Problem 26
Question
Let \(W\) denote the words in the English dictionary. Define the relation \(R\) by: \([2006]\) \(R=\\{(x, y) \in W \times W \mid\) the words \(x\) and \(y\) have at least one letter in common\\}. Then \(R\) is (A) not reflexive, symmetric and transitive (B) reflexive, symmetric and not transitive (C) reflexive, symmetric and transitive (D) reflexive, not symmetric and transitive
Step-by-Step Solution
Verified Answer
(B) reflexive, symmetric and not transitive
1Step 1: Understanding Reflexivity
A relation is reflexive if every element is related to itself. Here, for a word \( x \) in \( W \), \( (x, x) \) must be in \( R \) for the relation to be reflexive. Since every word has letters in common with itself, \( R \) is reflexive.
2Step 2: Checking Symmetry
A relation is symmetric if whenever \( (x, y) \in R \), then \( (y, x) \in R \) as well. If two words \( x \) and \( y \) have a letter in common, then \( y \) and \( x \) also share that letter, making \( R \) symmetric.
3Step 3: Evaluating Transitivity
A relation is transitive if whenever \( (x, y) \in R \) and \( (y, z) \in R \), then \( (x, z) \in R \). For words \( x, y, \) and \( z \) to have transitive relationships, a shared letter between \( x \) and \( y \) and another between \( y \) and \( z \) doesn't guarantee \( x \) and \( z \) have a common letter, so \( R \) is not transitive.
Key Concepts
Symmetric RelationTransitive RelationSet Theory
Symmetric Relation
In mathematical terms, a **symmetric relation** over a set is a relation where if one element is related to another, the reverse is also true. In this context of the provided exercise, we have a set of words where a relation \( R \) is defined based on the common letters between any two words. To determine symmetry for this relation, we consider any two words \( x \) and \( y \) within the set of words, \( W \).
- If \( x \) and \( y \) share at least one letter, represented as \((x, y) \in R\), then it's evident that \( y \) and \( x \) would also share that same letter.
- This symmetrical nature implies \( (y, x) \in R \) as well.
Transitive Relation
A **transitive relation** relates to chaining a connection through an intermediate element. In the given problem, we analyzed a relation \( R \) concerning words. You'd typically think a relation might be transitive in a setting where a shared characteristic links more than two elements.
Transitivity is a key property in many areas of mathematics but is context-sensitive, making it crucial to verify each case independently. Events in real-life where transitivity holds true include genealogy or hierarchies, such as if A is an ancestor of B, and B is an ancestor of C, then A is an ancestor of C.
- For words \( x, y, \) and \( z \) in the set \( W \), if \( (x, y) \in R \) (\( x \) shares a letter with \( y \)), and \( (y, z) \in R \) (\( y \) shares a letter with \( z \)), logic might suggest that \( x \) and \( z \) should also share a letter for the relation to be transitive.
Transitivity is a key property in many areas of mathematics but is context-sensitive, making it crucial to verify each case independently. Events in real-life where transitivity holds true include genealogy or hierarchies, such as if A is an ancestor of B, and B is an ancestor of C, then A is an ancestor of C.
Set Theory
Set theory is the study of collections of "things" or elements, where words like 'set', 'relation', and 'operation' are central. It provides the foundation for many concepts in mathematics, including how we define and work with relations.
- A **set** is a well-defined collection of distinct objects, considered as an object in its own right. The set \( W \) here refers to the collection of words in the English dictionary.
- A **relation** in set theory is a collection of ordered pairs, typically defined over Cartesian products.
Other exercises in this chapter
Problem 24
Let \(R=\\{(1,3),(4,2),(2,4),(2,3),(3,1)\\}\) be a relation on the set \(A=\\{1,2,3,4\\} .\) The relation \(R\) is \(\quad\) [2004] (A) a function (B) reflexive
View solution Problem 25
Let \(R=\\{(3,3),(6,6),(9,9),(12,12),(6,12),(3,9)\) \((3,12),(3,6)\\}\) be a relation on the set \(A=\\{3,6,9,12\\}\) be a relation the set \(A=\\{3,6,9,12\\}\)
View solution Problem 27
The set \(S=\\{1,2,3, \ldots, 12\) ) is to be partitioned into three sets \(A, B, C\) of equal size. Thus, \(A \cup B \cup C=S\), \(A \cap B=B \cap C=A \cap C=\
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Let \(R\) be the real line. Consider the following subsets of the plane \(R \times R\). \(S=\\{(x, y): y=x+1\) and \(0
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