Problem 26
Question
Solve each system of equations by the addition method. If a system contains fractions or decimals, you may want to first clear each equation of fractions or decimals.$$ \left\\{\begin{array}{l} 6 x-5 y=7 \\ 4 x-6 y=7 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{7}{16}\) and \(y = \frac{-7}{8}\).
1Step 1: Align the System of Equations
First, write the system of equations clearly, aligning the equations one below the other: \(6x - 5y = 7\) \(4x - 6y = 7\).
2Step 2: Equalize Coefficients
For the addition method, we need to have the coefficients of either \(x\) or \(y\) be opposites. We'll eliminate \(x\) by making the coefficients of \(x\) in both equations equal. Multiply the first equation by 2 and the second equation by 3:\( (2)(6x - 5y) = (2)(7)\) giving \(12x - 10y = 14\) \( (3)(4x - 6y) = (3)(7)\) giving \(12x - 18y = 21\).
3Step 3: Subtract Equations
Since both equations have the same \(x\) term after adjustment, subtract the second modified equation from the first modified equation. \( (12x - 10y) - (12x - 18y) = 14 - 21\)which simplifies to:\(8y = -7\).
4Step 4: Solve for y
Divide both sides of the equation by 8:\(y = \frac{-7}{8}\).
5Step 5: Substitute and Solve for x
Substitute \(y = \frac{-7}{8}\) back into the original first equation to solve for \(x\):\(6x - 5\left(\frac{-7}{8}\right) = 7\)which simplifies to:\(6x + \frac{35}{8} = 7\)Subtract \(\frac{35}{8}\) from both sides:\(6x = 7 - \frac{35}{8}\).Convert 7 to a fraction: \(\frac{56}{8}\), so\(6x = \frac{56}{8} - \frac{35}{8} = \frac{21}{8}\).Divide by 6:\(x = \frac{21}{8 \times 6} = \frac{7}{16}\).
Key Concepts
Addition MethodSolving Equations with FractionsEliminating VariablesAligning Equations
Addition Method
The addition method, sometimes called the elimination method, is a technique used to solve systems of linear equations. It involves combining the equations in order to eliminate one of the variables. This is done by adding or subtracting the equations to cancel out one variable, making it easier to solve for the other.
Here’s how it works:
Here’s how it works:
- Choose which variable you want to eliminate, either the x or the y.
- Modify the equations so that the coefficients of this chosen variable are opposites.
- Add or subtract the equations to eliminate the chosen variable.
Solving Equations with Fractions
Fractions can make solving equations a bit more challenging, mainly due to the arithmetic involved. However, with a systematic approach, they can be handled efficiently. Here are some tips:
- If the equation includes fractions, consider clearing them first by multiplying both sides of the equation by a common denominator.
- This simplification helps prevent arithmetic errors and makes the equations look simpler.
- Once the fractions are cleared, proceed with solving the system using the addition or substitution method.
Eliminating Variables
Eliminating one variable from a system of equations simplifies the problem, narrowing down the number of equations you’re dealing with. This approach utilizes the addition method to make coefficients opposites for one of the variables, allowing for elimination.
Steps to eliminate a variable:
Steps to eliminate a variable:
- Decide on which variable to eliminate from both equations.
- Adjust the coefficients by multiplying the equations with necessary constants so that they become opposites.
- Add or subtract the equations to cancel the chosen variable.
Aligning Equations
Aligning equations is the first step in systematically solving a system. By writing them out clearly, one under the other, you ensure organization, which helps in accurately proceeding with more complex operations.
- Begin by writing each equation so that similar terms (like variables) are vertically aligned.
- This visual clarity makes it easier to spot opportunities for manipulation, such as multiplication, addition, or subtraction.
- Good alignment aids in identifying which coefficients to adjust, as it shows the interaction between corresponding terms clearly.
Other exercises in this chapter
Problem 25
Solve each system of equations by the substitution method. $$ \left\\{\begin{array}{l} 3 x-y=1 \\ 2 x-3 y=10 \end{array}\right. $$
View solution Problem 25
Pratap Puri rowed 18 miles down the Delaware River in 2 hours, but the return trip took him \(4 \frac{1}{2}\) hours. Find the rate Pratap can row in still water
View solution Problem 26
Solve each system of equations by the substitution method. $$ \left\\{\begin{array}{l} 2 x-y=-7 \\ 4 x-3 y=-11 \end{array}\right. $$
View solution Problem 26
The Jonathan Schultz family took a canoe 10 miles down the Allegheny River in \(1 \frac{1}{4}\) hours. After lunch it took them 4 hours to return. Find the rate
View solution