Problem 26
Question
In Problems , compute a \(\mathbf{x}\) for the given vector \(\mathbf{x}\) and scalar a. Represent \(\mathbf{x}\) and a \(\mathbf{x}\) in the plane, and explain graphically how you obtain \(a \mathbf{x}\). $$ \mathbf{x}=\left[\begin{array}{r} 3 \\ -9 \end{array}\right] \text { and } a=-1 / 3 $$
Step-by-Step Solution
Verified Answer
The vector \( a\mathbf{x} = \begin{bmatrix} -1 \\ 3 \end{bmatrix} \) is one-third the length of \( \mathbf{x} \) and points in the opposite direction.
1Step 1: Compute the Scalar Multiplication
Given the vector \( \mathbf{x} = \begin{bmatrix} 3 \ -9 \end{bmatrix} \) and the scalar \( a = -\frac{1}{3} \), compute \( a\mathbf{x} \). Multiply each component of \( \mathbf{x} \) by \( a \): \[ a\mathbf{x} = -\frac{1}{3} \begin{bmatrix} 3 \ -9 \end{bmatrix} = \begin{bmatrix} -\frac{1}{3} \times 3 \ -\frac{1}{3} \times (-9) \end{bmatrix} = \begin{bmatrix} -1 \ 3 \end{bmatrix} \] Thus, \( a\mathbf{x} = \begin{bmatrix} -1 \ 3 \end{bmatrix} \).
2Step 2: Represent Vectors on the Plane
Represent the original vector \( \mathbf{x} = \begin{bmatrix} 3 \ -9 \end{bmatrix} \) and the new vector \( a\mathbf{x} = \begin{bmatrix} -1 \ 3 \end{bmatrix} \) on the Cartesian plane. The vector \( \mathbf{x} \) points from the origin to the point (3, -9), and \( a\mathbf{x} \) points to (-1, 3).
3Step 3: Graphical Explanation of Scalar Multiplication
To graphically understand \( a\mathbf{x} \), start at the origin (0,0) and draw the vector \( \mathbf{x} \) towards (3, -9). The effect of multiplying by \( a = -\frac{1}{3} \) contracts \( \mathbf{x} \) by one-third of its length and reverses its direction, resulting in the vector pointing towards (-1, 3). This demonstrates the geometric interpretation of scalar multiplication: it alters the vector's scale and direction.
Key Concepts
Scalar MultiplicationVector RepresentationCartesian Plane
Scalar Multiplication
Scalar multiplication is a fundamental concept in linear algebra. It involves taking a vector and multiplying it by a scalar, which is simply a real number. This operation modifies the vector by scaling its magnitude and possibly changing its direction. For instance, when you have a vector like \( \mathbf{x} = \begin{bmatrix} 3 \ -9 \end{bmatrix} \) and a scalar \( a = -\frac{1}{3} \), you perform scalar multiplication by multiplying each component of the vector by the scalar.
- This results in a new vector \( a\mathbf{x} = \begin{bmatrix} -1 \ 3 \end{bmatrix} \).
- The first component \( -1 \) is the product of \( 3 \) and \(- \frac{1}{3}\), whereas the second component \( 3 \) results from multiplying \(-9\) by \(- \frac{1}{3}\).
Vector Representation
Vector representation on a Cartesian plane is a powerful way to visualize vectors. Each vector in a 2D space is represented as an arrow that starts at the origin and ends at the coordinates specified by the vector's components.
- For instance, the vector \( \mathbf{x} = \begin{bmatrix} 3 \ -9 \end{bmatrix} \) points from the origin to the point (3, -9).
- After scalar multiplication, the vector \( a\mathbf{x} = \begin{bmatrix} -1 \ 3 \end{bmatrix} \) points to (-1, 3).
Cartesian Plane
The Cartesian plane is an essential tool in mathematics for plotting data and understanding vector behavior. It consists of two perpendicular axes, the x-axis and the y-axis, which form a flat plane. Each point on this plane is represented by an ordered pair of numbers (x, y).
- In vector representation, the plane allows you to plot the vector and its transformations visually.
- The vector \( \mathbf{x} \) pointing to (3, -9) illustrates its original placement on the plane.
- After applying the scalar \( a = -\frac{1}{3} \), this vector transforms to \( a\mathbf{x} = \begin{bmatrix} -1 \ 3 \end{bmatrix} \), thus pointing to (-1, 3).
Other exercises in this chapter
Problem 26
Find the augmented matrix and use it to solve the system of linear equations. $$ \begin{array}{l} 3 x-2 y+z=4 \\ 4 x+y-2 z=-12 \\ 2 x-3 y+z=7 \end{array} $$
View solution Problem 26
Find the angle between \(\mathbf{x}=[1,-3,2]^{\prime}\) and \(\mathbf{y}=[3,1,-4]^{\prime}\).
View solution Problem 27
Suppose that \(A\) is a \(3 \times 4\) matrix and \(B\) is a \(4 \times 2\) matrix. What is the size of the product \(A B ?\)
View solution Problem 27
Find the augmented matrix and use it to solve the system of linear equations. $$ \begin{array}{l} y+x=3 \\ z-y=-1 \\ x+z=2 \end{array} $$
View solution