Problem 26
Question
In Exercises \(17-26,\) let $$ A=\left[\begin{array}{rr} -3 & -7 \\ 2 & -9 \\ 5 & 0 \end{array}\right] \text { and } B=\left[\begin{array}{rr} -5 & -1 \\ 0 & 0 \\ 3 & -4 \end{array}\right] $$ Solve each matrix equation for \(X\). $$ 4 B+3 A=-2 X $$
Step-by-Step Solution
Verified Answer
The matrix X is found by doing scalar multiplication of 4 with matrix B, 3 with matrix A, adding these two resulting matrices together, and then dividing this sum by \(-2\).
1Step 1: Compute the Result of Scalar Multiplication and Addition
First, we need to calculate 4B and 3A and then add these two matrices together. Scalar multiplication is performed by multiplying each element in the matrix by the scalar value. Matrix addition is performed by adding each corresponding item in the two matrices.
2Step 2: Evaluate -2X
Next, we need to isolate \(X\) by dividing both sides of the equation by \(-2\). Just like in scalar multiplication, division involves dividing each element in the matrix by the scalar value.
3Step 3: Resulting Matrix X
The resulting matrix after executing the operations is the matrix \(X\). This is the solution to the matrix equation.
Key Concepts
Scalar MultiplicationMatrix AdditionMatrix Division
Scalar Multiplication
Scalar multiplication is a basic matrix operation that involves multiplying each element within a matrix by a scalar value. In our original exercise, this process was performed twice: once as 4 times matrix B, and then as 3 times matrix A. Here’s how it's done in a simple, straightforward way.
To perform scalar multiplication:
- Select a scalar value. In this case, they are '4' and '3'.
- Multiply each element of the chosen matrix by the scalar value. For example, multiplying each component of matrix A by 3 means multiplying -3, -7, 2, -9, 5, and 0 by 3 accordingly.
Matrix Addition
Matrix addition is another fundamental operation, crucial in solving matrix equations. It involves adding corresponding elements of matrices to attain a resultant matrix. In the exercise, after computing 4B and 3A using scalar multiplication, these results are added together.
Key steps in matrix addition include:
- Ensure both matrices are of the same size, which means they must have the same number of rows and columns.
- Add each pair of corresponding elements from the matrices.
Matrix Division
In the context of matrices, division is less intuitive than scalar multiplication or matrix addition. You can't directly divide matrices like you divide numbers, but you can divide a matrix by a scalar by multiplying by the reciprocal of the scalar.
In our problem, after obtaining the summed matrix from adding 4B and 3A, the process to solve for X was to divide the whole matrix by -2:
Here's how to think about matrix division:
- Identify the matrix you want to "divide", in our case, the matrix sum.
- Consider dividing all elements by the scalar. This effectively means multiplying them by the reciprocal of the scalar.
Other exercises in this chapter
Problem 25
Use Cramer's rule to solve each system or to determine that the system is inconsistent or contains dependent equations. $$ \begin{aligned}&4 y=16-3 x\\\&6 x=32-
View solution Problem 25
find \(A^{-1}\) by forming \([A | I]\) and then using row operations to obtain [ \(I | B],\) where \(A^{-1}=[B]\) Check that \(A A^{-1}=I\) and \(A^{-1} A=I\) $
View solution Problem 26
Use Cramer's rule to solve each system or to determine that the system is inconsistent or contains dependent equations. $$ \begin{aligned}&2 x=7+3 y\\\&4 x-6 y=
View solution Problem 26
find \(A^{-1}\) by forming \([A | I]\) and then using row operations to obtain [ \(I | B],\) where \(A^{-1}=[B]\) Check that \(A A^{-1}=I\) and \(A^{-1} A=I\) $
View solution