Problem 26
Question
Solve the given equation. $$ \frac{r}{3 r-1}=4 $$
Step-by-Step Solution
Verified Answer
The short answer to solving the equation \(\frac{r}{3r-1} = 4\) is to first clear the fraction by multiplying both sides by (3r-1), then simplify the equation to get \(r = 12r - 4\). Next, isolate r by subtracting 12r from both sides, yielding \(-11r=-4\). Finally, divide both sides by -11 to get the solution \(r = \frac{4}{11}\).
1Step 1: Clear the fraction.
To clear the fraction, we have to multiply both sides of the equation by the denominator (3r - 1). This will give us a linear equation without the fraction.
\((3r - 1) \cdot \frac{r}{3r - 1} = 4 \cdot (3r - 1)\)
2Step 2: Simplify the equation.
Now, we can simplify the left side of the equation by cancelling out the (3r - 1) terms, and expand the right side of the equation using the distributive property.
\(r = 12r - 4\)
3Step 3: Solve for r.
In order to isolate r, we need to move all the terms with r on one side of the equation. Let's subtract 12r from both sides of the equation.
\(r - 12r = - 4\)
This simplifies to:
\(-11r = - 4\)
Now, we'll divide both sides by -11 to isolate r.
\(\frac{-11r}{-11} = \frac{-4}{-11}\)
This gives us the final solution:
\(r = \frac{4}{11}\)
Key Concepts
Linear EquationsFractional EquationsEquation SimplificationDistributive Property
Linear Equations
Linear equations are equations of the first degree, meaning they involve variables raised only to the power of one. They are fundamental in algebra and appear in the form \(ax + b = c\). To solve linear equations, we aim to isolate the variable on one side of the equation, resulting in a simple expression. This involves the application of inverse operations to manipulate the equation without altering its equality.
- Start by getting rid of fractions, if any.
- Use addition or subtraction to move terms with the variable to one side.
- Use multiplication or division to isolate the variable.
Fractional Equations
Fractional equations contain fractions with variables in the numerator, denominator, or both. Solving these can seem more complex but can be simplified effectively. The key is to get rid of the fraction by applying a clear method, often multiplying through by the least common denominator (LCD) of all fractions involved.
In our specific exercise, the equation \(\frac{r}{3r-1}=4\) involves a fraction that can be handled by multiplying every term by the denominator \(3r - 1\). This step clears the fraction and transforms the equation into a more straightforward linear equation.
In our specific exercise, the equation \(\frac{r}{3r-1}=4\) involves a fraction that can be handled by multiplying every term by the denominator \(3r - 1\). This step clears the fraction and transforms the equation into a more straightforward linear equation.
- Multiply each term by the LCD to eliminate fractions.
- Simplify and rearrange the equation as needed.
Equation Simplification
Simplifying equations is a crucial step when solving algebraic problems. This means reducing an equation to its simplest form, making it easier to solve. In the context of the given exercise, simplifying involves canceling terms and collecting like terms.
- Identify and cancel out common factors on both sides of the equation.
- Combine like terms to reduce complexity.
- Ensure all terms are as simplified as possible without losing equality.
Distributive Property
The distributive property is a fundamental algebraic principle used to simplify and solve equations. It states that \(a(b + c) = ab + ac\). This property becomes very handy when one needs to eliminate parentheses or expand expressions.
In applying it to the exercise, when multiplying \((3r - 1)\) with 4 on the right-hand side, it becomes \(12r - 4\). This expansion is crucial to solve for the variable without altering the equation's balance.
In applying it to the exercise, when multiplying \((3r - 1)\) with 4 on the right-hand side, it becomes \(12r - 4\). This expansion is crucial to solve for the variable without altering the equation's balance.
- Apply the distributive property to eliminate parentheses and distribute coefficients.
- Ensure to distribute every term inside the bracket.
Other exercises in this chapter
Problem 26
Carry out the indicated operation and write your answer using positive exponents only. $$ \frac{4^{1 / 3} \cdot 4^{-2 / 5}}{4^{2 / 3}} $$
View solution Problem 26
Simplify the expression, writing your answer using positive exponents only. $$ \left(-a^{2}\right)^{-3} $$
View solution Problem 26
In Exercises, factor the polynomial. If the polynomial is prime, state it. $$ 3 m^{3}+3 m^{2}-18 m $$
View solution Problem 26
State the real number property that iustifies the statement $$ -(2 x+y)[-(3 x+2 y)]=(2 x+y)(3 x+2 y) $$
View solution