Problem 26
Question
In \(3-41\) , express each product in simplest form. Variables in the radicand with an even index are non-negative. $$ \sqrt{5}(1-\sqrt{10}) $$
Step-by-Step Solution
Verified Answer
\( \sqrt{5} - 5\sqrt{2} \)
1Step 1: Distribute the Square Root
Use the distributive property to distribute the square root of 5 across the expression in the parenthesis. This means multiplying \( \sqrt{5} \) with both 1 and \( -\sqrt{10} \).
2Step 2: Multiply Square Roots
Calculate \( \sqrt{5} \times 1 = \sqrt{5} \). Next, calculate \( \sqrt{5} \times -\sqrt{10} = -\sqrt{50} \).
3Step 3: Simplify the Radicals
Simplify \( \sqrt{50} \). Note that \( 50 = 25 \times 2 \), so \( \sqrt{50} = \sqrt{25 \times 2} \). This simplifies to \( \sqrt{25} \times \sqrt{2} \), which is \( 5\sqrt{2} \).
4Step 4: Write the Simplified Expression
Combine the simplified expressions from the previous steps: \( \sqrt{5} - 5\sqrt{2} \).
Key Concepts
Understanding the Distributive PropertySquare Roots Multiplication ExplainedRadical Simplification Made Easy
Understanding the Distributive Property
The distributive property is a crucial concept in algebra that allows us to handle expressions by spreading or distributing components across parenthetical terms. This technique is particularly useful when coping with radicals or terms inside parentheses. In our given exercise, we need to distribute the square root of 5, denoted as \( \sqrt{5} \), over the expression \( 1 - \sqrt{10} \).
Utilizing the distributive property, you multiply \( \sqrt{5} \) first with the number 1 and then with \( -\sqrt{10} \). Here's how it breaks down:
Utilizing the distributive property, you multiply \( \sqrt{5} \) first with the number 1 and then with \( -\sqrt{10} \). Here's how it breaks down:
- First, distribute \( \sqrt{5} \times 1 \), which simply gives \( \sqrt{5} \).
- Next, distribute \( \sqrt{5} \times -\sqrt{10} \), processing both the numerical values and the radicals involved.
Square Roots Multiplication Explained
Multiplying square roots might seem daunting at first, but it's quite straightforward once you understand the basic rules. The square root multiplication rules allow us to deal directly with numbers under the radical sign. These rules state that the product of two square roots is the square root of their product.
In our example, multiplying \( \sqrt{5} \) and \( \sqrt{10} \) follows these steps:
In our example, multiplying \( \sqrt{5} \) and \( \sqrt{10} \) follows these steps:
- Multiply the numbers under the square roots: \( 5 \times 10 = 50 \).
- The result is \( \sqrt{50} \).
- Always remember to carry forward any minus signs, resulting in \( -\sqrt{50} \).
Radical Simplification Made Easy
Once we've multiplied the square roots, as seen in the previous sections, the next step involves simplifying these radicals. Simplifying radicals is essential for expressing the result in its simplest form. A radical expression can often be streamlined by factoring out perfect squares.
To simplify \( \sqrt{50} \), we recognize that 50 can be further reduced:
To simplify \( \sqrt{50} \), we recognize that 50 can be further reduced:
- Break down 50 into its factors: \( 25 \times 2 \).
- Since 25 is a perfect square, we take \( \sqrt{25} = 5 \).
- This leaves us with \( 5\sqrt{2} \).
Other exercises in this chapter
Problem 25
In \(3-38\) , write each radical in simplest radical form. Variables in the radicand of an even index are non-negative. Variables occurring in the denominator o
View solution Problem 25
In \(15-26,\) find and graph the solution set of each inequality. $$ \left|x+\frac{1}{2}\right|+1 > \frac{1}{2} $$
View solution Problem 26
In \(3-38,\) solve each equation for the variable, check, and write the solution set. $$ x+\sqrt{x+1}=5 $$
View solution Problem 26
In \(11-38,\) evaluate each expression in the set of real numbers. $$ -\sqrt{\frac{49}{36}} $$
View solution