Problem 26
Question
Suppose that 5 percent of men and .25 percent of women are color blind. A color-blind person is chosen at random. What is the probability of this person being male? Assume that there are an equal number of males and females. What if the population consisted of twice as many males as females?
Step-by-Step Solution
Verified Answer
When there are an equal number of males and females, the probability of the color-blind person being male is approximately \(0.952381\). If there are twice as many males as females, the probability increases to approximately \(0.975823\).
1Step 1: Identify the Given Probabilities
We are given that 5 percent of men are color blind, and .25 percent of women are color blind. These values can be expressed as:
P(Color blind | Male) = 0.05
P(Color blind | Female) = 0.0025
Step 2: Calculate the Prior Probabilities
2Step 2: Calculate the Prior Probabilities
In this case, we have an equal number of males and females. This means that the prior probabilities are:
P(Male) = 0.5
P(Female) = 0.5
Step 3: Calculate the Joint Probabilities
3Step 3: Calculate the Joint Probabilities
Now calculate the joint probabilities, by multiplying the conditional probabilities by the respective prior probabilities:
P(Color blind, Male) = P(Color blind | Male) * P(Male) = 0.05 * 0.5 = 0.025
P(Color blind, Female) = P(Color blind | Female) * P(Female) = 0.0025 * 0.5 = 0.00125
Step 4: Calculate the Marginal Probability
4Step 4: Calculate the Marginal Probability
Calculate the marginal probability of a color-blind person:
P(Color blind) = P(Color blind, Male) + P(Color blind, Female) = 0.025 + 0.00125 = 0.02625
Step 5: Calculate the Probability of Male Given Color Blindness
5Step 5: Calculate the Probability of Male Given Color Blindness
Finally, using Bayes' theorem, find the probability of a color-blind person being male:
P(Male | Color blind) = P(Color blind, Male) / P(Color blind) = 0.025 / 0.02625 ≈ 0.952381
For the case where there are twice as many males as females:
Step 6: Update the Prior Probabilities
6Step 6: Update the Prior Probabilities
When there are twice as many males as females in the population, the prior probabilities are:
P(Male) = 1/3
P(Female) = 2/3
Step 7: Recalculate the Joint Probabilities
7Step 7: Recalculate the Joint Probabilities
Recalculate the joint probabilities:
P(Color blind, Male) = 0.05 * 2/3 ≈ 0.03333
P(Color blind, Female) = 0.0025 * 1/3 ≈ 0.00083
Step 8: Recalculate the Marginal Probability
8Step 8: Recalculate the Marginal Probability
Recalculate the marginal probability of a color-blind person:
P(Color blind) = 0.03333 + 0.00083 = 0.03416
Step 9: Recalculate the Probability of Male Given Color Blindness
9Step 9: Recalculate the Probability of Male Given Color Blindness
Recalculate the probability using Bayes' theorem:
P(Male | Color blind) = 0.03333 / 0.03416 ≈ 0.975823
So when there are an equal number of males and females, the probability of the color-blind person being male is approximately 0.952381. If there are twice as many males as females, the probability increases to approximately 0.975823.
Key Concepts
Conditional ProbabilityJoint ProbabilityMarginal ProbabilityBayes' Theorem
Conditional Probability
Conditional probability helps us calculate the likelihood of an event happening when we know that another event has already occurred.
In this problem, we are given that a certain percentage of men and women are color blind. These are expressed as conditional probabilities:
In this problem, we are given that a certain percentage of men and women are color blind. These are expressed as conditional probabilities:
- \( P(\text{Color blind} \mid \text{Male}) = 0.05 \)
- \( P(\text{Color blind} \mid \text{Female}) = 0.0025 \)
Joint Probability
Joint probability is all about finding the probability of two or more events happening at the same time. In our exercise, we look at the probability of being both color blind and male or female. This is calculated using the conditional probabilities and the prior probabilities of being male or female.
The formula for joint probability is:
The formula for joint probability is:
- \( P(A \text{ and } B) = P(A \mid B) \cdot P(B) \)
- \( P(\text{Color blind, Male}) = P(\text{Color blind} \mid \text{Male}) \times P(\text{Male}) \)
- Resulting in \( P(\text{Color blind, Male}) = 0.05 \times 0.5 = 0.025 \)
Marginal Probability
Marginal probability represents the probability of an event occurring, regardless of whether another event happens. It's like taking a step back and looking at a broader picture.
In our problem, we calculate the marginal probability of a person being color blind:
In the context of this exercise, it helps establish a base for calculating conditional probabilities using Bayes' theorem. Marginal probabilities give us an overarching view of an event's likelihood.
In our problem, we calculate the marginal probability of a person being color blind:
- \( P(\text{Color blind}) = P(\text{Color blind, Male}) + P(\text{Color blind, Female}) \)
In the context of this exercise, it helps establish a base for calculating conditional probabilities using Bayes' theorem. Marginal probabilities give us an overarching view of an event's likelihood.
Bayes' Theorem
Bayes' Theorem provides a way to update our beliefs in the presence of new data. It links together conditional and marginal probabilities to give us a more complete picture.
The theorem is expressed as:
The theorem is expressed as:
- \( P(B \mid A) = \frac{P(A \mid B) \times P(B)}{P(A)} \)
- \( P(\text{Male} \mid \text{Color blind}) = \frac{P(\text{Color blind, Male})}{P(\text{Color blind})} \)
Other exercises in this chapter
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