Problem 26
Question
Tennis \(A\) 2-oz tennis ball was served at 160 \(\mathrm{ft} /\) sec (about 109 \(\mathrm{mph}\) ). How much work was done on the ball to make it go this fast? (To find the ball's mass from its weight, express the weight in pounds and divide by \(32 \mathrm{ft} / \mathrm{sec}^{2},\) the acceleration of gravity.)
Step-by-Step Solution
Verified Answer
The work done is approximately 50 ft-lbs.
1Step 1: Convert the Weight to Pounds
The weight of the tennis ball is given as 2 ounces. We will first convert this to pounds. Since 1 pound equals 16 ounces, we have: \[ \text{Weight in pounds} = \frac{2 \text{ oz}}{16} = 0.125 \text{ lbs} \]
2Step 2: Calculate the Mass of the Ball
Use the weight in pounds to calculate the mass. Mass is calculated by dividing the weight by the acceleration due to gravity (32 ft/s²): \[ \text{Mass} = \frac{0.125 \text{ lbs}}{32 \text{ ft/s}^2} \approx 0.00390625 \text{ slugs} \]
3Step 3: Use Kinetic Energy Formula
The work done on the tennis ball to bring it to the serving speed of 160 ft/sec can be equated to its kinetic energy at that speed. Kinetic energy is given by the formula: \[ KE = \frac{1}{2}mv^2 \]where \( m \) is mass and \( v \) is velocity. Substituting the values: \[ KE = \frac{1}{2} \times 0.00390625 \text{ slugs} \times (160 \text{ ft/s})^2 \]
4Step 4: Compute Kinetic Energy (Work Done)
Now calculate the work done:\[ KE = \frac{1}{2} \times 0.00390625 \times 25600 \approx 50 \text{ ft-lbs} \]This value represents the amount of work done on the tennis ball to accelerate it to the given speed.
Key Concepts
Kinetic EnergyUnit ConversionMass and WeightAcceleration Due to Gravity
Kinetic Energy
Kinetic energy is a fundamental concept in physics that describes the energy an object possesses due to its motion. When an object moves, it can do work on other objects and this is quantified by its kinetic energy.
Kinetic energy is calculated using the formula:
Kinetic energy is calculated using the formula:
- \[ KE = \frac{1}{2}mv^2 \]
- Here, \( KE \) represents kinetic energy, \( m \) is the mass of the object, and \( v \) is the velocity.
Unit Conversion
Unit conversion is an important aspect when solving physics problems involving different measurement units.
In our exercise, the process starts with the conversion of the tennis ball's weight from ounces to pounds. This is necessary because standard equations in physics often require weights to be in consistent units:
In our exercise, the process starts with the conversion of the tennis ball's weight from ounces to pounds. This is necessary because standard equations in physics often require weights to be in consistent units:
- Weight in pounds is calculated as \( \frac{2 \text{ oz}}{16} = 0.125 \text{ lbs} \).
Mass and Weight
Understanding the difference between mass and weight is key in physics.
- Weight is the force exerted by gravity on an object, while mass is the measure of the amount of matter in that object.
- Weight depends on the gravitational pull and is calculated as the product of mass and gravitational acceleration.
- \( \text{Mass} = \frac{0.125 \text{ lbs}}{32 \text{ ft/s}^2} \).
Acceleration Due to Gravity
The acceleration due to gravity is a constant that appears in many physics equations.
- On Earth, its value is approximately \( 32 \text{ ft/s}^2 \) or \( 9.8 \text{ m/s}^2 \) depending on the unit system.
- This constant converts weight (a force) to mass for calculations, ensuring accurate results in physics problems.
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