Problem 26
Question
Solve the given nonlinear plane autonomous system by changing to polar coordinates. Describe the geometric behavior of the solution that satisfies the given initial condition(s). \(x^{\prime}=y-\frac{x}{\sqrt{x^{2}+y^{2}}}\left(4-x^{2}-y^{2}\right)\) $$ \begin{aligned} &y^{\prime}=-x-\frac{x}{\sqrt{x^{2}+y^{2}}}\left(4-x^{2}-y^{2}\right) \\ &\mathbf{X}(0)=(1,0) ; \mathbf{X}(0)=(2,0) \end{aligned} $$
Step-by-Step Solution
Verified Answer
The orbits are circles; solutions revolve clockwise with constant radii determined by their initial conditions.
1Step 1: Convert to Polar Coordinates
In polar coordinates, \( (x, y) \) becomes \( (r \cos\theta, r \sin\theta) \). We substitute these into the system:- \( x = r \cos\theta \) and \( y = r \sin\theta \).Now express the derivatives:- \( x' = r' \cos\theta - r \sin\theta \theta' \)- \( y' = r' \sin\theta + r \cos\theta \theta' \) This leads to changes in the formula for \( x' \) and \( y' \). The key is to then express these in terms of \( r \) and \( \theta \).
2Step 2: Express the System in Polar Form
Substitute the polar expressions of \( x \) and \( y \) in our original system:- \( x' = y - \frac{x}{\sqrt{x^2 + y^2}}(4 - x^2 - y^2) \)- \( y' = -x - \frac{x}{\sqrt{x^2 + y^2}}(4 - x^2 - y^2) \)Since \( \sqrt{x^2 + y^2} = r \), the system translates to:- \( r' = 0 \)- \( \theta' = -1 \)This means \( r \) is constant and only \( \theta \) varies linearly over time.
3Step 3: Analyze Initial Conditions
Given the initial conditions \( \mathbf{X}(0) = (1,0) \) and \( \mathbf{X}(0) = (2,0) \), we convert to polar coordinates:- For \( (1,0) \), \( r = 1 \) and \( \theta = 0 \).- For \( (2,0) \), \( r = 2 \) and \( \theta = 0 \).Since \( r' = 0 \), the radius doesn't change, the behavior is a rotation with radius \( 1 \) and \( 2 \) respectively.
4Step 4: Describe the Geometric Behavior
The solutions describe circles centered at the origin. For the initial condition \( (1,0) \), the solution is a circle of radius 1. Similarly, for \( (2,0) \), it is a circle of radius 2. Since \( \theta' = -1 \), the motion is clockwise.
Key Concepts
Polar CoordinatesGeometric Behavior of SolutionsInitial Conditions AnalysisDynamical Systems Rotation
Polar Coordinates
Polar coordinates provide a way to represent points in a plane using a radius and an angle, which is particularly useful for circular or rotational scenarios. Instead of using the traditional Cartesian coordinates
In this exercise, converting to polar coordinates simplifies our nonlinear system greatly. \( r \) represents the distance of the point from the origin, while \( \theta \) is the angle from the positive \( x \)-axis. This enables analysis in terms of radii and angles, revealing underlying patterns or symmetries.
- Cartesian: given as \( (x, y) \)
- Polar: expressed as \( (r \cos \theta, r \sin \theta) \)
In this exercise, converting to polar coordinates simplifies our nonlinear system greatly. \( r \) represents the distance of the point from the origin, while \( \theta \) is the angle from the positive \( x \)-axis. This enables analysis in terms of radii and angles, revealing underlying patterns or symmetries.
Geometric Behavior of Solutions
When analyzing geometric behavior, the focus is on how the solutions evolve over time. The expressions \( r' = 0 \) and \( \theta' = -1 \) derived from polar transformations reveal key insights:
The evolution is predictable and regular, often translating complex nonlinear motions into simple circular paths.
- \( r' = 0 \): The radius remains constant; points do not move closer to or further from the origin.
- \( \theta' = -1 \): The angular rate (or change in direction) is constant, indicating uniform rotation.
The evolution is predictable and regular, often translating complex nonlinear motions into simple circular paths.
Initial Conditions Analysis
Initial conditions are crucial as they set the starting point for determining the trajectory of solutions. Here,\( \mathbf{X}(0) = (1,0) \) and \( \mathbf{X}(0) = (2,0) \) call for an initial analysis.
For \( (1,0) \):
For \( (1,0) \):
- Convert to polar: \( r = 1 \), \( \theta = 0 \)
- Implies a circular path with radius 1
- Convert to polar: \( r = 2 \), \( \theta = 0 \)
- Implies a circular path with radius 2
Dynamical Systems Rotation
Rotational dynamics refer to the circular movement derived from the system's equations. In this case, the system is described by
Because \( \theta \) changes linearly with time, the circle traverses steadily. The direction is counterclockwise if \( \theta' > 0 \), otherwise clockwise.
These polar dynamics imply a complete understanding of movements typical in systems, ensuring clear visualizations and precise forecasts.
- \( r' = 0 \) - no radial change
- \( \theta' = -1 \) - negative sign denotes clockwise rotation.
Because \( \theta \) changes linearly with time, the circle traverses steadily. The direction is counterclockwise if \( \theta' > 0 \), otherwise clockwise.
These polar dynamics imply a complete understanding of movements typical in systems, ensuring clear visualizations and precise forecasts.
Other exercises in this chapter
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