Problem 26
Question
Sketch the graph of each function. $$f(x)=5+2 e^{x}$$
Step-by-Step Solution
Verified Answer
The graph of the function has a y-intercept at \(y = 7\), and it rises indefinitely as \(x\) increases, and approaches a horizontal line as \(x\) decreases. Actual y-values depend on specific x-values taken, and should be accurately calculated for precise sketching.
1Step 1: Determine the y-intercept
The y-intercept of the graph will occur when \(x = 0\). Therefore, substituting \(x = 0\) into the function, the y-intercept can be found as \(f(0) = 5 + 2 * e^0 = 5 + 2 = 7\).
2Step 2: Choose a set of x-values
Now, choose some x-values to determine the shape of the function. Note that since it is an exponential function, it is useful to choose both negative and positive x-values. Let's choose -2, -1, 0, 1, 2.
3Step 3: Compute corresponding y-values
The y-values will be found by substituting each chosen x-value into the function, the y-values will be -2: \(f(-2) = 5 + 2 * e^{-2}\), -1: \(f(-1) = 5 + 2 * e^{-1}\), 0: \(f(0) = 7\) (from the previous step), 1: \(f(1) = 5+2 * e^{1}\), and 2: \(f(2) = 5+2 * e^{2}\) approximately.
4Step 4: Sketch the graph
Now use the computed points to sketch the graph, keeping in mind that as an exponential function, the graph will approach a horizontal asymptote as \(x\) approaches negative infinity, and it will rise indefinitely as \(x\) approaches positive infinity.
Key Concepts
Graphing FunctionsY-interceptHorizontal AsymptoteExponential Growth
Graphing Functions
Graphing functions can be a fun and intuitive process, especially with exponential functions. To graph a function, follow these steps:
- First, understand the general shape of the function you are dealing with. For exponential functions like \(f(x) = 5 + 2e^x\), the graph tends to rise steeply as \(x\) increases and flattens towards a horizontal asymptote as \(x\) decreases.
- Next, determine critical points such as the y-intercept by setting \(x = 0\).
- Then, evaluate the function at several x-values, both positive and negative, to get a sense of the graph's behavior and shape.
- Finally, plot these points and sketch a smooth curve through them, keeping the growth pattern of the function in mind.
Y-intercept
The y-intercept of a graph is crucial because it tells us where the function crosses the y-axis. For the function \(f(x) = 5 + 2e^x\), the y-intercept is found by substituting \(x = 0\). This means you look at \(f(0) = 5 + 2e^0\).
- Since \(e^0 = 1\), you simply calculate \(f(0) = 5 + 2 \times 1 = 7\).
- This tells us that when \(x = 0\), \(f(x) = 7\), so the y-intercept is the point (0, 7).
Horizontal Asymptote
A horizontal asymptote refers to a line that a graph approaches but never quite reaches as \(x\) moves towards positive or negative infinity. For an exponential function like \(f(x) = 5 + 2e^x\), the constant term 5 identifies the horizontal asymptote. This is because as \(x\) approaches negative infinity, \(2e^x\) approaches zero.
- Thus, the horizontal asymptote is the line \(y = 5\).
- This means that as \(x\) becomes very negative, the function approaches a value of 5, but never dips below.
Exponential Growth
Exponential growth is a hallmark of functions like \(f(x) = 5 + 2e^x\). These functions are characterized by rapid increases in value as \(x\) becomes larger. This happens because the base of the exponential function, in this case \(e\), is greater than one.
- As \(x\) increases, \(e^x\) grows quickly, causing \(f(x)\) to increase without bound.
- This is evident in the graph, where the curve steeply rises as it moves rightward.
Other exercises in this chapter
Problem 26
In Exercises \(21-30,\) write each logarithm as a sum and\or difference of logarithmic expressions. Eliminate exponents and radicals and evaluate logarithms whe
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Evaluate each expression without using a calculator. $$\ln e^{w}$$
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It takes 5700 years for an initial amount \(A_{0}\) of carbon- 14 to break down into half the amount, \(\frac{A_{0}}{2}\) (a) Given an initial amount of \(A_{0}
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Solve the exponential equation. Round to three decimal places, when needed. $$e^{x^{2}+1}-2=3$$
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