Problem 26
Question
Simplify each expression by taking as much out from under the radical as possible. You may assume that all variables represent positive numbers $$\sqrt{72 x^{4} y^{2}}$$
Step-by-Step Solution
Verified Answer
The simplified expression is \(6x^2y\sqrt{2}\).
1Step 1: Break Down the Expression Under the Radical
Start by factoring the components inside the radical. Rewrite the expression under the square root as a product of perfect squares. The expression \(72x^4y^2\) can be broken down to \(36 \times 2 \times x^4 \times y^2\). Notice that \(36\) is a perfect square, as are \(x^4\) and \(y^2\).
2Step 2: Simplify the Perfect Squares
Next, take the square root of each perfect square component. The square root of \(36\) is \(6\), the square root of \(x^4\) is \(x^2\), and the square root of \(y^2\) is \(y\).
3Step 3: Simplifying the Remaining Radical
You are left with \(\sqrt{2}\) under the radical since 2 is not a perfect square. The expression at this point is \(6x^2y\sqrt{2}\).
4Step 4: Combine the Simplified Parts
Combine all the parts to express the entire radical expression in simplified form. The final simplified expression is \(6x^2y\sqrt{2}\).
Key Concepts
FactoringPerfect SquaresRadicalsAlgebra Basics
Factoring
Factoring is like breaking a number or a mathematical expression into parts, called factors, that can be multiplied to produce the original number or expression. In our exercise, the expression under the radical is \(72x^4y^2\). First, we need to factor this composite number to identify any perfect squares.
- Consider the number 72, which factors into \(36 \times 2\). Here, 36 is a perfect square \((6^2)\).
- The exponent \(x^4\) can be rewritten as \((x^2)^2\), indicating that it is also a perfect square.
- Similarly, \(y^2\) is already a perfect square \((y)^2\).
Perfect Squares
A perfect square is a number or a variable that can be expressed as the product of an integer with itself. Perfect squares play a crucial role in simplifying radical expressions as they allow us to "escape" the square root.
- In our example, 36 is a perfect square since \(6 \times 6 = 36\). Thus, the square root of 36 is simply 6.
- The variable \(x^4\) is written as \((x^2)^2\), making \(x^2\) its perfect square root.
- Similarly, \(y^2\) is already a perfect square, simplifying directly to \(y\).
Radicals
Radicals, often known as roots, represent the opposite operation of raising a number to a power. The most common radical is the square root, denoted by the symbol \(\sqrt{}\). Simplifying expressions involving radicals involves multiple steps:
- Identify any perfect squares under the radical since these can be swiftly simplified.
- The component that cannot be expressed as a perfect square, like \(\sqrt{2}\) in our example, remains under the radical symbol.
- Simplified forms like \(6x^2y\sqrt{2}\) emerge from breaking down and rebuilding the radical into simpler parts.
Algebra Basics
The foundations of algebra help us tackle expressions like \(\sqrt{72x^4y^2}\) with ease. Familiarity with core operations such as factoring, recognizing perfect squares, and working with radicals are all elements involved.
- Recognition of components that can be simplified, such as integers and powers, is essential.
- Simplification involves the gradual breakdown of expressions into basic parts, then assembling them into simpler solutions.
- Mastering these basics improves problem-solving capabilities and enhances mathematical fluency across a wide range of concepts.
Other exercises in this chapter
Problem 26
Perform each of the following divisions. $$6 . 6 \longdiv { 0 . 1 9 8 }$$
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Simplify each of the following expressions without using a calculator. $$\sqrt{\frac{100}{121}}$$
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Write each decimal as a fraction in lowest terms. $$0.06$$
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Find each of the following products. $$\begin{array}{r} 157.02 \\ \times 10,000 \\ \hline \end{array}$$
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