Problem 26
Question
It takes \(m\) hours to grade a set of papers. (a) What is the grader's rate (in job per hour)? (b) How much of the job will the grader do in \(2 \mathrm{hr} ?\)
Step-by-Step Solution
Verified Answer
(a) \(\frac{1}{m}\) job per hour. (b) \(\frac{2}{m} \) of the job.
1Step 1: Identify Given Information
It is given that it takes the grader \(m\) hours to grade a set of papers. This is the total time taken to complete the job.
2Step 2: Determine Grader's Rate
The grader's rate (in job per hour) is calculated as the reciprocal of the time taken to complete the job. Therefore, the rate is \[ \text{Rate} = \frac{1}{m} \text{ job per hour} \]
3Step 3: Calculate Job Completed in 2 Hours
To find out how much of the job the grader will complete in 2 hours, multiply the rate by the time (2 hours). \[ \text{Job completed} = \text{Rate} \times 2 = \frac{1}{m} \times 2 = \frac{2}{m} \]
Key Concepts
Understanding ReciprocalsTime Rate Work ProblemsMultiplication of Fractions
Understanding Reciprocals
A reciprocal of a number is simply flipping that number. If you have a fraction, the reciprocal is created by swapping its numerator and denominator. For example, the reciprocal of \( \frac{a}{b} \) is \( \frac{b}{a} \).
For whole numbers, you can think of them as having an implicit denominator of 1. So, the reciprocal of 5 is \( \frac{1}{5} \).
Reciprocals are especially important in rate problems like this exercise.
When we talk about a rate, what we’re essentially looking at is how much work or task is done over a certain period. Thus, for a task that takes \( m \) hours, the rate becomes \( \frac{1}{m} \) jobs per hour.
For whole numbers, you can think of them as having an implicit denominator of 1. So, the reciprocal of 5 is \( \frac{1}{5} \).
Reciprocals are especially important in rate problems like this exercise.
When we talk about a rate, what we’re essentially looking at is how much work or task is done over a certain period. Thus, for a task that takes \( m \) hours, the rate becomes \( \frac{1}{m} \) jobs per hour.
Time Rate Work Problems
Rate problems often involve finding how much of a job gets done in a certain amount of time.
These problems can be solved by identifying how quickly a task is completed (rate), and then using that rate to calculate portions of the job done over different periods.
In our exercise, we found the grader’s rate as \( \frac{1}{m} \) jobs per hour. This means that in one hour, \( \frac{1}{m} \) of the job is completed. To find out how much of the job the grader completes in 2 hours, we use this rate.
These problems can be solved by identifying how quickly a task is completed (rate), and then using that rate to calculate portions of the job done over different periods.
In our exercise, we found the grader’s rate as \( \frac{1}{m} \) jobs per hour. This means that in one hour, \( \frac{1}{m} \) of the job is completed. To find out how much of the job the grader completes in 2 hours, we use this rate.
Multiplication of Fractions
In rate problems, we often have to multiply fractions to find the solution. For our problem, once we know the rate is \( \frac{1}{m} \), we need to find how much work that rate accomplishes in 2 hours. This requires multiplying the rate by 2: \[ \text{Job completed} = \frac{1}{m} \times 2 = \frac{2}{m} \]
When multiplying fractions, multiply the numerators together and the denominators together. In this case, we multiply 1 (the numerator of \( \frac{1}{m} \)) by 2, which gives 2, and \( m \) (the denominator of \( \frac{1}{m} \)) remains the same.
So, the grader completes \( \frac{2}{m} \) of the job in 2 hours.
When multiplying fractions, multiply the numerators together and the denominators together. In this case, we multiply 1 (the numerator of \( \frac{1}{m} \)) by 2, which gives 2, and \( m \) (the denominator of \( \frac{1}{m} \)) remains the same.
So, the grader completes \( \frac{2}{m} \) of the job in 2 hours.
Other exercises in this chapter
Problem 26
Solve each inequality. $$ (7-6 x)^{2} \geq-1 $$
View solution Problem 26
Solve each equation for the specified variable. (Leave \(\pm\) in the answers.) \(S=v t+\frac{1}{2} g t^{2}\) for \(t\)
View solution Problem 27
Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ (r-3)(r+5)=2 $$
View solution Problem 27
Graph each parabola. Give the vertex, axis of symmetry, domain, and range. $$ f(x)=x^{2}+4 x+3 $$
View solution