Problem 26
Question
Solve quadratic equation by completing the square. \(x^{2}=5 x-3\)
Step-by-Step Solution
Verified Answer
The solutions to the given quadratic equation are \(x = 2.5 + \sqrt{9.25}\) and \(x = 2.5 - \sqrt{9.25}\).
1Step 1: Rearrange the equation
First, the original equation \(x^{2} - 5x + 3 = 0\) needs to be rearranged to the form \(x^2 - 5x = 3\).
2Step 2: Complete the square
The quadratic term in the equation needs to be completed by adding the square of half the coefficient of 'x'. Therefore, add \(\left(\frac{-5}{2}\right)^2 = 6.25\) to both sides to get \((x - 2.5)^2 = 9.25\).
3Step 3: Find the value of 'x'
Finally, to find 'x', take the square root of both sides. Since the square root has both a positive and negative value, there are two possible solutions. \nTherefore, the solutions would be \(x = 2.5 + \sqrt{9.25}\) and \(x = 2.5 - \sqrt{9.25}\).
Key Concepts
Completing the SquareQuadratic FormulaAlgebraic Manipulation
Completing the Square
Completing the square is a method used to solve quadratic equations by transforming a quadratic expression into a perfect square trinomial. This method is beneficial when a quadratic equation doesn't factor easily. The goal is to rewrite the equation in such a way that it becomes easier to solve for the variable.
To complete the square, follow these steps:
This method is especially useful for deriving other forms of the quadratic formula and is a fundamental concept in algebra.
To complete the square, follow these steps:
- Ensure the quadratic equation is in the form \[x^2 + bx + c = 0\]
- Move the constant term to the other side: \[x^2 + bx = -c\]
- Calculate and add \[\left(\frac{b}{2}\right)^2\] to both sides to form a perfect square trinomial.
- This changes the left side of the equation to \[(x + \frac{b}{2})^2\]
This method is especially useful for deriving other forms of the quadratic formula and is a fundamental concept in algebra.
Quadratic Formula
The quadratic formula is a universal tool for solving any quadratic equation of the form \[ax^2 + bx + c = 0\]. This method doesn't rely on factoring and can solve any type of quadratic equation when the equation is difficult to factor.
The formula is: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
- \(b^2 - 4ac \) is the discriminant, determining the nature of the roots.
Here's how it works:
It complements other solving methods like completing the square, particularly when manual calculations are complex.
The formula is: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
- \(b^2 - 4ac \) is the discriminant, determining the nature of the roots.
Here's how it works:
- Identify values of \(a\), \(b\), and \(c\) from the quadratic equation.
- Plug these values into the formula.
- Calculate the discriminant \(b^2 - 4ac\).
- Evaluate the solutions which could be real or complex.
It complements other solving methods like completing the square, particularly when manual calculations are complex.
Algebraic Manipulation
Algebraic manipulation involves rearranging and simplifying equations or expressions to make them easier to work with or solve. It's a fundamental technique in solving equations, especially quadratics.
Key techniques include:
This rearrangement is essential for applying methods like completing the square or the quadratic formula.
Algebraic manipulation lays the groundwork for solving equations systematically. Mastering these techniques improves understanding and effectiveness in dealing with various algebraic problems.
Key techniques include:
- Rearranging terms to isolate the variable.
- Combining like terms to simplify expressions.
- Factoring to express an equation in simpler terms.
This rearrangement is essential for applying methods like completing the square or the quadratic formula.
Algebraic manipulation lays the groundwork for solving equations systematically. Mastering these techniques improves understanding and effectiveness in dealing with various algebraic problems.
Other exercises in this chapter
Problem 26
Graph the parabola whose equation is given $$y=x^{2}+10 x+9$$
View solution Problem 26
In solving \(\sqrt{2 x-1}+2=x,\) why is it a good idea to isolate the radical term? What if we don't do this and simply square each side? Describe what happens.
View solution Problem 26
Solve each quadratic equation by the square root property. If possible, simplify radicals or rationalize denominators. $$(x-3)^{2}=15$$
View solution Problem 26
Solve each quadratic equation using the quadratic formula. $$x^{2}+2 x+2=0$$
View solution