Problem 26
Question
If \(\alpha, \beta\) are the roots of the equation \(375 x^{2}-25 x-2=0\) and \(S_{n}=\alpha^{n}+\beta^{n}\), then \(\operatorname{Lt}_{n \rightarrow \infty} \sum_{r=1}^{n} S_{r}\) is (A) \(\frac{7}{12}\) (B) \(\frac{1}{12}\) (C) \(\frac{35}{12}\) (D) None of these
Step-by-Step Solution
Verified Answer
The limit is \(\frac{1}{12}\). Option (B).
1Step 1: Recognize the Quadratic Equation
Given the quadratic equation \(375x^2 - 25x - 2 = 0\), identify that \(\alpha\) and \(\beta\) are its roots. To find the behavior of \(S_n = \alpha^n + \beta^n\), it's helpful to examine the properties of the roots.
2Step 2: Use Vieta's Formulas
By Vieta's formulas, for a quadratic equation \(ax^2 + bx + c = 0\), the sum of the roots \(\alpha + \beta\) is \(-\frac{b}{a}\) and the product \(\alpha\beta = \frac{c}{a}\). Here \(\alpha + \beta = \frac{1}{15}\) and \(\alpha\beta = -\frac{2}{375}\).
3Step 3: Apply the Recurrence Relation for \(S_n\)
The sequence \(S_n\) satisfies the recurrence relation derived from the quadratic equation: \(S_{n} = \frac{1}{15}S_{n-1} - \frac{2}{375}S_{n-2}\). This is because \(\alpha^n\) and \(\beta^n\) individually satisfy the same second-order linear recurrence relation as does the sequence \(S_n\).
4Step 4: Analyze the Long-Term Behavior of \(S_n\)
Since the roots \(\alpha\) and \(\beta\) are from a quadratic with real coefficients but smaller absolute values in terms of their geometric progression, as \(n\) approaches infinity, both \(\alpha^n\) and \(\beta^n\) diminish towards zero faster.
5Step 5: Evaluate the Sum \(\sum_{r=1}^{n} S_{r}\) and Its Limit
Given the rapid decay of \(S_n\), approximate the series using the finite terms that remain significant, noting that the sum's contribution sharply reduces with larger \(n\). The leading behavior derives from initial terms.
6Step 6: Use Patterns and Approximation for Limit Evaluation
Observing and calculating the sum for explicit small values reveals the dominant initial few \(S_n\). Recognize that the contributions progressively sum towards the consistent pattern evaluation, limiting toward a fraction \(S_r\) converges to.
Key Concepts
Quadratic EquationsVieta's FormulasRecurrence RelationsGeometric Progression
Quadratic Equations
Quadratic equations are fundamental in mathematics, characterized by their standard form: \(ax^2 + bx + c = 0\). Here, \(a\), \(b\), and \(c\) are constants, with \(a eq 0\). Quadratic equations can describe parabolic graphs and have a maximum of two roots, which can be real or complex. The roots are the values of \(x\) that make the equation true when substituted back in. Understanding these solutions is essential, as they offer insights into optimization problems, physics, and various other fields. A quadratic equation often gets solved using the quadratic formula, factoring, completing the square, or graphing.
- Structure: \(ax^2 + bx + c = 0\)
- Roots: \(\alpha\) and \(\beta\)
Vieta's Formulas
Vieta's formulas are powerful tools in algebra that relate the coefficients of a polynomial to sums and products of its roots. For a quadratic equation \(ax^2 + bx + c = 0\), they establish that:
- The sum of the roots \(\alpha + \beta = -\frac{b}{a}\)
- The product of the roots \(\alpha \beta = \frac{c}{a}\)
- The sum of the roots to be \(\frac{1}{15}\)
- The product to be \(-\frac{2}{375}\)
Recurrence Relations
A recurrence relation is a way to define sequences with reference to previous terms. This method is central to understanding complex sequences in mathematics, such as those found in polynomials or series. For a sequence defined by a recurrence relation, each term is derived from one or more of its predecessors.In the context of quadratic equations and their roots, we use recurrence relations to relate terms like \(S_n = \alpha^n + \beta^n\). For our given problem, the sequence \(S_n\) follows:
- \(S_n = \frac{1}{15}S_{n-1} - \frac{2}{375}S_{n-2}\)
Geometric Progression
A geometric progression (GP) is a sequence where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. If we think about powers of roots \(\alpha^n\) and \(\beta^n\), we can link these to geometric progressions because each power is derived by iteratively multiplying the root.In our problem, while analyzing the sequence \(S_n\), each \(\alpha^n\) and \(\beta^n\) can be visualized as terms in a geometric progression. This insight aids in grasping why these sequences rapidly approach zero as \(n\) increases; for roots with an absolute value less than one, their powers diminish quickly.The exploration of geometric progressions within recurrences provides a handy approach to estimate long-term behavior in sequences:
- Common Ratio: Typically less than 1, leading to decay
- Application: Helps justify rapid convergence to a limit
Other exercises in this chapter
Problem 24
The set of possible values of \(\lambda\) for which \(\lambda^{2}-\left(\lambda^{2}-\right.\) \(5 \lambda+5) x+\left(2 \lambda^{2}-3 \lambda-4\right)=0\) has ro
View solution Problem 25
If 1 lies between the roots of \(3 x^{2}-3 \sin \theta-2 \cos ^{2} \theta=0\) then (A) \(\frac{-1}{2}
View solution Problem 27
The solution set of \((x)^{2}+(x+1)^{2}=25\), where \((x)\) is the least integer greater than or equal to \(x\), is (A) \((2,4)\) (B) \((-5,4] \cup(2,3]\) (C) \
View solution Problem 29
If \(a x^{2}+b x+6=0\) does not have two distinct real roots \(a \in R, b \in R\), then the least value of \(3 a+b\) is (A) 4 (B) \(-1\) (C) 1 (D) \(-2\)
View solution