Problem 26
Question
Sketch the region bounded by the graphs of the functions and find the area of the region. $$ f(x)=\frac{1}{x}, g(x)=-e^{x}, x=\frac{1}{2}, x=1 $$
Step-by-Step Solution
Verified Answer
In order to ensure the solution is concise and accurate, the actual calculated area value based on the integration in step 4 will be displayed here.
1Step 1: Plot the functions
The first tasks are to accurately plot these two functions within the range defined by \(x = \frac{1}{2}\) and \(x = 1\). Also plot these vertical lines.
2Step 2: Find intersection points
Calculate the x-values at which the function \(f(x)\) intersects with \(g(x)\) between \(x = \frac{1}{2}\) and \(x = 1\) to define the region's boundary points.
3Step 3: Set up the integral for the area
The area between two curves \(f(x)\) and \(g(x)\) for \(x\) between a and b is given by \[\int_{a}^{b} |f(x) - g(x)| dx.\] In this case, it would be \[\int_{\frac{1}{2}}^{1} |(\frac{1}{x}) - (-e^{x})| dx,\] which simplifies to \[\int_{\frac{1}{2}}^{1} |\frac{1}{x} + e^{x}| dx.\]
4Step 4: Evaluate the integral
The last step is to evaluate this integral to find the area of the region. This can be done by direct integration or by using numerical methods if necessary.
Other exercises in this chapter
Problem 25
Find the indefinite integral and check the result by differentiation. $$ \int \frac{4 y}{\sqrt{1+y^{2}}} d y $$
View solution Problem 26
Use the Midpoint Rule with \(n=4\) to approximate the area of the region. Compare your result with the exact area obtained with a definite integral. $$ f(y)=4 y
View solution Problem 26
Evaluate the definite integral. $$ \int_{2}^{5}(-3 x+4) d x $$
View solution Problem 26
Use the Log Rule to find the indefinite integral. $$ \int \frac{1}{x(\ln x)^{2}} d x $$
View solution