Problem 26
Question
Solve the following equations and tick the correct one. If \(\tan 2 x \cdot \tan x=1\), then \(x\) is (a) \(\frac{\pi}{3}\) (b) \((6 n \pm 1) \frac{\pi}{6}\) (c) \((4 n \pm 1) \frac{\pi}{6}\) (d) \((2 n \pm 1) \frac{\pi}{6}\)
Step-by-Step Solution
Verified Answer
The correct answer is (d).
1Step 1: Simplify the given equation
We will start by simplifying the given equation. The formula to convert double angles in terms of single angles for tan can be used here. The formula is \(\tan 2a = \frac{2\tan a}{1 - \tan^2 a}\). Substitute \(\tan 2x\) using this formula. We get \(\frac{2 \tan x}{1 - \tan^2 x} \cdot \tan x=1\) or \(\frac{2 \tan^2 x}{1 - \tan^2 x}=1.\)
2Step 2: Solve the equation further
Next step will be to solve this equation for \(\tan x\). After further simplification, we get \(\tan^2 x = \frac{1}{2}\) or \(\tan x = \pm\sqrt{1/2}\). This implies that \(x\) can be \(n\pi \pm \frac{\pi}{4}\).
3Step 3: Match against the options
The last step is to match the values of \(x\) with the available options. Looking at the options, we find a match with the option (d) \((2 n \pm 1) \frac{\pi}{6}\), where \(n\) is an integer.
4Step 4: Verify
To ensure the option (d) is correct, we can also put the value of \(x\) from (d) back into the equation to verify it. After substituting the values, it can be verified that both sides of equation matches. Hence, the solution for \(x\) is indeed (d).
Key Concepts
tan double angle formulasolving equationstrigonometric identities
tan double angle formula
The tan double angle formula is a crucial concept in trigonometry. It allows us to express the tangent of a double angle in terms of the tangent of a single angle. This formula is given by:
For instance, in the exercise given, we substitute \( \tan 2x \) using this formula. Doing so helps us convert the equation into a manageable form that is easier to solve. Understanding this formula can also help you recognize when an equation's complexity can be reduced.
Remember, the formula can only be applied when the expression matches its structure, so look for a double angle and a single angle in your equation.
- \( \tan 2a = \frac{2 \tan a}{1 - \tan^2 a} \)
For instance, in the exercise given, we substitute \( \tan 2x \) using this formula. Doing so helps us convert the equation into a manageable form that is easier to solve. Understanding this formula can also help you recognize when an equation's complexity can be reduced.
Remember, the formula can only be applied when the expression matches its structure, so look for a double angle and a single angle in your equation.
solving equations
Solving equations involving trigonometric functions requires substituting known identities and simplifying the given expressions. In our exercise, after using the tan double angle formula, we obtained the equation:
- \( \frac{2 \tan^2 x}{1 - \tan^2 x} = 1 \)
- Isolate the trigonometric function \( \tan x \).
- Simplify the expression to find \( \tan^2 x \).
- Finally, solve for \( \tan x \).
- \( \tan^2 x = \frac{1}{2} \)
- This simplifies to \( \tan x = \pm \sqrt{\frac{1}{2}} \).
trigonometric identities
Trigonometric identities are fundamental tools in the simplification and solution of trigonometric equations. They are equations involving trigonometric functions that are true for all values of the variable for which they are defined. Here are a few key identities frequently used:
By recognizing which identities match the given components of a problem, you can transform unwieldy expressions into simpler ones that pave the way for finding solutions.
- \( \tan^2 a + 1 = \sec^2 a \)
- \( \sin^2 a + \cos^2 a = 1 \)
- \( 1 + \cot^2 a = \csc^2 a \)
By recognizing which identities match the given components of a problem, you can transform unwieldy expressions into simpler ones that pave the way for finding solutions.
Other exercises in this chapter
Problem 25
Solve the following equations and tick the correct one. If \(\cos p \theta+\cos q \theta=0\), then the different values of \(\theta\) are in A.P., whose common
View solution Problem 25
Solve: \(\sin 2 x+\sin x+\cos 2 x+\cos x+1=0\)
View solution Problem 26
Solve: \(\cos x \cos 2 x \cos 4 x=\frac{1}{4}\) \(0 \leq x \leq \pi\)
View solution Problem 27
Solve the following equations and tick the correct one. The maximum value of \(5 \sin \theta+3 \sin (\theta-\alpha)\) is 7 , then the set of all possible values
View solution