (0, 0) \). This is the lowest point on the graph of a parabola that opens upwards, and the highest point for one that opens downwards.
In general, the vertex of a parabola described by a quadratic function \( y = ax^2 + bx + c \) can be found using the formula for the \( x \)-coordinate of the vertex: \( x = -\frac{b}{2a} \).
Once the \( x \)-coordinate is known, substitute it back into the equation to find the corresponding \( y \)-coordinate. Thus, the vertex provides a key piece of information required to sketch the parabola or optimize quadratic expressions.
Points to remember:
In general, the vertex of a parabola described by a quadratic function \( y = ax^2 + bx + c \) can be found using the formula for the \( x \)-coordinate of the vertex: \( x = -\frac{b}{2a} \).
Once the \( x \)-coordinate is known, substitute it back into the equation to find the corresponding \( y \)-coordinate. Thus, the vertex provides a key piece of information required to sketch the parabola or optimize quadratic expressions.
Points to remember:
- The **vertex** is located at the minimum or maximum point of the parabola, depending on its orientation.
- Alterations in the quadratic function can shift the vertex, changing its position on the graph.
Other exercises in this chapter
Problem 25
Check to see if \(b=8\) is or is not a solution of the inequality. $$ 37 \geq 4 b $$
View solution Problem 26
Evaluate the expression for the given value of the variable. \(8 a\) when \(a=6\)
View solution Problem 26
Check to see if x = 5 is or is not a solution of the equation or the inequality. $$ 17-x
View solution Problem 26
Evaluate the power. \(10^{3}\)
View solution